trees | project provides trees data structure | Dataset library
kandi X-RAY | trees Summary
kandi X-RAY | trees Summary
This project provides trees data structure serving for general purpose.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of trees
trees Key Features
trees Examples and Code Snippets
Community Discussions
Trending Discussions on trees
QUESTION
I have a question about how rebasing works in git, in part because whenever I ask other devs questions about it I get vague, abstract, high level "architect-y speak" that doesn't make a whole lot of sense to me.
It sounds as if rebasing "replays" commits, one after another (so sequentially) from the source branch over the changes in my working branch, is this the case? So if I have a feature branch, say, feature/xyz-123
that was cut from develop
originally, and then I rebase from origin/develop
, then it replays all the commits made to develop
since I branched off of it. Furthermore, it does so, one develop
commit at a time, until all the changes have been "replayed" into my feature branch, yes?
If anything I have said above is incorrect or misled, please begin by correcting me! But assuming I'm more or less correct, I'm not seeing how this is any different than merging in changes from develop
by doing a git merge develop
. Don't both methods result with all the latest changes from develop
making their way into feature/xyz-123
?
I'm sure this is not the case but I'm just not seeing the forest through the trees here. If someone could give a concrete example (with perhaps some mock commits and git command line invocations) I might be able to understand the difference in how rebase works versus a merge. Thanks in advance!
...ANSWER
Answered 2021-Jun-15 at 13:22" It sounds as if rebasing "replays" commits, one after another (so sequentially) from the source branch over the changes in my working branch, is this the case? "
Yes.
" Furthermore, it does so, one develop commit at a time, until all the changes have been "replayed" into my feature branch, yes? "
No, it's the contrary. If you rebase your branch on origin/develop
, all your branch's commits are to be replayed on top of origin/develop
, not the other way around.
Finally, the difference between merge and rebase scenarios has been described in details everywhere, including on this site, but very broadly the merge workflow will add a merge commit to history. For that last part, take a look here for a start.
QUESTION
I am trying to follow this tutorial here - https://juliasilge.com/blog/xgboost-tune-volleyball/
I am using it on the most recent Tidy Tuesday dataset about great lakes fishing - trying to predict agency based on many other values.
ALL of the code below works except the final row where I get the following error:
...ANSWER
Answered 2021-Jun-15 at 04:08If we look at the documentation of last_fit() We see that split
must be
An rsplit object created from `rsample::initial_split().
You accidentally passed the cross-validation folds object stock_folds
into split
but you should have passed rsplit
object stock_split
instead
QUESTION
I'm building a web app using Laravel 8 and one thing I tend to struggle with is the complex relationships and accessing the data. I've started reading on hasManyThrough
relationships but I'm not convinced that's the correct way to do it for my scenario.
The app is used by travelling salesmen to check in to a location when they arrive safely.
I have three main tables:
Locations
(where they are visiting),Checkins
(where their check in data is stored, e.g. time),Users
This is where it gets a little complex and where I find myself not being able to see the wood for the trees...
- Locations have many users, users have many locations. Many-to-many pivot table created.
- Locations have many check ins, check ins have many locations. Many-to-many pivot table created.
- Check ins have many users, users have many check ins. Many-to-many pivot table created.
As such they're all created using a belongsToMany
relationship.
Now what I'd like to do is access the user
of the check in
so I can call something similar to on my show.blade.php
:
ANSWER
Answered 2021-Jun-14 at 23:46You said "Check ins have many users", you seem to want the singular user for a check-in, but currently that would result in many users. It sounds like users check-in in a many to one relationship
Also $checkin->created_at
will be by default a carbon object, so you can just go $checkin->created_at->format('jS F Y')
Also don't mix using compact
and with
, stay consistent and use only 1 as they achieve the same thing
Also $checkin->users()->name
won't work, if you use the brackets on syntax is only returns a query builder instance, which you would need to call get on like $checkin->users()->get()
, or you could use $checkin->users
which will fetch them anyway. You may want to look into using with('relation')
on query builder instances to stop N+1 queries if you want to dive a little deeper. Lastly $checkin->users()->get()->name
also won't work as your user relation is many to many which returns a collection, which again points to you should have a belongsTo relationship called user
without a pivot table
QUESTION
Can I find out in Git2-rs / libgit2 about the status of a file like added/removed/modified from the commit log? I've looked at the documentation but only find Diff Trees.
...ANSWER
Answered 2021-Jun-14 at 08:08To my knowledge, there's no direct access to the status of a specific path but you can use the statuses
function of a repository to iterate over all the statuses it knows and look at the path of each StatusEntry
.
