coercible | Powerful , flexible and configurable coercion library

 by   solnic Ruby Version: Current License: MIT

kandi X-RAY | coercible Summary

kandi X-RAY | coercible Summary

coercible is a Ruby library. coercible has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Powerful, flexible and configurable coercion library. And nothing more.
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            kandi-support Support

              coercible has a low active ecosystem.
              It has 138 star(s) with 15 fork(s). There are 9 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 9 open issues and 4 have been closed. On average issues are closed in 487 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of coercible is current.

            kandi-Quality Quality

              coercible has 0 bugs and 0 code smells.

            kandi-Security Security

              coercible has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              coercible code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              coercible is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              coercible releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.
              coercible saves you 759 person hours of effort in developing the same functionality from scratch.
              It has 1749 lines of code, 86 functions and 105 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed coercible and discovered the below as its top functions. This is intended to give you an instant insight into coercible implemented functionality, and help decide if they suit your requirements.
            • Determine the class of the given type
            • Defines an option
            • Initialize a new instance
            • Determine the primitive
            • Defines all options for the given options .
            • Returns a hash with the default options .
            • Determine the given string
            • Add valid options .
            • Extracts the options from the given class .
            • Sets the options for the given hash .
            Get all kandi verified functions for this library.

            coercible Key Features

            No Key Features are available at this moment for coercible.

            coercible Examples and Code Snippets

            No Code Snippets are available at this moment for coercible.

            Community Discussions

            QUESTION

            Error: `data` must be a data frame, or other object coercible by `fortify()`,...Did you accidentally pass `aes()` to the `data` argument?
            Asked 2021-Jun-04 at 17:43

            I have this data

            ...

            ANSWER

            Answered 2021-Jun-04 at 17:43

            We need to specify the column name as unquoted

            Source https://stackoverflow.com/questions/67841765

            QUESTION

            `data` must be a data frame, or other object coercible by `fortify()`, not an S3 object with class ranger
            Asked 2021-May-20 at 11:37

            I am working with R. Using a tutorial, I was able to create a statistical model and produce visual plots for some of the outputs:

            ...

            ANSWER

            Answered 2021-May-20 at 01:23

            As per the ggplot2 documentation, you need to provide a data.frame() or object that can be converted (coerced) to a data.frame(). In this case, if you want to reproduce the plot above in ggplot2, you will need to manually set up the data frame yourself.

            Below is an example of how you could set up the data to display the plot in ggplot2.

            Data Frame

            First we create a data.frame() with the variables that we want to plot. The easiest way to do this is to just group them all in as separate columns. Note that I have used the as.numeric() function to first coerce the predicted values to a vector, because they were previously a data.table row, and if you don't convert them they are maintained as rows.

            Source https://stackoverflow.com/questions/67559175

            QUESTION

            giving a type signature to `_` in haskell
            Asked 2021-May-17 at 15:54

            I want to associate _ with coerce yet I can't give a type signature to it.

            Is there any trickery to get around that ?

            ...

            ANSWER

            Answered 2021-May-17 at 15:54

            _ is a reserved name which can not be redefined. It can be used in patterns as a wildcard, e.g.

            Source https://stackoverflow.com/questions/67572802

            QUESTION

            How to use string manipulation functions inside .names argument in dplyr::across
            Asked 2021-May-15 at 15:46

            Though I tried to search whether it is duplicate, but I cannot find similar question. (though a similar one is there, but that is somewhat different from my requirement)

            My question is that whether we can use string manipulation function such substr or stringr::str_remove inside .names argument of dplyr::across. As a reproducible example consider this

            ...

            ANSWER

            Answered 2021-May-15 at 15:46

            This works, but with probably a few caveats. You can use functions inside a glue specification, so you could clean up the strings that way. However, when I tried escaping the ".", I got an error, which I assume has something to do with how across parses the string. If you need something more dynamic, you might want to dig into the source code at that point.

            In order to use the {.fn} helper, at least in conjunction with creating the glue string on the fly like this, the function needs a name; otherwise you get a number for the function's index in the .fns argument. I tested this out with a second function and using lst for automatic naming.

