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QUESTION
Tensoflow Embedding Layer (https://www.tensorflow.org/api_docs/python/tf/keras/layers/Embedding) is easy to use, and there are massive articles talking about "how to use" Embedding (https://machinelearningmastery.com/what-are-word-embeddings/, https://www.sciencedirect.com/topics/computer-science/embedding-method) . However, I want to know the Implemention of the very "Embedding Layer" in Tensorflow or Pytorch. Is it a word2vec? Is it a Cbow? Is it a special Dense Layer?
...ANSWER
Answered 2021-Jun-09 at 09:22Structure wise, both Dense
layer and Embedding
layer are hidden layers with neurons in it. The difference is in the way they operate on the given inputs and weight matrix.
A Dense
layer performs operations on the weight matrix given to it by multiplying inputs to it ,adding biases to it and applying activation function to it. Whereas Embedding
layer uses the weight matrix as a look-up dictionary.
The Embedding layer is best understood as a dictionary that maps integer indices (which stand for specific words) to dense vectors. It takes integers as input, it looks up these integers in an internal dictionary, and it returns the associated vectors. It’s effectively a dictionary lookup.
QUESTION
I am following the Tensorflow tutorial https://www.tensorflow.org/guide/migrate. Here is an example:
...ANSWER
Answered 2021-Jun-06 at 07:54Why do batch_normalization produce all-zero output when training = True
It's because your batch size = 1 here.
Batch normalization layer normalizes its input by using batch mean and batch standard deviation for each channel.
When the batch size is 1 and after flatten, there is only one single value in each channel, so that the batch mean(for that channel) will be the single value itself, thus outputting a zero tensor after the batch normalization layer.
but produce non-zero output when training = False?
During inference, batch normalization layer normalizes inputs by using moving average of batch mean and SD instead of current batch mean and SD.
The moving mean and SD are initialized as zero and one respectively and updated gradually. Therefore, the moving mean doesn't equal that single value in each channel at the beginning, therefore the layer will not output a zero tensor.
In conclusion: use batch size > 1 and input tensor with random values/realistic data values rather than tf.ones()
in which all elements are the same.
QUESTION
I am training a VAE model with 9100 images (each of size 256 x 64). I train the model with Nvidia RTX 3080. First, I load all the images into a numpy array of size 9100 x 256 x 64 called traindata
. Then, to form a dataset for training, I use
ANSWER
Answered 2021-Jun-04 at 14:50That's because holding all elements of your dataset in the buffer is expensive. Unless you absolutely need perfect randomness, you should use a smaller buffer_size
. All elements will eventually be taken, but in a more deterministic manner.
This is what's going to happen with a smaller buffer_size
, say 3. The buffer is the brackets, and Tensorflow samples a random value in this bracket. The one randomly picked is ^
QUESTION
I am trying to add a neuron layer to my model which has tf.keras.activations.relu() with max_value = 1 as its activation function. When I try doing it like this:
...ANSWER
Answered 2021-May-30 at 06:06You can try this
QUESTION
I just wanted to set up a learning rate schedule for my first CNN and I found there are various ways of doing so:
- One can include the schedule in callbacks using
tf.keras.callbacks.LearningRateScheduler()
- One can pass it to an optimizer using
tf.keras.optimizers.schedules.LearningRateSchedule()
Now I wondered if there are any differences and if so, what are they? In case it makes no difference, why do those alternatives exist then? Is there a historical reason (and which method should be preferred)?
Can someone elaborate?
...ANSWER
Answered 2021-May-29 at 03:38Both tf.keras.callbacks.LearningRateScheduler()
and tf.keras.optimizers.schedules.LearningRateSchedule()
provide the same functionality i.e to implement a learning rate decay while training the model.
A visible difference could be that tf.keras.callbacks.LearningRateScheduler
takes in a function in its constructor, as mentioned in the docs,
QUESTION
I try to create a custom standardize function for the TextVectorization layer in Tensorflow 2.1 but I seem to get something fundamentally wrong.
