lucy | Lucy on Rails - Lucy in the sky with rubies
kandi X-RAY | lucy Summary
kandi X-RAY | lucy Summary
Lucy in the sky with rubies.
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Top functions reviewed by kandi - BETA
- This method generates all the common JS frameworks .
- Create a new instance .
- Writes a key to the object .
- Write data to raw data
- Get the JavaScript code as a string
lucy Key Features
lucy Examples and Code Snippets
Community Discussions
Trending Discussions on lucy
QUESTION
I have a table in database named Message and this is how the table looks like:
I need to find the last message of conversation gomez had with every user from the table. So, I want to make a column that combines sender and receiver username and group by with that column. However, how do i validate
Lucy+Gomez == Gomez+Lucy
My code so far:
...ANSWER
Answered 2021-Jun-13 at 16:00Use NOT EXISTS
instead of GROUP BY
:
QUESTION
I'm currently working on an assignment and I cannot find any clue to remove the headline from the text file and write the rest into an ArrayList. Can someone help me?
...ANSWER
Answered 2021-Jun-05 at 12:10If you want to ignore first line while reading the CSV file then you can simple skip processing of 1st line by calling in.readLine();
twice at the start as shown in below example:
QUESTION
I am a novice programmer, and I am wondering if there is a way to write a conditional statement to test whether a given dictionary contains more than x number of key-value pairs. Also, is there a way to return the number of key-value pairs a dictionary has in general?
My example dictionary I am using:
...ANSWER
Answered 2021-Apr-27 at 19:08You can use len()
which returns the number of elements in an object. This works on all iterables.
QUESTION
If i have a dataframe and i want to merge ID column based on the Name column without deleting any row. How would i do this?
Ex-
Name ID John ABC John XYZ Lucy MNOI want to convert the above dataframe into the below one
Name ID John ABC, XYZ John ABC, XYZ Lucy MNO ...ANSWER
Answered 2021-Jun-01 at 08:50Use GroupBy.transform
with join
:
QUESTION
I want to sort a list by date and then create new lists containing only items with that date. In this example there would be one list with items of the date 21.01.2021 and a list with items of date 28.01.2021 etc, so that there a three different lists at the end.
...ANSWER
Answered 2021-May-30 at 13:16Not really sure what you mean by having three separate lists but check this example where I uses a Map>
to split your dates into its own list:
QUESTION
Suppose I have the following strings,
...ANSWER
Answered 2021-May-23 at 17:08So this is my attempt.
The development process here was to code by intention. That is, I started at the top level and called a function that I had not yet written. This was the line:
QUESTION
I have written a short script to test if the first words from a text file I have saved in a different folder all start with a capital letter. however, i realized the self...append method does not work correctly. Here is the code:
...ANSWER
Answered 2021-May-17 at 19:42Based on your code I am assuming that each sentence is on a separate line.
There are a couple of things in your code that are problematic.
First, a matter of style: setting up a unit test is usually done in setUp
, not in __init__
.
Second, test_reader
is not a test, but part of the setup, or can be done in the test itself. Tests that depend on each other is bad practice, also test functions that don't test anything.
Your test does not work, because test_reader
is executed after test_capitalization
-- unittest
orders tests alphabetically by default.
So, here is an example for a working version, provided you have one sentence per line as assumed in your code:
QUESTION
I want to define an object type in TypeScript, that is composed of several properties of which I want to define the type, but without knowing them keys.
I could have used an array to filter, but I prefer to use properties to gain speed (my use case is a graph).
Ex:
...ANSWER
Answered 2021-May-13 at 17:30You're looking for Typescript's Index Signature.
QUESTION
The super attribute cannot be accessed, but can be modified?
What does super
stand for? Some people say it is prototype? I know that the function of Class is in the prototype of the object, but why can super.name ='Lucy';
modify the properties of the object instance?
ANSWER
Answered 2021-May-13 at 16:49Assigning to super.prop
is useful when prop
is defined on the parent's prototype, not when it is defined as an instance property, as is the case with name
in your code. Realise that the assignment name = 'jack'
happens on the instance that is created by new b
, not on some other object.
So when you do super.name = 'Lucy'
, you are doing nothing else than this.name = 'Lucy'
. This change is not visible when you consult super.name
after that assignment, because that will scan the parent's prototype chain, not the instance object. And there is no name
defined anywhere on that prototype chain...
The difference between how super.name
acts when used for lookup and for assignment is specific: for (non-setter) assignment, it is no different than assigning on this
, while for lookup (including setter lookup), it skips this
and starts the lookup in the parent's prototype chain.
The power of the super.prop
syntax only reveals itself when you have to deal with methods that have been created on the prototype.
To demonstrate this, let's define name
as a getter/setter function on the prototype:
QUESTION
I am trying to query a column that contains an array of json objects.
The array of object looks like this:
...ANSWER
Answered 2021-May-12 at 13:43You can use OPENJSON
to break out the array into separate rows:
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Install lucy
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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