unbox | progress command line utility to unpack various types | Compression library

 by   mitsuhiko Rust Version: Current License: No License

kandi X-RAY | unbox Summary

kandi X-RAY | unbox Summary

unbox is a Rust library typically used in Utilities, Compression, Numpy applications. unbox has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

A work in progress command line utility to unpack various types of archives quickly.
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            kandi-support Support

              unbox has a low active ecosystem.
              It has 134 star(s) with 8 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 1 have been closed. On average issues are closed in 1 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of unbox is current.

            kandi-Quality Quality

              unbox has no bugs reported.

            kandi-Security Security

              unbox has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              unbox does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              unbox releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            unbox Key Features

            No Key Features are available at this moment for unbox.

            unbox Examples and Code Snippets

            Unboxing int array .
            javadot img1Lines of Code : 3dot img1License : Permissive (MIT License)
            copy iconCopy
            public static int[] unboxIntegerArray(Integer[] array) {
                    return ArrayUtils.toPrimitive(array);
                }  

            Community Discussions

            QUESTION

            Pattern binding: why are recursive patterns allowed?
            Asked 2021-May-29 at 10:51
            Prelude> let (Just x) = Just (x - 1) in x
            *** Exception: <>
            
            ...

            ANSWER

            Answered 2021-May-28 at 07:15

            Data can be just as lazy as functions in Haskell. As a result there are certainly use cases for recursive bindings. For example, consider this definition of fix:

            Source https://stackoverflow.com/questions/67733530

            QUESTION

            No-copy way of creating an NDArray from an unboxed slice?
            Asked 2021-Apr-29 at 20:36

            I am writing a Rust plugin for an Electron app using Neon. The Javascript code passes me an image -- a 3D array of rows of columns of 4-element pixels (RGBA). Because the # of rows and # of columns are not known at compile time, I would like to create an NDArray of the passed image (probably a 2D array of pixels rather than a 3D array of bytes).

            However, I don't want to copy the image. It's megabytes in size, and this is happening many times per second, so copying would be inefficient.

            I think I see how it could be done if the image were Boxed -- something like this:

            ...

            ANSWER

            Answered 2021-Apr-29 at 20:36

            Assuming that you're getting a byte slice from Javascript, you should be able to use ndarray::ArrayView to create a borrowed view into the data:

            https://docs.rs/ndarray/0.15.1/ndarray/type.ArrayView.html#impl

            Source https://stackoverflow.com/questions/67324647

            QUESTION

            Debugging visualizer which targets DateTime doesn't transfer the value
            Asked 2021-Apr-26 at 21:02

            I've written a Visual Studio debugging visualizer which targets DateTime (repo). My issue is that the debugger side only passes the target value to the debuggee side if the target expression is of object, not of DateTime (issue).

            I've published a GH repo containing an MCVE that reproduces the problem. The debugger side looks like this:

            ...

            ANSWER

            Answered 2021-Apr-23 at 12:36

            I can't find a proper solution. It could be just a bug introduced in one of the latest versions and nobody has come across this problem with value types so far. Actually, I tried

            Source https://stackoverflow.com/questions/67152796

            QUESTION

            Boxing/unboxing costs and do boxed objects have copy on write?
            Asked 2021-Apr-24 at 08:34

            From what I understand, Java has boxed (heap) and unboxed (stack) variables, and if I assign a boxed type to an unboxed type or vice-versa there is a(n) (un)boxing cost involved.

            Is unboxing cheaper than allocating a new boxed object? And do boxed objects support COW if used readonly?

            ...

            ANSWER

            Answered 2021-Apr-24 at 08:34

            Wrapping types are not on the heap because they box a primitive type but because they are objects. Primitive types can live on the stack, as local variables, or on the heap, as member variables.

            What happens in your example is:

            • Long l2 = cls.myLong; assigns the reference of the object behind class.myLong to l2, or in other words: l2 now references the same object as class.myLong.
            • l2 += 5; unboxes the object referenced by l2, adds 5 to the value, wraps the result in a new instance of Long and assigns the reference of that new instance to l2, or in other words: l2 now references a new object, which wraps the result.

            Imagine this example code:

            Source https://stackoverflow.com/questions/67224207

            QUESTION

            Overloaded methods for java certification exam
            Asked 2021-Apr-18 at 15:45

            I am preparing for Java certification exam and one thing that I do not understand is below:

            ...

            ANSWER

            Answered 2021-Apr-09 at 15:19

            If you remove the method add(int a, long... b) you will find that your code won't compile because the remaining method add(int a, Long b) cannot be called with add(1, 2) because 2 is an int and a primitive int cannot be boxed into a Long. Likewise, the statement Long a = 2; is invalid. Therefore the only matching candidate is add(int a, long... b).

            Source https://stackoverflow.com/questions/67023762

            QUESTION

            Changing the value in the Generics object in Java
            Asked 2021-Apr-08 at 15:20

            I recently started to learn about generics in Java, and I understand the basic concepts of generics. However, one thing I don't understand is that I don't know why the following method doesn't work:

            ...