            Source https://stackoverflow.com/questions/67548197

            QUESTION

            avoid `unsafeCoerce` with some `Coercible` use case
            Asked 2021-May-06 at 17:52

            In the current implementation of Coercible can we quantify over "representational preserving type constructors", to extract a safer proof in the code below

            ...

            ANSWER

            Answered 2021-May-06 at 17:16

            We can not allow that without making the type system unsafe.

            Assume we have a safe way to obtain

            Source https://stackoverflow.com/questions/67422162

            QUESTION

            Unable to Plot Intersections using st_intersects() in r
            Asked 2021-May-04 at 19:52

            I digitized some roads as multilines, hospitals as multipoints, boundary as polygon, then created how many roads intersect using the Simple Features (SF) library by getting latitudes and longitudes from google maps and plotted it using ggplot2 it worked well.

            I then wanted to check and plot how many roads intersects with a hospital and created a 200mtr buffer around it and tried using st_intersects() function for the same, using this only gave 1:1 as answer and a message saying

            Sparse geometry binary predicate list of length 1, where the predicate was `intersects' 1: 1

            And when I tried plotting it, using ggplot it gives this error message

            Error: data must be a data frame, or other object coercible by fortify(), not an S3 object with class sgbp/list Run rlang::last_error() to see where the error occurred.

            I am pasting my code below,

            ...

            ANSWER

            Answered 2021-May-03 at 19:56

            In your code you are using st_intersects to create the road features. But this function returns a booolean, not a spatial feature. Try st_intersection() instead.

            Source https://stackoverflow.com/questions/67350113

            QUESTION

            How do I create this histogram
            Asked 2021-Apr-14 at 03:22

            I am trying to create a histogram for the wage variable

            My code is

            ...

            ANSWER

            Answered 2021-Apr-13 at 21:02

            Try this. Last line: I think it was typo: changed logW with W.

            Source https://stackoverflow.com/questions/67082276

            QUESTION

            How to apply ggplot2 to each row in a data frame
            Asked 2021-Apr-09 at 17:10

            I want to code a ggplot2 visualization as a function, and then apply the function on each row of a dataframe (I want to use apply to avoid a for loop, as suggested here.)

            The data:

            ...

            ANSWER

            Answered 2021-Apr-09 at 17:10

            As suggested by Gregor Thomas in the comment:

            Source https://stackoverflow.com/questions/67024322

            QUESTION

            Graphs of the mixed effects model residuals using the ggplot2 function
            Asked 2021-Mar-30 at 14:06

            I am trying to graph the residual effects of the mixed effects model using the ggplot2 function. However, after performing a search I found some functions available but what seems to me is that for the function nlme they are not working.

            The graphs that I intend to make are those of the example below:

            The data is here.

            Data: https://drive.google.com/file/d/19mykz4B7jkTilbtwPQb3NUI09YZwohhs/view?usp=sharing

            The computational routines that I tried initially are below, see the errors that are appearing when executing the function in ggplot2.

            ...

            ANSWER

            Answered 2021-Feb-24 at 13:02

            QUESTION

            Choosing ordering for labels in geometric bar plot
            Asked 2021-Mar-20 at 13:52

            I am trying to visualize qualitative grade based data, and I would like to order the grades from worst to best. The current ordering seems to be lexicographic one. How can I change this? Unfortunately I do not know how to share a working example: the column G3.x is full of letter based qualitative grades. When I tried the code with an example test_data <- c("Excellent", "Very Good", "Good", "Sufficient", "Weak", "Poor") I get errors: Error: data must be a data frame, or other object coercible by fortify(), not a character vector

            ...

            ANSWER

            Answered 2021-Mar-20 at 13:52

            The ordering of any discrete item is done in the following way:

            • if your column is a factor, ggplot2 orders by the levels of the factor
            • if your column is not a factor, ggplot2 orders alphanumerically

            In this case, the solution is to set the levels of math_and_portuguese$G3.x discretely by converting to a factor and specifying the levels you want:

            Source https://stackoverflow.com/questions/66722291

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install coercible

            Add this line to your application's Gemfile:.

            Support

            Fork itCreate your feature branch (git checkout -b my-new-feature)Commit your changes (git commit -am 'Add some feature')Push to the branch (git push origin my-new-feature)Create new Pull Request
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