bktree | Burkhard Keller Tree implementation in Ruby | Dataset library
kandi X-RAY | bktree Summary
kandi X-RAY | bktree Summary
Burkhard Keller Tree implementation in Ruby
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Top functions reviewed by kandi - BETA
- Creates a new term
- Query the term against the node .
- Creates a graph of graph
- Dump the term dump .
- Calls the distance between two hashes
- Initialize a Distance instance
- Exports a stream to the stream
- Build a graph graph
bktree Key Features
bktree Examples and Code Snippets
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Trending Discussions on bktree
QUESTION
I'm building a tool that helps find duplicate images. To utilize bktrees, I need to use a bit hash, however, it would be nice to compress that larger bit hash into a smaller hex hash for storage.
The bit hash looks like this:
dhash_bits = 19965419413067491224447942902196404479
The hex hash of the bit hash look like this:
dhash_hex = 0f05332d4d0b471500007722dc7300ff
I've tried to use bin(int(dhash_hex,16))
to convert the hex hash back into the bits, but I know this isn't the right way to do it.
What is the correct way to convert the hex hash back into the bit hash?
Here is the function that converts the bits into hex:
...ANSWER
Answered 2018-Jul-07 at 22:45Your dhash_bits
is just a single integer; the corresponding dhash_hex
value is also achievable with
QUESTION
Hello I'm trying to read a file (words.txt), which contains a large list of english words into a Hashmap. I'm accessing the file with Paths. My function passes in a Path that is being opened and attempts to input the contents into a HashMap. I can print all the values of the Path word by word, but I'm having trouble storing the values into a HashMap. I'm attempting to make a SpellChecker thats better than my O(n) ArrayList implementation. Before I attempt to solve it with a Trie or BKTree, I would like to solve it with a HashMap.
Summary: How can I get the word.txt file opened with Path into a HashMap.
My Code ...ANSWER
Answered 2017-Feb-15 at 22:05System.out::println
is a method reference and theWords.put(count++, stream)
is not. Additionally as already pointed out by Boris the stream would be added to the map, not the individual words.
A correct lambda expression could look like word -> theWords.put(count++, word)
but this also won't compile due to the count
variable not being effectively final, it cannot be changed inside a lambda expression.
If the intention is to be able to just quickly look up if a particular word is contained in the dictionary file a Set
would also be sufficient and the code could look like:
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