ghi | GitHub Issues on the command line | Command Line Interface library

by stephencelis Ruby Version: 1.2.0 License: Non-SPDX

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | ghi Summary

ghi is a Ruby library typically used in Utilities, Command Line Interface applications. ghi has no vulnerabilities and it has medium support. However ghi has 1 bugs and it has a Non-SPDX License. You can download it from GitHub.

GitHub Issues on the command line. Use your $EDITOR, not your browser. ghi was originally created by Stephen Celis, and is now maintained by Alex Chesters.

Support

Quality

Security

License

Reuse

Support

ghi has a medium active ecosystem.

It has 2159 star(s) with 147 fork(s). There are 35 watchers for this library.

It had no major release in the last 12 months.

There are 74 open issues and 220 have been closed. On average issues are closed in 107 days. There are 9 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of ghi is 1.2.0

Quality

ghi has 1 bugs (0 blocker, 0 critical, 1 major, 0 minor) and 28 code smells.

Security

ghi has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ghi code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ghi has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

ghi releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

ghi saves you 1250 person hours of effort in developing the same functionality from scratch.

It has 2812 lines of code, 177 functions and 25 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed ghi and discovered the below as its top functions. This is intended to give you an instant insight into ghi implemented functionality, and help decide if they suit your requirements.

Perform an HTTP request
Formats a markdown document .
Format issues .
Sets the paginate .
Extracts issues from issues
Creates a new editor instance .
Render a random data from a string .
Format the date
Make an HTTP request
Writes the string to the username

Get all kandi verified functions for this library.

ghi Key Features

No Key Features are available at this moment for ghi.

ghi Examples and Code Snippets

Join strings together .

python

Lines of Code : 30

License : Non-SPDX (Apache License 2.0)

Copy

def string_join(inputs, separator="", name=None):
  """Perform element-wise concatenation of a list of string tensors.

  Given a list of string tensors of same shape, performs element-wise
  concatenation of the strings of the same index in all tens

Community Discussions

Trending Discussions on ghi

'DataFrame' object has no attribute 'data not available' while returning the value from function

Return column A for which count(column A) = sum(column B)

Conditional jump or move depends on uninitialised value(s) at strcpy

How to set an autoincrement composite primary key in oracle19c?

How to select only one row if a value of a column occurse multiple times in the result?

sieve data accordingly, when either of the inputs changed

Creating a Pandas df from two lists in python

How to use ranges with List in C#?

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element [id=""]

QUESTION

BigQuery correlated subqueries - transform array to array

Asked 2021-Jun-14 at 18:05

I'm trying to join array elements in BigQuery but I am getting the following error message:

Correlated subqueries that reference other tables are not supported unless they can be de-correlated, such as by transforming them into an efficient JOIN.

In my first table I have something like:

field1 | field2 | some_list

Elements in some_list have ids and other data and I'd like to enrich each element from some_list with some fields from a different table (they may exist or not).
I've tried to unnest some_list and left join with a different table on id but it seems it's not allowed.

Any ideas how I can do it? Thanks!

First table:

...

ANSWER

Answered 2021-Jun-14 at 12:24

This should work just fine and it seem to do what you are describing:

Source https://stackoverflow.com/questions/67970117

QUESTION

'DataFrame' object has no attribute 'data not available' while returning the value from function

Asked 2021-Jun-13 at 12:20

I have created a function to create new column. While returning the value it is giving error

'DataFrame' object has no attribute 'data not available'

sample df:

...

ANSWER

Answered 2021-Jun-13 at 12:20

try:

Source https://stackoverflow.com/questions/67958007

QUESTION

Return column A for which count(column A) = sum(column B)

Asked 2021-Jun-11 at 21:40

A SQL Query to Return column A for which count(column A) = sum(column B) group by column A

Ex:

Column A Column B ABC 1 ABC 1 ABC -1 DEF 1 DEF 1 GHI 1 GHI -1 GHI -1 GHI -1

Output : DEF (Because count of DEF is equal to sum of its corresponding values in Column B)

...

ANSWER

Answered 2021-Jun-11 at 21:40

Using the Having count(*)=sum([Column B])

Example

Source https://stackoverflow.com/questions/67943538

QUESTION

Conditional jump or move depends on uninitialised value(s) at strcpy

Asked 2021-Jun-11 at 16:02

Valgrind detects a problem with strcpy in the following code:

...

