bk | Terminal Epub reader | Command Line Interface library
kandi X-RAY | bk Summary
kandi X-RAY | bk Summary
bk is a terminal EPUB reader, written in Rust.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of bk
bk Key Features
bk Examples and Code Snippets
Usage: bk [] [-m] [-t] [-w ]
read a book
Options:
--bg background color (eg 282a36)
--fg foreground color (eg f8f8f2)
-m, --meta print metadata and exit
-t, --toc start with table of contents open
def add_operators(operators,
operator_name=None,
addition_tiers=None,
name=None):
"""Efficiently add one or more linear operators.
Given operators `[A1, A2,...]`, this `Op` returns a possibly
def compute_bridges(graph: dict[int, list[int]]) -> list[tuple[int, int]]:
"""
Return the list of undirected graph bridges [(a1, b1), ..., (ak, bk)]; ai <= bi
>>> compute_bridges(__get_demo_graph(0))
[(3, 4), (2, 3), (2
public static Optional findLedgerByName(BookKeeper bk, String name) throws Exception {
Map ledgers = new HashMap();
final AtomicInteger returnCode = new AtomicInteger(BKException.Code.OK);
final CountDownLatch processDone = ne
Community Discussions
Trending Discussions on bk
QUESTION
I coded lazy loading for videos, background images and images but didn't work on ios safari.
I want show the background images/images/video with IntersectionObserver method.
below codes are for background image and video.
...ANSWER
Answered 2021-Jun-10 at 21:40item.target.ariaLabel
is availbale in v8 engine (chrome). hence I changed it to item.target.getAttribute('aria-label')
now it works.
QUESTION
I am a Python beginner. Python versions 3.8 and 3.9
In an existing URL validation code, I ran into issues with the password containing '['. The password is PN-[.d.g5(R{bK}[5ZLx,4~K*hHrSy32=q+
URL:
...ANSWER
Answered 2021-Jun-02 at 13:20There also curly braces in problematic password, so you need to add them too.
r"(?::[-a-z0-9._\[\]\{\}~%!$&'()*+,;=:]*)?@)?"
QUESTION
I have a task to create a table function that receives a string and sorts it into different columns. The string itself may vary, but the columns are supposed to be the same always.
The string is: '100^TEst¬200^TEst2¬300^Test3'
, but for example if I add "¬400^Test4" that should be in the result set as well.
Here is what I've managed to do so far.
...ANSWER
Answered 2021-May-25 at 14:07Firstly, although you can use STRING_SPLIT
the order of the value returned by it is not guaranteed. As you define the length of your parameter as 1000
in your function stringSplit1
this means we can safely use a function like DelimitedSplit8K_LEAD
which does guarantee the order by providing the ordinal position of each value. This means we can do something like this:
QUESTION
Hello everybody. I have a Blazor project as below: Server And Shared Layer Picture AND Client Layer Inside of Food Class File , I have two classes as below:
...ANSWER
Answered 2021-May-21 at 04:36Hi at first you should create a method and get data from database and send data to Blazor component and then use data in edit component like below:
QUESTION
'm new to jq, and hoping to convert JSON below so that, for each object in the records array , the "Account" object is deleted and replaced with an "AccountID" field which has a the value of Account.Id. Assuming I don't know what the name of the field (eg. Account ) is prior to executing, so it Has to be dynamically included as an argument to --arg.
Contacts.json:
...ANSWER
Answered 2021-May-15 at 02:05The key to a simple solution is |=
. Here's one using map
:
QUESTION
I am trying to , create a list view that allows a user to browse and borrow books, so as a data source I want to load and mapp the XML into objects handled in memory. in spring boot, I am very new to java and spring boot, I got this error:
...ANSWER
Answered 2021-May-11 at 10:06I've checked and can confirm. You need to
- add
@XmlRootElement(name = "catalog")
on your Catalog class to tell JAXB this can be at the root - change annotation to
@XmlElement(name="book")
on getBooks() method (otherwise doesn't match, look for books) - add annotation
@XmlAttribute
on BooksetId
method (otherwise you end up with empty ids)
And then your code works:
QUESTION
Hello I'm just Starting In python day 3 and trying own projects with selenium chromedriver
i'm trying to automate login and update phone number on 50 accounts but i don't know how to get username,pass,number from csv file one row at a time and loop the whole project in a loop. please help any advice would be great
Here is the csv file Csv image file
...ANSWER
Answered 2021-May-09 at 10:04Take a look at this. Username is in index 0,password is in index 1 and number is in index 2.
