sushi | SUSHI : Supporting User for SHell script Integration

 by   uzh Ruby Version: v5.0.2 License: No License

kandi X-RAY | sushi Summary

kandi X-RAY | sushi Summary

sushi is a Ruby library. sushi has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

SUSHI: Supporting User for SHell script Integration
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    Quality
      Security
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            kandi-support Support

              sushi has a low active ecosystem.
              It has 23 star(s) with 8 fork(s). There are 20 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 1 open issues and 2 have been closed. On average issues are closed in 9 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of sushi is v5.0.2

            kandi-Quality Quality

              sushi has 0 bugs and 0 code smells.

            kandi-Security Security

              sushi has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              sushi code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              sushi does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              sushi releases are available to install and integrate.
              sushi saves you 12038 person hours of effort in developing the same functionality from scratch.
              It has 24298 lines of code, 676 functions and 314 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

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            sushi Key Features

            No Key Features are available at this moment for sushi.

            sushi Examples and Code Snippets

            No Code Snippets are available at this moment for sushi.

            Community Discussions

            QUESTION

            JavaScript: Comparing Two Arrays and Replacing Objects
            Asked 2021-Jun-06 at 00:27

            I have two arrays that I would like to compare against each other based on the Username and create a new array that includes EmployeeName

            ...

            ANSWER

            Answered 2021-Jun-06 at 00:20

            You can make a Map to store information about each employee such as EmployeeName at each key (being the Username). Then you can use .map() on your first array and use the OrderBy key to grab the associated employee data from the map you made, which you can then spread into the resulting new object:

            Source https://stackoverflow.com/questions/67854852

            QUESTION

            How can I split a string into separate keys and values?
            Asked 2021-Jun-03 at 21:47

            I have the following string:

            ...

            ANSWER

            Answered 2021-Jun-03 at 19:49

            QUESTION

            Transferring JavaScript objects to HTML table
            Asked 2021-May-31 at 07:11

            The object within an object contains variables such as "name", "amount", "amountType", and "cal". The strings on those variables should be transferred through loop as several row in the given HTML table. Each variable should be on its own cell.

            I already made one row and made 4 cell for the name, amount, amount type, and calorie columns. Then, I tried to transfer the objects elements inside the cell using the index of the object.

            ...

            ANSWER

            Answered 2021-May-31 at 07:11

            You're treating the mealObj as an array while it's an object and also you're not looping, so your code only runs once.

            Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.

            Source https://stackoverflow.com/questions/67768563

            QUESTION

            Taking an object's element and turning it into a button's innerHTML
            Asked 2021-May-31 at 04:03

            On the function "createIngrList", it should take all the ingredient names, such as "Butter", "Beef", "Onion", etc., and turn it into buttons. So each button should have a text with the name of an ingredient written on it. As of now, there is just 4 buttons with "undefined" written on it. If possible, all the repeating ingredients such as "Onion" should not be made into button twice. Once is enough.

            ...

            ANSWER

            Answered 2021-May-31 at 00:33

            I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.

            You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name to get the name. Through the first for/in loop the key -> i will be the name of the food, then use the second key along witht he first to get the actual .name => obj[i][k].name this will give you the ingredient name.

            I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...

            You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.

            NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name, likely that is just a typo...

            Source https://stackoverflow.com/questions/67766627

            QUESTION

            Posting array of objects to REST API with ReactJS
            Asked 2021-May-28 at 07:30

            I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:

            ...

            ANSWER

            Answered 2021-May-27 at 21:44

            You are setting the ingredients state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError. If you want to send an array that way you must specify the array bracket [ and ] in order to make it a valid array.

            To solve it just change:

            Source https://stackoverflow.com/questions/67730171

            QUESTION

            Get recursive rootID of parent-child-table with ef-core
            Asked 2021-May-21 at 20:26

            I have an SQL-Table which is build like a tree list (parent child). Means you have rootId's and childId's. Each entity has a ParentId. If the ParentId is null then that element is a root item.

            Here an example of the hierarchical architecture

            ...

            ANSWER

            Answered 2021-May-21 at 20:26

            If you don't interest to load all records from database then process them, you have two choices :

            Solution 1 : Write a StoreProcedure and processing in database.

            Solution 2 : Write a recursive function that send multiple requests to database (In the amount of root depth)

            Here is a function for solution 2 :

            Source https://stackoverflow.com/questions/66242101

            QUESTION

            I can't delete an item from a drop-down menu properly. It deletes more than one
            Asked 2021-May-19 at 13:28

            The HTML create two drop-down menu and one delete button. One JavaScript, I made a code to fill those drop-down box with arrays. And, every time I change the item on the first drop-down menu, a new set of options appears on the second drop-down menu. The goal is, whenever I clicked the delete button, I should be able to delete an item on the second drop-down and when I changed the item on the first drop-down menu, hence another set of option will appear on the second drop-down menu, I should be able to delete an item from there as well.

            The problem is, once the set of items on the second drop-down menu has been changed, a bunch of unwanted results occurs, such as deleting more than one items or deleting on another set of items. For example, if I delete something from "meal", it'll delete one item. Then if I go over to "dessert" and delete something from there, it'll delete one item. But if I go back to "meal" again, a bunch of items are now deleted. Just try it out yourself to see what I mean

            ...

            ANSWER

            Answered 2021-May-19 at 13:28

            What were you doing wrong?
            In practice your code stored in the variable menuOption the first menu, doing so every time you tried to delete something it was removed from the first menu

            Solution

            1. Call up the menu variable as often as needed
            2. Store index before remove it
            3. Extra:
              • Use menuList.selectedIndex instead of drinkListArr.indexOf(subMenuOption)
              • Use menuType.value instead of menuType.options[menuType.selectedIndex].text

            Source https://stackoverflow.com/questions/67603885

            QUESTION

            select first order for each customer from two tables
            Asked 2021-May-18 at 11:39

            Hi guys I have two tables dbo.Sales (customer_id, order_date, product_id) and dbo.Menu (Product_id, product_name, price). The question is What was the first item from the menu purchased by each customer?

            My solution is

            ...

            ANSWER

            Answered 2021-May-18 at 11:39

            You could use a ROW_NUMBER() window function to get the earliest product_id per customer and then join to the Menu table to get your product details.

            Edit: Updated ORDER to ASC.

            Source https://stackoverflow.com/questions/67561322

            QUESTION

            R: Converting "tidyr/tidyverse" statements to "dplyr" and "reshape2"
            Asked 2021-Apr-29 at 18:33

            I am working with the R programming language. In a previous post (R: converting tidyverse to dplyr/reshape2 for plots), I learned how to make automatic histograms for all categorical variables in my dataset:

            ...

            ANSWER

            Answered 2021-Apr-29 at 18:33

            With reshape2::melt, specify the id columns in id.vars i.e. deselect_not_factors, and the corresponding arguments for names_to and values_to are variable.name and value.name

            Source https://stackoverflow.com/questions/67322709

            QUESTION

            R: Automatically Producing Histograms
            Asked 2021-Apr-29 at 04:41

            I am using the R programming language. I created the following data set for this example:

            ...

            ANSWER

            Answered 2021-Apr-29 at 04:30

            A ggplot2/tidyverse solution is to lengthen each column into data and then use faceting to plot them all in the same page:

            (with edit to plot only factor variables)

            Source https://stackoverflow.com/questions/67310844

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sushi

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/uzh/sushi.git

          • CLI

            gh repo clone uzh/sushi

          • sshUrl

            git@github.com:uzh/sushi.git

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