I have the following text data:
...ANSWER
Answered 2021-May-25 at 15:59def custom_standardization(input_data):
lowercase = tf.strings.lower(input_data)
stripped_html = tf.strings.regex_replace(lowercase, "
", " ")
stripped_html = tf.strings.regex_replace(stripped_html,r'\d+(?:\.\d*)?(?:[eE][+-]?\d+)?', ' ')
stripped_html = tf.strings.regex_replace(stripped_html, r'@([A-Za-z0-9_]+)', ' ' )
for i in stopwords_eng:
stripped_html = tf.strings.regex_replace(stripped_html, f' {i} ', " ")
return tf.strings.regex_replace(
stripped_html, "[%s]" % re.escape(string.punctuation), ""
)
QUESTION
I'm trying to implement an SPL loss in keras. All I need to do is pretty simple, I'll write it in numpy to explain what I need:
...ANSWER
Answered 2021-May-22 at 21:00The reason you're getting this error is that the indices
in tf.tensor_scatter_nd_update
requires at least two axes, or tf.rank(indices) > = 2
need to be fullfilled. The reason for indices
in 2D
(in scaler update) is to hold two information, one is the length of the updates (num_updates) and the length of the index vector. For a detailed overview of this, check the following answer regarding this: Tensorflow 2 - what is 'index depth' in tensor_scatter_nd_update?.
Here is the correct implementation of SPL loss in tensorflow.
QUESTION
I'm reading Aurélien Géron's book, and on chapter 13, I'm trying to use Tensorflow datasets (rather than Numpy arrays) to train Keras models.
1. The datasetThe dataset comes from sklearn.datasets.fetch_california_housing
, which I've exported to CSV. The first few lines look like this:
ANSWER
Answered 2021-May-25 at 03:42Just as the official docs for tf.keras.Sequential
suggest, no batch_size
needs to be provided when inputs
are instances of tf.data.Dataset
while calling tf.keras.Sequential.fit()
,
Integer or None. Number of samples per gradient update. If unspecified, batch_size will default to 32. Do not specify the batch_size if your data is in the form of datasets, generators, or keras.utils.Sequence instances (since they generate batches).
In case of tf.data.Dataset
, the fit()
method expects a batched dataset.
To batch the tf.data.Dataset
, use the batch()
method,
QUESTION
I encountered many hardships when trying to fit a CNN (U-Net) to my tif training images in Python.
I have the following structure to my data:
- X
-
- 0
-
-
- [Images] (tif, 3-band, 128x128, values ∈ [0, 255])
-
- X_val
-
- 0
-
-
- [Images] (tif, 3-band, 128x128, values ∈ [0, 255])
-
- y
-
- 0
-
-
- [Images] (tif, 1-band, 128x128, values ∈ [0, 255])
-
- y_val
-
- 0
-
-
- [Images] (tif, 1-band, 128x128, values ∈ [0, 255])
-
Starting with this data, I defined ImageDataGenerators:
...ANSWER
Answered 2021-May-24 at 17:23I found the answer to this particular problem. Amongst other issues, "class_mode"
has to be set to None
for this kind of model. With that set, the second array in both X
and y
is not written by the ImageDataGenerator
. As a result, X and y are interpreted as the data and the mask (which is what we want) in the combined ImageDataGenerator
. Otherwise, X_val_gen
already produces the tuple shown in the screenshot, where the second entry is interpreted as the class, which would make sense in a classification problem with images spread out in various folders each labeled with a class ID.
QUESTION
Is there a way to directly update the elements in tf.Variable
X at indices without creating a new tensor having the same shape as X?
tf.tensor_scatter_nd_update create a new tensor hence it appears not updateing the original tf.Variable.
This operation creates a new tensor by applying sparse updates to the input tensor.
tf.Variable assign apparently needs a new tensor value
which has the same shape of X to update the tf.Variable X.
ANSWER
Answered 2021-May-23 at 13:42About the tf.tensor_scatter_nd_update
, you're right that it returns a new tf.tensor (and not tf.Variable). But about the assign
which is an attribute of tf.Variable, I think you somewhat misread the document; the value
is just the new item that you want to assign in particular indices of your old variable.
AFAIK, in tensorflow all tensors are immutable like python numbers and strings; you can never update the contents of a tensor, only create a new one, source. And directly updating or manipulating of tf.tensor
or tf.Variable
such as numpy like item assignment is still not supported. Check the following Github issues to follow up the discussions: #33131, #14132.
In numpy, we can do an in-place item assignment that you showed in the comment box.
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