To make it more efficient if you have several paths for which you'd like to know the status, you can do the iteration, build a map from paths to statuses, then query this map for every path you're interested in.
QUESTION
I made a lisp code that transforms a list of numbers into a tree. The rules of the tree are that the value of the left child node should always be smaller than the value of its parent node and the value of the right child node should always be higher than the value of its parent node.
Here is my lisp code:
...ANSWER
Answered 2021-Jun-13 at 15:55You are modifying list
but not returning it.
Here is what you need to do:
QUESTION
I'm working on this assignment and I can't seem to stop this read access violation error. I am new to C++ and I think part of my issue is using pointers when they aren't necessary (I think), but I've also looked at this code and traced through it so many times with the debugger that I think I'm missing something obvious.
The assignment is to implement a Huffman encoder. To do this I have to create a HuffmanTree class and a HuffmanProcedure class, and I am provided with a (mostly) complete Heap class (minheap).
The HuffmanProcedure class has to use the Heap class to store and create HuffmanTrees until I have a Huffman code for every single lowercase letter.
When running the code, I get a read access violation error in the helper I wrote for my Tree destructor, treeRemovalHelper
.
The specific error I get (using Visual Studio 2019 targeting C++11):
Exception thrown: read access violation. root was 0xDDDDDDDD
Here's where the error is occurring:
...ANSWER
Answered 2021-Jan-27 at 21:41I found your problem: After you delete the root, remember to set it to nullptr.
QUESTION
I struggle with very strange behaviour while trying to compare two ints but first things first. Here is my method inside the class:
...ANSWER
Answered 2021-Jun-12 at 07:01"I need to return every 3rd element in a tree..." this description screams for the modulo %
operator.
If you want to enter an if-condition on every 3rd iteration then you can check this with the following condition: counter % 3 == 0
. You don't need to subtract anything at all.
How does %
work?
Put simply: The modulo operator returns the result of a division.
Example:
QUESTION
I have trained a churn tidymodel with customer data (more than 200 columns). Got a fairly good metrics using xgbboost but the issue is when tryng to predict on new data.
Predict function asks for target variable (churn) and I am a bit confused as this variable is not supposed to be present on real scenario data as this is the variable I want to predict.
sample code below, maybe I missed the point on procedure. Some questions arised:
should I execute prep() at the end of recipe?
should I execute recipe on my new data prior to predict?
why removing lines from recipe regarding target variable makes predict work?
why is asking for my target variable?
...
ANSWER
Answered 2021-Jun-10 at 19:13You are getting this error because of recipes::step_string2factor(churn)
This step works fine when you are training the data. But when it is time to apply the same transformation to the training set, then step_string2factor()
complains because it is asked to turn churn
from a string to a factor but the dataset doesn't include the churn
variable. You can deal with this in two ways.
skip = FALSE
in step_string2factor()
(less favorable)
By setting skip = FALSE
in step_string2factor()
you are telling the step o only be applied to when prepping/training the recipe. This is not favorable as this approach can produce errors in certain resampling scenarios using {tune} when the response is expected to be a factor instead of a string.
QUESTION
How to create a list with the y-axis labels of a TreeExplainer
shap chart?
Hello,
I was able to generate a chart that sorts my variables by order of importance on the y-axis. It is an impotant solution to visualize in graph form, but now I need to extract the list of ordered variables as they are on the y-axis of the graph. Does anyone know how to do this? I put here an example picture.
Obs.: Sorry, I was not able to add a minimal reproducible example. I don't know how to paste the Jupyter Notebook cells here, so I've pasted below the link to the code shared via Github.
In this example, the list would be "vB0 , mB1 , vB1, mB2, mB0, vB2".
...ANSWER
Answered 2021-Jun-09 at 16:36TL;DR
QUESTION
I'm solving the example probation problem in Python and had only partial success so far (passed 30 test cases, wrong answer in the 31st). The test cases themselves are not disclosed.
Description.
A network of n nodes connected by n-1 links is given. Find two nodes so that the distance from the fatherst node to the nearest of those two would be minimal. If several answers are possible, any of them will be accepted.
The input is given as a list of pairs of numbers. Each number represents node, pair is the connection between two nodes. The result should be the list of two nodes.
Example 1 in = [[1, 2], [2, 3]] result = [3, 1]
Example 2 in = [[1, 2], [3, 2], [2, 4], [4, 5], [4, 6]] result = [2, 4]
My solution.
The net will always be a tree, not a graph. For the above examples the corresponding trees will be:
example 1
...ANSWER
Answered 2021-Jun-10 at 10:21I've found the basic algorithmic error in my implementation and can demonstrate it with an example.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install trees
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page