xorf | Xor filters - efficient probabilistic hashsets | Hashing library
kandi X-RAY | xorf Summary
kandi X-RAY | xorf Summary
This repository hosts a Rust library implementing xor filters -- data structures for fast approximation of set membership using little memory. Probabilistic filters like xor filters are useful when it's okay to have false positives sometimes, but it's important to be space and time efficient. In other words, they trade off accuracy for efficiency as compared to general-purpose hashsets. Filters like xor filter are often used in conjunction with larger hash-based data structures, with the filter doing a "first pass" of the work to avoid using a more expensive resource unnecessarily. For example, filters like xor filters can be used to reduce disk writes in a cache or identify malicious URLs in a browser. Xor filters are faster and smaller than Bloom and Cuckoo filters. Xor filters incur a relative time penalty in construction, but are very fast in lookups; the expectation is that construction of a filter is amortized after many queries. Daniel Lemire's go implementation provides a useful summary of xor filters' benefits and listing of other xor filter libraries.
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xorf Key Features
xorf Examples and Code Snippets
[dependencies]
xorf = { version = "M.m.p", features = ["nightly"] }
[dependencies]
xorf = { version = "M.m.p", features = ["serde"] }
[dependencies]
xorf = { version = "M.m.p", default-features = false }
scripts/check lf # validates lint and format
scripts/check test # tests source code
Community Discussions
Trending Discussions on xorf
QUESTION
I am trying to solve sure but can you SKI on codewars. It is about to express lambda in SKI combinators. Source is at https://repl.it/@delta4d/SKI.
After some researching, especially the Combinatory Logic, I am able to solve all the cases except xor
.
I first translates xor into
...ANSWER
Answered 2018-Apr-30 at 12:44The problem comes from the double use of x
in λxy.y (x false true) x
. It's forced to have two types simultaneously. Since y
uses x
, y
must return something of let's say type a
. Now this means that x false true
is also of type a
. So something of type a
must be (b -> b -> a)
(for some b
). But that's impossible, since that means a
must contain itself.
It's worth noting that your solution is correct wrt. SK, just not Haskell's type system. So to fix we need to not use x
twice with different types. So why not make them the same type with λxy.y(x false true)(x true false)
?
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