crush | command line shell | Interpreter library

 by   liljencrantz Rust Version: Current License: MIT

kandi X-RAY | crush Summary

kandi X-RAY | crush Summary

crush is a Rust library typically used in Utilities, Interpreter applications. crush has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Crush is an attempt to make a traditional command line shell that is also a modern programming language. It has the features one would expect from a modern programming language like a type system, closures and lexical scoping, but with a syntax geared toward both batch and interactive shell usage.
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            kandi-support Support

              crush has a medium active ecosystem.
              It has 1818 star(s) with 39 fork(s). There are 24 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 18 open issues and 11 have been closed. On average issues are closed in 62 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of crush is current.

            kandi-Quality Quality

              crush has no bugs reported.

            kandi-Security Security

              crush has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              crush is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              crush releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            crush Key Features

            No Key Features are available at this moment for crush.

            crush Examples and Code Snippets

            Crush a cell .
            javadot img1Lines of Code : 9dot img1License : Non-SPDX
            copy iconCopy
            void handleCrush(Cell c, CellPool pool, Cell[][] cellMatrix) {
                if (this.positionY >= c.positionY) {
                  this.crush(pool, cellMatrix);
                  c.crush(pool, cellMatrix);
                } else {
                  c.crush(pool, cellMatrix);
                  this.crush(pool, cellM  

            Community Discussions

            QUESTION

            Find all words that match and get the number of them
            Asked 2021-Jun-15 at 17:18

            My code should print the number of all the words replaced from Z's to Y's, using a while loop.

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:18

            Use sum and count with list comprehension

            Source https://stackoverflow.com/questions/67990710

            QUESTION

            Git commands in git bash requiring credentials freeze, and login popup does not show
            Asked 2021-Jun-10 at 05:13

            Windows 7 PC

            • Installed Git (includes Git Bash console)
            • Opened console and typed command to clone a Git repo.
            • Got a warning to install .Net Framework, but wanted to install that later, so hit cancel and got the old school default username and password separate login popups (NOT the new Git Credentials popup)
            • typed my user and password into the old school popups and it logged in and then properly cloned the repo to my local workspace
            • Installed .NetFramework and restarted computer as necessary
            • Opened Git Bash, tried to run a command that requires git login (git pull, git push, etc) and the command console freezes at that point. I would expect the new Git Credentials Manager popup to come up so I can login, but it never comes up. Neither does the old school login popup. Therefore, I cannot log in to Git, and so all actions requiring login cannot proceed.

            I tried:

            • restarting computer
            • uninstalling and reinstalling git
            • repairing .netframework
            • looking for saved credentials (couldn't find anything). there should not be any saved credentials anyway since I used the old school authentication login which doesn't save them, AFAIK.

            I've gone through all this before on another computer and didn't run into this. That time, after installing .netframework, when I tried a git command requiring login, the new Git Credentials Manager popped up (after which it then saved my credentials)

            Searched Google and Stack Overflow / exchange etc and could not find this exact issue anywhere. Most questions were about how to stop the popup from showing and to save credentials, which is exactly the opposite issue of mine.

            Note: Windows 7 should not be the issue because I've done this on a Win 7 PC without issue.

            So, how do I Force a Git login popup to show up (either the new one or the old school one)?

            EDIT: Tried a variety of things, still can't get the new token authentication popup, but here's what I tried and where I'm at now:

            I decided to look in Windows Programs area, and did not find Git Credential Manager, which is odd because it's included with Git and I just installed Git. Anyway, downloaded and installed the standalone git credentials manager.

            Then tried these: git config --global credential.helper manager-core git config --global credential.helperselector.selected manager-core

            and got: warning: credential.helper has multiple values (and I forget the other error lines but it said something about using --replace-all to fix)

            so I did: git config --global --replace-all credential.helper manager-core

            and that gave no errors and seemed to do something

            then I ran: git config --global credential.helperselector.selected manager-core

            Then I did git push, and it automatically pushed without asking my credentials at all, which is really confusing.

            So, I have still failed to get the new Token Authentication popup. This is incredibly frustrating...

            EDIT 2: The plight continues Since Git Push worked without asking for creds, I realized the popup I want may not be showing up because Windows Credential Manager may already have the creds I typed previously. So I went to Windows Credential Manager, found them, and removed them from the vault.

