segment-tree | Rust implementation of two segment trees | Dataset library

 by   Darksonn Rust Version: Current License: MIT

kandi X-RAY | segment-tree Summary

kandi X-RAY | segment-tree Summary

segment-tree is a Rust library typically used in Artificial Intelligence, Dataset applications. segment-tree has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A Rust implementation of two segment trees and a fenwick tree.
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            kandi-support Support

              segment-tree has a low active ecosystem.
              It has 28 star(s) with 2 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              segment-tree has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of segment-tree is current.

            kandi-Quality Quality

              segment-tree has 0 bugs and 0 code smells.

            kandi-Security Security

              segment-tree has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              segment-tree code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              segment-tree is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              segment-tree releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            segment-tree Key Features

            No Key Features are available at this moment for segment-tree.

            segment-tree Examples and Code Snippets

            No Code Snippets are available at this moment for segment-tree.

            Community Discussions

            QUESTION

            Dictionary using Balanced BST lookup time complexity
            Asked 2022-Jan-31 at 07:14

            I was going through an article in geeksforgeeks on how to implement dictionary using balanced BST and found this line:

            If we store keys in binary search tree, a well balanced BST will need time proportional to M * log N, where M is maximum string length and N is number of keys in tree.

            I didn't understand how this would be O(M*logn), given balanced BSTs always maintain a max height of O(logn), shouldn't this be (logn)?

            ...

            ANSWER

            Answered 2022-Jan-31 at 07:14

            This quote is taken from a context of searching words in a dictionary:

            Trie is an efficient data structure for searching words in dictionaries, search complexity with Trie is linear in terms of word (or key) length to be searched. If we store keys in binary search tree, a well balanced BST will need time proportional to M * log N, where M is maximum string length and N is number of keys in tree. Using trie, we can search the key in O(M) time. So it is much faster than BST.

            In a BST these words would be stored such that one node gets one word.

            Although in a balanced BST of 𝑁 nodes you need to visit O(log𝑁) nodes to find the targeted value in the worst case, it will also take time to compare a node's string with the target string. As the maximum length of a word is given as 𝑀, the worst case time complexity for each individual string comparison is O(𝑀). As such a comparison happens at each visited node, this gives a total complexity of O(𝑀log𝑁).

            Source https://stackoverflow.com/questions/70920585

            QUESTION

            Compute sum of (min*max) across all subarrays of the array
            Asked 2020-May-18 at 01:29

            given N elements of an array compute the sum (min*max) across all the subarrays of the array.

            e.g. N = 5

            Array: 5 7 2 3 9

            output: 346 (5*5 + 7*7 + 2*2 + 3*3 + 9*9 + 5*7 + 2*7 + 2*3 + 3*9 + 2*7+2*7 + 2*9 + 2*7 + 2*9 + 2*9)

            here is the complete question

            i cannot think of anything better than O(n^2). The editorial solution uses segment trees which i couldnt understand.

            ...

            ANSWER

            Answered 2020-May-18 at 01:29

            Hint regarding the editorial (the details of which I am uncertain about): if we can solve the problem for all the intervals that include both A[i] and A[i+1], where i divides A in half, in O(n) time, then we can solve the whole problem in O(n log n) time using divide and conquer, solving left and right separately, and adding to that the intervals that overlap both left and right.

            Source https://stackoverflow.com/questions/61707201

            QUESTION

            Iterative segment tree implmentation
            Asked 2020-Apr-10 at 01:20

            I'm referring to this post : https://www.geeksforgeeks.org/segment-tree-efficient-implementation/

            Pasting the code here for reference. My questions are below the code.

            ...

            ANSWER

            Answered 2020-Apr-10 at 01:20
            Question 1

            The variable p doesn't mean parent, it means child. In for loop, i is child node, and we update value of i's parent.

            tree[p+n] = value;: update the value of leave node (node without children). Then we update value of node's parent from the leave node. tree[i>>1] = tree[i] + tree[i^1];, tree[i>>1] is tree[i]' parent.

            For example: the array size is 16 (the tree size is 32) and I want to update arr[8]. So I call updateTreeNode(8, value). First three[8+16] is updated, which corresponds to arr[8]. Then p is set to 24. In for loop, we update p's parent (tree[12]), then set p to p/2 (p=12), until p doesn't have parent.

            Qustion 2

            If l and r is even, we add the parent's value in next recurrence. That's the function of segment tree, to avoid querying each element in the interval.

            For example: the array size is 16 and I want to query [8,10). In segment tree, the interval is [24,26). We don't need to add value of tree[24] and tree[25], we add value of tree[12]!

            Source https://stackoverflow.com/questions/61132290

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install segment-tree

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/Darksonn/segment-tree.git

          • CLI

            gh repo clone Darksonn/segment-tree

          • sshUrl

            git@github.com:Darksonn/segment-tree.git

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