xorf | Xor filters - efficient probabilistic hashsets | Hashing library

 by   ayazhafiz Rust Version: 0.8.1 License: MIT

kandi X-RAY | xorf Summary

kandi X-RAY | xorf Summary

xorf is a Rust library typically used in Security, Hashing applications. xorf has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This repository hosts a Rust library implementing xor filters -- data structures for fast approximation of set membership using little memory. Probabilistic filters like xor filters are useful when it's okay to have false positives sometimes, but it's important to be space and time efficient. In other words, they trade off accuracy for efficiency as compared to general-purpose hashsets. Filters like xor filter are often used in conjunction with larger hash-based data structures, with the filter doing a "first pass" of the work to avoid using a more expensive resource unnecessarily. For example, filters like xor filters can be used to reduce disk writes in a cache or identify malicious URLs in a browser. Xor filters are faster and smaller than Bloom and Cuckoo filters. Xor filters incur a relative time penalty in construction, but are very fast in lookups; the expectation is that construction of a filter is amortized after many queries. Daniel Lemire's go implementation provides a useful summary of xor filters' benefits and listing of other xor filter libraries.
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            kandi-support Support

              xorf has a low active ecosystem.
              It has 86 star(s) with 17 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 3 open issues and 9 have been closed. On average issues are closed in 58 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of xorf is 0.8.1

            kandi-Quality Quality

              xorf has no bugs reported.

            kandi-Security Security

              xorf has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              xorf is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              xorf releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            xorf Key Features

            No Key Features are available at this moment for xorf.

            xorf Examples and Code Snippets

            xorf,Usage,Features
            Rustdot img1Lines of Code : 6dot img1License : Permissive (MIT)
            copy iconCopy
            [dependencies]
            xorf = { version = "M.m.p", features = ["nightly"] }
            
            [dependencies]
            xorf = { version = "M.m.p", features = ["serde"] }
            
            [dependencies]
            xorf = { version = "M.m.p", default-features = false }
              
            xorf,Installation
            Rustdot img2Lines of Code : 2dot img2License : Permissive (MIT)
            copy iconCopy
            [dependencies]
            xorf = "M.m.p" # use a desired version
              
            xorf,Development
            Rustdot img3Lines of Code : 2dot img3License : Permissive (MIT)
            copy iconCopy
            scripts/check lf     # validates lint and format
            scripts/check test   # tests source code
              

            Community Discussions

            Trending Discussions on xorf

            QUESTION

            Express XOR in SKI combinators
            Asked 2018-May-01 at 01:35

            I am trying to solve sure but can you SKI on codewars. It is about to express lambda in SKI combinators. Source is at https://repl.it/@delta4d/SKI.

            After some researching, especially the Combinatory Logic, I am able to solve all the cases except xor.

            I first translates xor into

            ...

            ANSWER

            Answered 2018-Apr-30 at 12:44

            The problem comes from the double use of x in λxy.y (x false true) x. It's forced to have two types simultaneously. Since y uses x, y must return something of let's say type a. Now this means that x false true is also of type a. So something of type a must be (b -> b -> a) (for some b). But that's impossible, since that means a must contain itself.

            It's worth noting that your solution is correct wrt. SK, just not Haskell's type system. So to fix we need to not use x twice with different types. So why not make them the same type with λxy.y(x false true)(x true false)?

            Source https://stackoverflow.com/questions/50095962

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install xorf

            Add a dependency to xorf in Cargo.toml:. Available versions are listed on crates and the in repository's releases.

            Support

            Contributions are warmly welcomed. No contribution is too small, and all are appreciated.
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            https://github.com/ayazhafiz/xorf.git

          • CLI

            gh repo clone ayazhafiz/xorf

          • sshUrl

            git@github.com:ayazhafiz/xorf.git

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