            Then I tried git pull and I finally got the NEW Token Authentication popup. My hopes skyrocketed. I entered my Token. Then my hopes were crushed when the terminal gave the following errors:

            fatal: An error occurred while sending the request. fatal: The request was aborted: Could not create SSL/TLS secure channel.

            EDIT 3 - SOLVED! Followed the instructions in the accepted answer below. Once I got the new token cred manager coming back up, I had to enable TLS 1.2 on my Windows 7 PC. I had the newest .net framework version, but I had to edit the registry to add a key to enable TLS 1.2. After backing up my registry, I then followed these instructions: https://help.runbox.com/enabling-tls-1-2-on-windows-7/

            After restarting my computer, the TLS 1.2 was enabled, and when I got the token cred manager popup, I entered my token, it was accepted, and the popup went away. Now my creds are saved and using the new more secure token authentication.

            ...

            ANSWER

            Answered 2021-Jun-10 at 05:13

            I would expect the new Git Credentials Manager popup to come up so I can login, but it never comes up.

            For that, you would need at least to instruct Git to use it:

            Source https://stackoverflow.com/questions/67895635

            QUESTION

            How to handle if (element.display) in selenium
            Asked 2021-Jun-09 at 13:12

            I want to check if element is displayed - if true than execute some code. If not than execute some other code.

            When I am trying to do that if the condition is false and the element does not exist then the test crush. Its not continue to the else or else if.

            I want to know how to handle it.

            In the next code I want to check if arrow side is up or down, if its up do something else do something different.

            ...

            ANSWER

            Answered 2021-Jun-09 at 13:12

            Two ways :

            1. List

            You can get that element in a list using (findElements) and then if size is > 0 then execute your desire code or else if it is 0 then do the else part.

            Code :

            Source https://stackoverflow.com/questions/67904799

            QUESTION

            Most effective way to fold polynomial parse tree
            Asked 2021-Jun-07 at 19:34

            I am working on a symbolic algebra system. I'm currently looking at how to carry out polynomial addition/multiplication from a binary parse tree. I will later consider this to be a general ring.

            Parsing is not relevant here -- this intended to be the output of parsing. The parse tree that is formed. If something could be improved here, I'm certainly happy to learn about that too.

            I 'feel' that this tree structure could be folded/crushed, yet I'm not too clear on how to go about it. I believe I can hack something together, but as I'm still learning Haskell, I wanted to learn what the more advanced users would do.

            Below is relevant code background.

            My two relevant data declarations are:

            ...

            ANSWER

            Answered 2021-May-03 at 15:35

            "Fold" has two related but distinct meanings in common parlance.

            1. Fold as in Foldable. Viewing the datatype as a container, Foldable gives you access to the container's elements while throwing away any information about the shape of the container itself. (This is also the sense in which lens's Fold uses the term.) Not every datatype is Foldable — only those which can be viewed as a container.
            2. "Fold" can also mean "catamorphism", which is a technique for writing higher-order functions which reduce a structure to a summary value. Every datatype has a corresponding catamorphism, but the signature of the catamorphism depends on the datatype.

            The two meanings of "fold" happen to coincide when the datatype you're talking about is [] (which partly explains the confusion over the two meanings), but in general they don't. Your Tree happens to be a suitable candidate for either type of fold, and from your question I can't quite tell which one you're after, so I'll show you how to do both.

            The easiest way to write an instance of Foldable is to turn on DeriveFoldable.

            Source https://stackoverflow.com/questions/67368081

            QUESTION

            Syntax Error: Unexpected token. problem with empty tag
            Asked 2021-Jun-06 at 23:14

            My code runing good on desktop but on my laptop it is crushing. Sorry for stupid question but where is a problem?

            ...

            ANSWER

            Answered 2021-Jun-06 at 23:14

            Your code is a little nonsensical and incomplete but maybe something like this:

            There were syntax errors like herf instead of href and some missing closing tags.

            Source https://stackoverflow.com/questions/67864317

            QUESTION

            I cant look for a value in a object array, it returns me error
            Asked 2021-May-29 at 17:22

            Hello everyone I'm doing this music player and this is the song loader but the problem is that when I try to assing the value to song constant with lookSongbyId function it returns me an error idk why

            ...

            ANSWER

            Answered 2021-May-29 at 17:18

            You can simplify your function to just use find which will return the matched song.

