cron-parser | Dissect your Cron pattern | Cron Utils library
kandi X-RAY | cron-parser Summary
kandi X-RAY | cron-parser Summary
cron-parser is a Ruby library typically used in Utilities, Cron Utils applications. cron-parser has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.
Dissect your Cron pattern!
Dissect your Cron pattern!
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Quality
Security
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Support
cron-parser has a low active ecosystem.
It has 11 star(s) with 1 fork(s). There are 2 watchers for this library.
It had no major release in the last 6 months.
There are 1 open issues and 0 have been closed. There are no pull requests.
It has a neutral sentiment in the developer community.
The latest version of cron-parser is current.
Quality
cron-parser has 0 bugs and 0 code smells.
Security
cron-parser has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
cron-parser code analysis shows 0 unresolved vulnerabilities.
There are 0 security hotspots that need review.
License
cron-parser is licensed under the MIT License. This license is Permissive.
Permissive licenses have the least restrictions, and you can use them in most projects.
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cron-parser releases are not available. You will need to build from source code and install.
Installation instructions, examples and code snippets are available.
It has 589 lines of code, 61 functions and 13 files.
It has medium code complexity. Code complexity directly impacts maintainability of the code.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of cron-parser
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of cron-parser
cron-parser Key Features
No Key Features are available at this moment for cron-parser.
cron-parser Examples and Code Snippets
No Code Snippets are available at this moment for cron-parser.
Community Discussions
Trending Discussions on cron-parser
QUESTION
Cron expression for specific days using cron-utils
Asked 2021-Sep-19 at 09:24
I am using cron-utils jar for generating cron expression like:
0 0 0 ? * 1,3,7 *
At 00:00:00am, on every Sunday, Tuesday and Saturday, every month
How can i create the 'days of week' expression so it will be list and not only one value?
Below is my code for above expression:
...ANSWER
Answered 2021-Sep-19 at 09:24You can use and()
and you will be able to pass multiple days.
Example:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install cron-parser
Install gem by using following command:.
Support
You’re encouraged to contribute to this gem.
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