lapin | AMQP client library in Rust , with a clean , futures based API | Pub Sub library
kandi X-RAY | lapin Summary
kandi X-RAY | lapin Summary
A Rust AMQP client library. This project follows the AMQP 0.9.1 specifications, targeting especially RabbitMQ.
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lapin Key Features
lapin Examples and Code Snippets
Community Discussions
Trending Discussions on lapin
QUESTION
I am looking for sample code illustrating consuming messages from RabbitMQ using lapin including accessing the AMQP message payload.
I am trying to run the "consumer.rs" example from "https://raw.githubusercontent.com/CleverCloud/lapin/master/examples/consumer.rs" but I am getting the below
...ANSWER
Answered 2021-Oct-15 at 09:22Your problem is that you are likely depending on the latest stable version of lapin
in crates.io, which at this moment is 1.8. However, the example you are running is from the master
branch. Seems like the developer is preparing for a new major version, 2.0, and as such, API of the library is different in master
.
If you use the same example file from the 1.8 branch, the code compiles.
Alternatively: use the example from master
and the crate from master
, rather than the latest stable release.
QUESTION
Link : https://www.codechef.com/LRNDSA01/problems/LAPIN
Program description : Lapindrome is defined as a string which when split in the middle, gives two halves having the same characters and same frequency of each character. If there are odd number of characters in the string, we ignore the middle character and check for lapindrome. For example gaga is a lapindrome, since the two halves ga and ga have the same characters with same frequency. Also, abccab, rotor and xyzxy are a few examples of lapindromes. Note that abbaab is NOT a lapindrome. The two halves contain the same characters but their frequencies do not match. Your task is simple. Given a string, you need to tell if it is a lapindrome.
My code :
...ANSWER
Answered 2021-Mar-01 at 15:00The algorithm you implemented is both incorrect and very slow (even if it was correct). Since the input characters are limited to a..z, you could implement a fast algorithm by comparing the frequencies of letters in the left and right portions of the input text. An example implementation is below. The code assumes that the character codes of a..z are contiguous, which isn't guaranteed by the C standard.
QUESTION
Suppose I have the following graph
...ANSWER
Answered 2020-Dec-01 at 15:09A good approach when chaining more MATCH
clauses is to use WITH
statement that separates query parts explicitly, allowing you to declare which variables to carry over to the next part.
In your case:
QUESTION
I have an excel file which I regularly update in Power BI.
I added an additional line, which did not cause any issues to my operations, however, Power BI also added three "null" lines afterwards.
I do not understand why.
I thus created a table, because I thought that I would prevent this.
But I still have "null" rows appended to my lines.
The only remedy that I found is to filter rows on a column (Lapin) which as no null (and which should never in future), in the following way:
...ANSWER
Answered 2020-May-29 at 18:41On importing from Excel, you can get dummy rows that are due to formatting, hidden formulas, rows that are holding over something in the cell reference in the background. Its not just Power BI, this happens on importing into SQL Server tables, Pandas, and on exporting the Excel to csv etc. The best option is to us the remove rows function in the Power Query
Select Remove Rows > Remove Blank Rows
QUESTION
I expected to get two list that contains all males in one and all females in another list. I am just getting a list with only one item.
Using Python2.7
Output: ['Phyllis Lapin'] ['Roy Anderson']
Expected Output :['Phyllis Lapin', 'Pam Beesly', 'Angela Martin' etc..]
------------------------['Dwight Shrute','Jim Halpert','Ryan Howard' etc..]
...ANSWER
Answered 2020-May-04 at 22:24You're overriding the self.male
and self.female
fields in each iteration, what you want to do is append the lists with the new elements
for your Manager's __init__
try:
QUESTION
"Select the beers that have been drank by more than one person". Basically, I'm trying to retrieve a query result that shows me the list of the beers that has been drank by more than one person and then the name of the persons who have drank that beer. I tried to do a group and having clause but realized that I cant have a group clause since I'm interested in duplicate values from both the name and beer columns. What should I do?
...ANSWER
Answered 2020-Apr-28 at 17:00You need a condition in the HAVING clause:
QUESTION
I'm using a service called opentok which store video on their cloud and give me a callback url when file are ready so that i can download it and store on my cloud provider.
We use gcloud where we work and i need to download the file, then store it on my gcloud bucket with a firebase cloud functions.
Here is my code :
...ANSWER
Answered 2020-Mar-30 at 10:25If someone is looking for this in the futur here is how i solved it :
With Firebase cloud functions you can write temporary files in /tmp
(see here for more information https://cloud.google.com/functions/docs/concepts/exec#file_system)
I solved the problem by using node-fetch
package andwriteStream
function of Node.JS :
QUESTION
The aim is to select all the names of the persons who have drank all beers from tyskland. In this case, im looking to find the name of the person that has max(count) of beers from germany. I formed smaller tables along the way to try to get the result: From the table below :
...ANSWER
Answered 2020-Mar-29 at 20:25You can do it with RANK()
window function:
QUESTION
Ive been looking around different sites and havent found any examples om how to join different tables when looking for a result while including a except statement in the query. To know the structure of such a query would be very helpful! Lets say I want to find the names of the people who havent drank the beer Anchor Steam Beer, how should the query operation look like?
My own attempt looked like this:
...ANSWER
Answered 2020-Mar-27 at 18:39You can use aggregation. Assuming that the table names are beers
and person_beers
:
QUESTION
Im trying to find the person who has drank most beer types from USA. The result should be just be the name of that person alone and not include a count column. How should I perform the select statement? The result should look like this:
...ANSWER
Answered 2020-Mar-04 at 18:55Use GROUP BY
, ORDER BY
and LIMIT
if you want one result (even when there are ties):
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Install lapin
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
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