            Source https://stackoverflow.com/questions/67753986

            QUESTION

            Is there a reason why the strcmp function isn't working nor the else?
            Asked 2021-May-26 at 23:52

            I have the code below and it isn't working with respects to the last two conditional statements: else-if and else. Using the strcmp, I would think that if both player1 and player2 had the same string, that this else-if body would be enabled, but it does not. Instead it loops again and asked to enter scissors, rocks or paper. In addition, entering something like hamburger and rock, does not activate the else part and instead asked for scissors, rocks and paper entry.

            update1: According to the debugger and as far as I can see, it appears to be because one of the else-if earlier was exhausted. If I enter paper for player1 and paper for player2 then it enters in this one: 'else if(strcmp(player1, "paper") == 0)'. But it does not printf anything because there isn't another paper in its body. Then after, it loops again in the while loop (asking for inputs again: rock, paper or scissors), never reaching this: 'else if(strcmp(player1,player2) == 0)'

            update2: If I place the 'else if(strcmp(player1,player2) == 0) at the very top, starting it off with an 'if' statement. The program works. However, the else is still not working and its because of similar situation. Placing it at the top will not work, because it is suppose to encompass any other wording that is not scissors, rocks or paper.

            ...

            ANSWER

            Answered 2021-May-26 at 23:52

            I would change it a bit to make if-else a bit clearer. Using switch you can clearly see the winning logic.

            Source https://stackoverflow.com/questions/67713461

            QUESTION

            Is there a reason for why it doesn't enter some of the else-if statements?
            Asked 2021-May-26 at 19:06

            Some of the else-if statements aren't working like the 'else if(strcmp(player1,player2) == 0) ' or the 'else if(strcmp(player1, "scissors") == 0)'. Could it be their subsequent 'if' statements? They are replicas (with some modification) from the other else if statements that do work. They are nearly identical so I don't get why they wouldn't work.

            ...

            ANSWER

            Answered 2021-May-26 at 18:53

            Your if-else statements do not make a sense. For example consider these if-else statements

            Source https://stackoverflow.com/questions/67710987

            QUESTION

            How to stretch the middle view vertically in a ConstraintLayout
            Asked 2021-May-23 at 20:54

            I have two TextInputLayouts as a header and a footer in my XML layout, and a RecyclerView in between. What I wanna achieve is to set the height of the RecyclerView to fill the area between the other two.

            I've tried setting constrains of the RecyclerView based on the header and footer and setting layout_height to 0dp, but it seems there's a problem. The RecyclerView gets crushed to 0 pixels in runtime.

            Here's my code:

            ...

            ANSWER

            Answered 2021-May-23 at 20:54

            Parent ConstraintLayout height should be match_parent instead of wrap_content.

            Source https://stackoverflow.com/questions/67663868

            QUESTION

            How to properly end a if else statement in Python (Treasure Hunt Game Question)?
            Asked 2021-May-16 at 11:08
            print('Welcome to the Treasure Hunt!')
            print('Your goal is to find the treasure.')
            direction = input('You are at a crossroad. Where do you want to go? Type "left" or "right". \n').lower()
            
            if direction == "left":
                wait_or_swim = input('You have come to a lake. There is an island in middle of the lake. Type "wait" to wait for a boat or "swim" to swim accross the lake? \n').lower()
            elif direction == "right":
                print('You are crushed by a truck. Game Over!')
            else:
                print('You chose an option that doesn\'t exist.')
            
                
            if wait_or_swim == "wait":
                color = input('You arrived at the island unharmed. There is a house with three doors. One red, one blue and one green. Which one will you choose? \n').lower()
            elif wait_or_swim == "swim":
                print('You have been eaten by a shark.\nGame Over.')
            else:
                print('You chose an option that does not exist. ')
            
                
            if color == "red":
                print('You fell into a room full of fire.\nGame Over.')
                
            elif color == "green": 
                print('Congratulations, you have found the treasure!')
                
            elif color == "blue":
                print('You fell into a ditch.\nGame Over.')
                    
            else:
                print('You chose a door that does not exist.\nGame Over.')
            
            ...

            ANSWER

            Answered 2021-May-16 at 11:06

            Insert the if...else statement after the right option. By typing the wrong option, you are printing a statement and then it reads the next code where wait_or_swim is not defined.

            Source https://stackoverflow.com/questions/67555839

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install crush

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone liljencrantz/crush

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