            ANSWER

            Answered 2021-Apr-08 at 15:20

            I agree with the first two comments. Also, it's not a generics problem, it's just that the method doesn't work because it's not supposed to work because the boxing assumption you concluded doesn't apply here.

            Autoboxing and Unboxing are supplied for some of the Number types but not all. See table below: https://docs.oracle.com/javase/tutorial/java/data/autoboxing.html

            So while this works the way you expect (because both types are in the supported table):

            Source https://stackoverflow.com/questions/66996797

            QUESTION

            Write 4 : 'x&{.&.;: y' tacitly
            Asked 2021-Apr-06 at 20:50

            Conor Hoekstra recently solved a Leetcode problem in APL https://youtu.be/QtvvQ7MdwKY The problem is to take the first x words from a character string y

            In J, using &. (Under) and ;: (Words) I can come up with a nice explicit one liner

            ...

            ANSWER

            Answered 2021-Apr-06 at 06:24

            mainly because I believe x needs to be bound to {. during the creation of the verb.

            If creating a verb with an input is the key, shouldn't you use an adverb?

            Source https://stackoverflow.com/questions/66963366

            QUESTION

            Hiding associated type shared by two traits
            Asked 2021-Apr-06 at 03:53

            I have traits for senders and receivers of a specific message type.

            ...

            ANSWER

            Answered 2021-Apr-05 at 11:58

            I don't quite know if this is what you are looking for, but you could make the SendAndReceive generic on the sender and receiver:

            Source https://stackoverflow.com/questions/66951061

            QUESTION

            Is it better to assign Boolean.TRUE/Boolean.FALSE or true/false to a boolean primitive variable?
            Asked 2021-Apr-03 at 19:24

            While doing some code reviews I stumbled upon this:

            People usually assign Boolean.TRUE or Boolean.FALSE value to a boxed boolean variable but use true/false for primitive variables. What is the best way for this?

            According to an architect I worked with - he said that every time you assign true/false to a variable a new instance of Boolean is created. We can skip that if we assign the boolean variable to the static instances - Boolean.FALSE/Boolean.TRUE. If the variable is primitive an auto-unboxing is done.

            Is the auto-unboxing faster than the initialization of a boolean variable? The differences are not big and I think this is just a micro-optimisation of the code but I wanted to learn more about this.

            ...

            ANSWER

            Answered 2021-Apr-01 at 12:11

            if you have a primitive boolean variable, then assign true or false to avoid performing the unboxing.

            if you have a wrapper Boolean variable, then use Boolean.TRUE or Boolean.FALSE to avoid performing boxing and/or instantiation of a new object.

            Source https://stackoverflow.com/questions/66904071

            QUESTION

            How to use Unboxed Mutable vector
            Asked 2021-Apr-02 at 18:28
            import           Control.Monad.ST
            import           Data.STRef
            
            import qualified Data.Vector.Unboxed         as V
            import qualified Data.Vector.Unboxed.Mutable as MV
            
            -- what the heck is that s?
            new0 :: (MV.Unbox a, Num a) => ST s (MV.STVector s a)
            new0 = do
              v <- MV.new 10
              MV.write v 1 10
              MV.write v 2 10
              return v
            
            new1 :: (MV.Unbox a) => IO (MV.IOVector a)
            new1 = MV.new 10
            
            new2 :: (MV.Unbox a, Num a) => IO (MV.STVector RealWorld a)
            new2 = do
              v <- MV.new 10
              MV.write v 1 10
              return v
            
            ...

            ANSWER

            Answered 2021-Apr-01 at 12:26

            The ST monad is for when you want to take some immutable data, make it temporarily mutable, do something with it, and make it immutable again. In particular, there is no way to return a mutable result from the ST monad (by design).

            In particular, STVector is mutable, so it can never leave the ST monad. So there is no way to "print out" new0. You would have to convert it to something immutable to return it out of the ST monad.

            If you're wanting to mutate something, print it out, mutate it a bit more, print it out, etc., you probably want the IO monad. The ST monad is for making something temporarily mutable, to eventually produce an ordinary immeduate result.

            Regarding the s type variable: It's a slight hack that enforces the property that mutable data cannot leave ST. The runST function requires an action that works for every possible choice of s. This means it's impossible to return anything that contains s. Since all the mutable stuff has s in its type signature, this enforces our guarantee.

            Source https://stackoverflow.com/questions/66903260

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install unbox

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            Note on cabinet files: this uses the cab Rust library which currently only supports deflate cabs. This means it's unable to extract cabs which use the LZX or Quantum compression formats.
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            https://github.com/mitsuhiko/unbox.git

          • CLI

            gh repo clone mitsuhiko/unbox

          • sshUrl

            git@github.com:mitsuhiko/unbox.git

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