dfw | Docker Firewall Framework , written in Rust | Firewall library

 by   pitkley Rust Version: 1.3.0-rc.1 License: Apache-2.0

kandi X-RAY | dfw Summary

kandi X-RAY | dfw Summary

dfw is a Rust library typically used in Security, Firewall, Docker applications. dfw has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Docker Firewall Framework, written in Rust
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            kandi-support Support

              dfw has a low active ecosystem.
              It has 74 star(s) with 8 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 6 open issues and 25 have been closed. On average issues are closed in 68 days. There are 11 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of dfw is 1.3.0-rc.1

            kandi-Quality Quality

              dfw has no bugs reported.

            kandi-Security Security

              dfw has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              dfw is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              dfw releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dfw
            Get all kandi verified functions for this library.

            dfw Key Features

            No Key Features are available at this moment for dfw.

            dfw Examples and Code Snippets

            copy iconCopy
            $ docker run \
                --name "your_container" \
                --network "your_network" \
                --publish 80:8080 \
                --publish 443:8443 \
                ...
            
            [[wider_world_to_container.rules]]
            network = "your_network"
            dst_container = "your_container"
            expose_port = [
                "80  

            Community Discussions

            QUESTION

            Compare two strings and return the difference as 0s and 1s efficiently in Python
            Asked 2021-May-11 at 13:10

            I have a set of strings as student answers for a test and the answer key.

            ...

            ANSWER

            Answered 2021-May-11 at 13:10

            The most straightforward (and, in my testing, the fastest) way to do this may just be a list comprehension using zip:

            Source https://stackoverflow.com/questions/67487205

            QUESTION

            How can i access the multibrands.legKey property of this json object
            Asked 2021-Apr-09 at 09:58

            In the given Json array object I want to access the property Multibrands.Legkey can someone help me to access the property Multibrands.Legkey. I tried various methods but I am clueless in doing this.I tried accesing it like this (airLegKeyobject[0].MultiBrands[0].Legkey) But it is giving undefined value?

            ...

            ANSWER

            Answered 2021-Apr-09 at 09:58

            Structure of MultiBrands

            Source https://stackoverflow.com/questions/67017124

            QUESTION

            What does \\n means and how to remove it?
            Asked 2021-Jan-20 at 07:14

            I have a data set and should clean it. One example from my data:

            ...

            ANSWER

            Answered 2021-Jan-20 at 07:14

            '\n' is a new line character whereas '\\n' is an escaped backslash followed by 'n'.

            You can remove it by using gsub :

            Source https://stackoverflow.com/questions/65804641

            QUESTION

            Issue Parsing JSON Data in Python because of Random Value
            Asked 2021-Jan-11 at 00:33

            I'm scraping a website for product reviews. I can successfully get the JSON data, but I'm having an issue with the parsing. The levels of data are like this: payload -> reviews -> 22Y6N61W6TO2 -> customerReviews.

            The data I want is in the "customerReviews level. However, the "6IYETQATGRMP" value will be different when looking at another item.

            I don't want to have to use a different python script for each item to account for this one value. How do I use something like a wild card or something to get the data I'm after?

            I'm using Python 3, requests, and JSON in my script.

            My script looks like this:

            ...

            ANSWER

            Answered 2021-Jan-11 at 00:20

            You have to set a simple variable to have a standard export function.

            Source https://stackoverflow.com/questions/65658938

            QUESTION

            Getting error "not well-formed (invalid token)"
            Asked 2020-Dec-17 at 15:51

            I have an XML file with the following data:

            ...

            ANSWER

            Answered 2020-Dec-17 at 08:53

            It looks like the error occurs in the first 4 lines of your script. As such, the rest of the script is not needed for a minimal reproducible example.

            Having said that, interestingly the example from the documentation yields the same error.

            Finally, I managed to resolve the issue by following the solution provided here.

            Source https://stackoverflow.com/questions/65337068

            QUESTION

            How to get text inside specific tag using tag name with Python
            Asked 2020-Dec-17 at 14:31

            I'm trying to open an XML file and parse through it, looking through its tags and finding the text within each specific tag. If the text within the tag matches a string, I want it remove a part of the string or substitute it with something else.

            My question is, I'm not sure if: start = x.find('start_char').text is actually getting the text inside "start_char" tag and saving it to the "start" variable. (Does "x.find('tag_name').text actually get the text inside the tag?)

            The XML file has the following data:

            ...

            ANSWER

            Answered 2020-Dec-17 at 14:31

            Code start = x.find('start_char').text will function in cases when filter element has start_char child, otherwise it will throw an error AttributeError: 'NoneType' object has no attribute 'text'.

            This can be avoided e.g. using following approach:

            Source https://stackoverflow.com/questions/65340306

            QUESTION

            Why am I unable to download https from server Peer's Certificate issuer is not recognized. issuer: CN=Cisco Umbrella Secondary SubCA
            Asked 2020-Dec-15 at 18:01

            On a client I'm able to access a website but not from a server, there I get this:

            ...

            ANSWER

            Answered 2020-Dec-15 at 18:01

            Turns out the problem was a "man in the middle" firewall. Normally it would say the issuer for that URL is "Oracle" but suspiciously it says "Cisco". My corporate firewall is intercepting calls and redirecting them to add a tag before finally allowing them to work (which they do). Or it maybe intercepting them to show a "blocked/malware" page.

            It was working from my local computer because it was "company issued" and they had manually installed the cisco CA which apparently isn't a common, or standard browser accepted one.

            Fix for me was to download the "umbrella" CA from here:

            https://support.opendns.com/hc/en-us/articles/227987007-Block-Page-Errors-Installing-the-Cisco-Umbrella-Root-CA#CERT

            and use that instead on the server:

            Source https://stackoverflow.com/questions/65311009

            QUESTION

            How to do time series backward resampling e.g. 5 business days starting on the last data date?
            Asked 2020-Nov-26 at 07:37

            I would like to compute weekly returns but starting from the end date backwards. This is my initial attempt to implement it using pandas:

            ...

            ANSWER

            Answered 2020-Nov-26 at 07:37

            So what you're looking for are anchored offsets, i.e. resampling the DataFrame on a weekly basis, starting on the same weekday that your last index is on. In your case, 2020-10-13 is a Tuesday, i.e. you want to use the rule W-TUE. I'd suggest using a lookup dictionary to translate the .weekday() number (e.g. Tuesday == 1) into the respective rule. Then you only need to apply your function over the .resample():

            Source https://stackoverflow.com/questions/64934798

            QUESTION

            While loop not working when working with Pandas dataframe
            Asked 2020-Nov-25 at 15:10

            I am working with the following dataframe dfW(it is a sample from a much larger dataset):

            ...

            ANSWER

            Answered 2020-Nov-25 at 15:10

            QUESTION

            Parsing and looking for something specific
            Asked 2020-Nov-23 at 04:38

            I need to parse through and look for a specific id. In the code below I need to be able to pull out the id number. It looks like this "itemIds":["918e337d-82ae-4e91-bdc3-16ad06572e21". I need to be able to pull the number "918e337d-82ae-4e91-bdc3-16ad06572e21". I have been having trouble understanding this concept. If you could send how or the actual code to do it . That would be very much appreciated.

            ...

            ANSWER

            Answered 2020-Nov-23 at 04:38

            First you need to determine which prop will you get the value of? And then try this, in this case I will get "itemIds" so my findProp function will take 2 parameters:

            Source https://stackoverflow.com/questions/64961710

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install dfw

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/pitkley/dfw.git

          • CLI

            gh repo clone pitkley/dfw

          • sshUrl

            git@github.com:pitkley/dfw.git

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