ANSWER

Answered 2021-Jun-11 at 15:29

It's strcpy(destination, source). Also strcpy() 0-terminates the copy.

So replace

Source https://stackoverflow.com/questions/67939632

QUESTION

How to set an autoincrement composite primary key in oracle19c?

Asked 2021-Jun-10 at 05:21

I want to create a table, with composite primary key and autoincrement, in Oracle 19c, like this:

...

ANSWER

Answered 2021-Jun-10 at 05:16

Create trigger on this table to achieve this result. Assume table name is test123

Source https://stackoverflow.com/questions/67914853

QUESTION

How to select only one row if a value of a column occurse multiple times in the result?

Asked 2021-Jun-09 at 21:00

I have a table like this on:

AttributeA AttributeB AttributeC AttributeD A B EQUALITY D 123 B EQUALITY D 456 B C D ... ... ... ...

My goal is, to create a Select-Query where the result only contains one row with an equal AttributeC - no matter of the count of rows with the same value in this column.

The other Attributes do not matter. So I want this:

AttributeA AttributeB AttributeC AttributeD A or 123 B EQUALITY D ABC DEF GHI JKL ... ... ... ...

I have already tried some WHERE-Clauses, but I found no way to specify that I want to have the row atleast once in my result.

Something like this was my plan with an unique ID.

...

ANSWER

Answered 2021-Jun-09 at 21:00

You can use row_number():

Source https://stackoverflow.com/questions/67911621

QUESTION

sieve data accordingly, when either of the inputs changed

Asked 2021-Jun-09 at 16:28

Working Stackblitz:

I implemented 2 calendars in html, for filtering the data between 2 dates. When i filter data for the first time, i will select both calendar dates and the data is filtering. Now we have both the inputs for calendar given right. Now my issue lies here. When i change the first calendar date. the second calendar remains the same with previously assigned date as we filtered previously. and there is no change in the filtering of data until we give inputs to both calendars again. I want the second calendar value to be cleared on changing the first calendar. And also clear the first calendar input when the second calendar is changed. Please help me achieve this.

can we trigger the output based on either of the input values ? as of now it's not showing. example: i have 2 records in grid: with dates : 07/12/2020 and 15/12/2020 Initially if i filter from dec 1st 2020 to dec 31st 2020. It's showing both records. Now, again if i set 15/12/2020 in first calendar without changing second. There is no change in the table. i should enter second also. Can we fix it ??

...

ANSWER

Answered 2021-Jan-04 at 12:04

You are not updating the list on the change of the first Date input. Update the list onChange of the first Date if the second Date already been selected. Change your code as below.

Instead of

Source https://stackoverflow.com/questions/65562118

QUESTION

Creating a Pandas df from two lists in python

Asked 2021-Jun-09 at 13:47

I have two python lists in following form:

...

ANSWER

Answered 2021-Jun-08 at 20:08

Try:

Source https://stackoverflow.com/questions/67893732

QUESTION

How to use ranges with List in C#?

Asked 2021-Jun-08 at 23:58

With C# 8 we got ranges to get "sub lists".

While this works:

...

ANSWER

Answered 2021-Jun-06 at 07:28

Unfortunately you can't. From the language specification:

For example, the following .NET types support both indices and ranges: String, Span, and ReadOnlySpan. The List supports indices but doesn't support ranges.

Type Support for ranges and indices.

So the only way would be something like this, which is a bit clunky:

Source https://stackoverflow.com/questions/67856174

QUESTION

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element [id=""]

Asked 2021-Jun-08 at 04:21

I'm trying to get the input tag and use click() by using selenium.

Here is my code:

...

ANSWER

Answered 2021-Jun-08 at 04:21

The element that you are looking for, is in iframe. So we would have to change the driver focus in order to interact with the desire element or elements :

Iframe xpath :

Source https://stackoverflow.com/questions/67881107

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ghi

Via brew (latest stable release):.

Support

If you're looking for a place to start, there are issues we need help with!. Once you have an idea of what you want to do, there is a section in the wiki to provide more detailed information but the basic steps are as follows.

Find more information at: