envious | A Simplistic Programming Language That Targets the LLVM | Interpreter library

by Hacker-007 Rust Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | envious Summary

envious is a Rust library typically used in Utilities, Interpreter applications. envious has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A new programming language that focuses on simplicity without compromising on speed. This language is meant to be born from the desires of the community. In a sense, it is a language that will hopefully address the issues that developers have with other programming languages. Perhaps more importantly, this project is a way for me to learn more about compilers and VMs. Envy is heavily influenced by Math. A lot of the symbols used comes directly from mathametical theory. In that right, Envy is easy to understand. Envy targets the LLVM or Low-Level Virtual Machine. Also, note that this language is under active development and that there will be many changes in the future. Currently, there are 4 different parts of the project that have been partially completed. Envious is an expression based language. Therefore, most of the statements written are expressions. Here is a detailed description of each expression. The define expression creates a new function that is very similar to math.

Support

Quality

Security

License

Reuse

Support

envious has a low active ecosystem.

It has 7 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 2 open issues and 6 have been closed. On average issues are closed in 20 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of envious is current.

Quality

envious has 0 bugs and 0 code smells.

Security

envious has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

envious code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

envious is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

envious releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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envious Key Features

No Key Features are available at this moment for envious.

envious Examples and Code Snippets

No Code Snippets are available at this moment for envious.

Community Discussions

Trending Discussions on envious

How do I split and sort strings in a list using for loops in Python

C Socket programming HTTP request: bad request after successful request

Split string cutting off.. no idea what's going on

Flattening list

Eclipse throws the error "Data cannot be resolved to a type" for using the Project Lombok

How to split each words from several lines of a word file? (python)

beginner issue with python : how to make one list of separated lines in a file in python

Unexpected newline in my retrieved web data

Python Open() and File Handles?

Protect your API key from being stolen or abused

QUESTION

How do I split and sort strings in a list using for loops in Python

Asked 2022-Mar-28 at 18:57

Trying to read a file then store it in a list but not getting the desired output:

...

ANSWER

Answered 2022-Mar-28 at 18:57

All you have to do is loop through all of the words in the sentence, then check if they are already in the list, then append them.

Source https://stackoverflow.com/questions/71652342

QUESTION

C Socket programming HTTP request: bad request after successful request

Asked 2022-Feb-27 at 18:00

I am learning socket programming using C. I am trying to make HTTP request and get its response.

I put the response into a file called "response.txt". Since I have no idea how long the response will be, I put the recv() inside a while loop, append the received content to "response.txt", and break the loop when the socket receives 0 bytes.

The question I have is that I am receiving 2 responses. One is "HTTP/1.1 200 OK", another one is "HTTP/1.1 400 Bad Request".

I want to know why this happen. Is it because there is some unwanted bug in my code, or is it because of some networking or protocol design?

This is the part of the code related to http requests.

...

ANSWER

Answered 2022-Feb-27 at 18:00

Source https://stackoverflow.com/questions/71286877

QUESTION

Split string cutting off.. no idea what's going on

Asked 2021-Jul-16 at 02:58

I'm a beginner in Python and I used .split to make every word in an unorganized list into an organized list. But it seems to be cutting off some words or something, making it an incomplete list.

So the words I initially copied and pasted were formatted like so (with the line break after every word):

adorable

adventurous

aggressive

agreeable

and so on...

After typing the code:

...

ANSWER

Answered 2021-Jun-30 at 07:40

If you have a word per line on a txt file the most straightforward method would be something like

Source https://stackoverflow.com/questions/68190054

QUESTION

Flattening list

Asked 2021-Jan-13 at 06:11

I'm taking a Python class on EDx and am stuck on this assignment. I'm hoping someone can point me in the right direction on here.

The instructions are here:

8.4 Open the file romeo.txt and read it line by line. For each line, split the line into a list of words using the split() method. The program should build a list of words. For each word on each line check to see if the word is already in the list and if not append it to the list. When the program completes, sort and print the resulting words in alphabetical order. You can download the sample data at

This is the data I am to parse:

But soft what light through yonder window breaks It is the east and Juliet is the sun Arise fair sun and kill the envious moon Who is already sick and pale with grief

Below is my code:

...

ANSWER

Answered 2021-Jan-13 at 05:53

You can use this code below

Source https://stackoverflow.com/questions/65696200

QUESTION

Eclipse throws the error "Data cannot be resolved to a type" for using the Project Lombok

Asked 2020-Dec-07 at 15:48

I am new to Java and Project Lombok, I am trying to follow some tutorials to understand it better. I have created a very simple java project to test the Project Lombok and it throws the error Data cannot be resolved to a type when I add the annotation @Data to my class.

I am using macOS and Eclipse IDE for running my Java application. Following are the steps that I followed to run my first Java and Lombok project:

Downloaded the latest Project Lombok version 1.18.16 and placed it in the Documents folder.
Installed the Project Lombok in my system using the command java -jar lombok.jar.
Restarted my Eclipse and verified that Project Lombok installed in the Eclipse -> About Eclipse: "Lombok v1.18.16 "Envious Ferret" is installed. https://projectlombok.org/"
Created a new Java project and the class Alien.
Added the Project Lombok JAR to my project Classpath.
Added the @Data annotation to my Alien class and imported the JAR file but I get the error The type lombok.Data is not accessible for my import statement import lombok.Data;
Also, I get the error Data cannot be resolved to a type for my annotation at the class level public @Data class Alien

I am really unsure what's wrong. I tried to find out but all the answers have mentioned the same steps. I was just wondering what am doing wrong. Any help would be really appreciated.

Following is my complete code:

...

ANSWER

Answered 2020-Dec-04 at 13:09

The error The type SOMETYPE is not accessible is... bizarre. As far as I know, there are only three ways to get that error:

lombok.Data isn't public. Except, it is, so this can't be it.
You've manually added a list of forbidden packages ('access rules') in eclipse, to deny yourself access to lombok. Presumably, you'd remember if you did that, so it can't be this.
lombok is loaded as a module, and the lombok package isn't exported. Except, the only versions of lombok that exist either aren't modularized (and module-info-less jar files export everything), or they are, and the lombok package is exported. So it can't be this.

Perhaps it would be useful to doublecheck all of these:

I guess javap -cp lombok.jar lombok.Data, and check that it's public, but, this just cannot be it, so you probably don't need to bother.
For that access rules thing, which is the most likely of 3 very unlikely options, go into your project's setup (right click on it in e.g. the package explorer, and pick 'properties...', you can set up lots of stuff from there), go to 'build path', find the lombok.jar, open it up, and check 'access rules'. It should read 'no rules defined'.
Go into your project's setup and ensure it's all set to java8, and rebuild. Presumably you want to use new features, but the point is to at least isolate down to: It's a module issue.

Source https://stackoverflow.com/questions/65144033

QUESTION

How to split each words from several lines of a word file? (python)

Asked 2020-Jul-19 at 18:47

I have a text file:

...

ANSWER

Answered 2020-Jul-19 at 16:47

output = []
with open('file_name') as f:
    for i in f.readlines():
        for j in words_to_split:
            i = ''.join(i.split(j))
        output.append(i)

Source https://stackoverflow.com/questions/62983086

QUESTION

beginner issue with python : how to make one list of separated lines in a file in python

Asked 2020-Jul-12 at 13:59

I have an issue as a beginner that made me exhausted trying to solve it so many times/ways but still feel dump, the problem is that I have a small file that I read in python and I have to make a list of the whole lines to sort it in alphabetical order. but when I try to make it in a list, it makes a separate list for each line.

here is my may that I tried to solve the issue using it:

...

ANSWER

Answered 2020-Jul-12 at 13:59

To have a list of all lines you can use simple

Source https://stackoverflow.com/questions/62861884

QUESTION

Unexpected newline in my retrieved web data

Asked 2020-May-10 at 00:06

I am taking a self-learning class, and I am using Python 3.8 to reproduce an in-class exercise regarding connecting to websites and extracting text. The code I am running looks like this:

...

ANSWER

Answered 2020-May-10 at 00:06

Your buffer 512 was reached and so print came to an end and reiterated causing the newline

Change Your code

Source https://stackoverflow.com/questions/61705321

QUESTION

Python Open() and File Handles?

Asked 2020-May-09 at 14:44

I'm new to Python and I have read a file into memory. I then do a simple loop to see what the contents of the file are....

Then I try to perform another action on the file and it appears it has disappeared or left memory?

Can someone please explain what's going on and how I can store a file in memory to query it?

...

ANSWER

Answered 2020-May-09 at 14:44

The object returned by open acts as its own iterator. When you iterate over its contents, the file pointer remains at the end of the file. That means the second for loop starts at the end, rather than getting a "fresh" iterator that starts at the beginning.

To iterate again, use the seek method to return to the start of the file.

Source https://stackoverflow.com/questions/61698443

QUESTION

Protect your API key from being stolen or abused

Asked 2020-Apr-25 at 06:13

Hello so I would like to ask what are the other ways of protecting your api from being abused or DDOS'ed by your envious enemies?

I have this simple website of mine that uses Google API and some homebrew API that is deployed in Heroku.

My first idea is to simply never call an API on the front end let the webhost server call everything first and load the data with the webpage making it so that when the page is loaded there is no trace of your API in the front end.

But sometimes when your websites contains an auto-updating data your api has to be in the front end. In scenarios such as these what are other "pro" measures i can take so that i can protect my API.

I have heard that there are ways that involves OAuth and SSL ? how do they basically work?

My API are deployed to Heroku and is created using Node.Js express library.

...

ANSWER

Answered 2020-Apr-25 at 06:13

Well APIs that are in the front end can and will be stolen, its just a matter of when. It is the nature APIs. Even API in the app can be retrieved by reading its assembly.

What you can do though is limit what the user can do to your API in server side, either place timeout, how fast is this specific device calling you API, then simply lock out the uses IP address for a day or so.

There is no way around it, the whole industry has to change in order for you to completely hide APIs.

Source https://stackoverflow.com/questions/61409745

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install envious

You can download it from GitHub.
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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