QUESTION
I'm trying to build a chess game in Python using tkinter for graphics. I've created a grid that is 8x8 (rows and columns) and placed Tiles there (which is a type of button). It all works great, until you fill an entire row with chess pieces, then the entire row dissappears. And I have no idea why.
When filling entire row except one: https://gyazo.com/865aed481e4a84c5e9e8918695410006
When filling entire row: https://gyazo.com/acf48c9790335ba11913b6017d2652c3
As you can see, the entire row of buttons dissappear^
Here's my code:
Code for the Tile class (inherits tkinter button)
...ANSWER
Answered 2021-May-06 at 16:02Adding minsize=self.square to the row and column configuration solved the problem.
QUESTION
Given two integer arrays A of size n and B of size k, and knowing that all items in the array B are unique, I want to find an algorithm that finds indices j' < j'', such that all elements of B belong to A[j' : j''] and value |j''-j'|is minimized or returns zero if there are no such indices at all. I also note that A can contain duplicates.
To provide more clarity, we can consider array A = {1, 2, 9, 6, 7, 8, 1, 0, 0, 6} and B {1, 8, 6}, then you can see that B ⊆ A[1 : 6] and B ⊆ A[4 : 7], but at the same time 7−4 < 6−1, thus algorithm should output j'= 4 and j''= 7.
I want to find an algorithm that runs in O(nk) time.
My work so far is that I was thinking for each j'∈ [n], I can compute the minimum j'' ≥ j' so that B ⊆ A[j', j'']. If I assume B = {b1, ..., bk}, let Next[j'][i] denote the smallest index t ≥ j' so that at = b_i, i.e., the index of next element after a_j' (included) which equals bi. In particular if such t doesn’t exist, simply let Next[j'][i] = ∞. If I am able to show that the minimum j'' is the following
j'' = max i∈[k] of Next[j'][i],
then I think I will be able to design a dynamic programming algorithm to compute Next in O(nk) time. Any help on this dynamic programming problem would be much appreciated!
...ANSWER
Answered 2021-May-05 at 19:56Just run a sliding window that maintains the invariant of including all elements of B. That's O(n) with a hashmap.
QUESTION
For this example I'm working in the tab "Math". What I would like to do is that if any of these columns' values ("O", "S", "W", "AA", AE", "AI", "AU", "AY", "BC", BG", "BK") are "0" or "1", then columns D-J of the same row would import into the tab "MATH ANALYSIS".
You can see that AU9 has a value of "0", so I would want D-J of row 9 to import into the MATH ANALYSIS tab, and what would be even better is if I could also then have a column there that indicates the column header for that column, so that I know which column has the 0 or 1. In this case AU is PA alignment_score, so I'd love it if I would get D-J and then some identification of that column, like could it read the value of "AU2"?
I've put the values into the MATH ANALYSIS tab that I would want to see, based on the values of row 9.
Can this be done??
...ANSWER
Answered 2021-May-03 at 21:47You can do this with the query()
function. Usually you would use conditions like S = 0 or S = 1 or W = 0 or W = 1
but there would be a lot of repetition, so in this case it may be easier to coerce the numbers to text and use pattern matching instead, like this:
=query(Math!A2:BK, "select D, E, F, G, H, I, J where O matches '0|1' or S matches '0|1' or W matches '0|1' or AA matches '0|1' or AE matches '0|1' or AI matches '0|1' or AU matches '0|1' or AY matches '0|1' or BC matches '0|1' or BG matches '0|1' or BK matches '0|1'", 1)
See the new Solution sheet in your sample spreadsheet for an illustration, and the query() help page for more information.
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Install bk
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
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