RustPython | A Python interpreter written in Rust | Interpreter library

by shinglyu Rust Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | RustPython Summary

RustPython is a Rust library typically used in Utilities, Interpreter, Numpy applications. RustPython has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A Python interpreter written in Rust

Support

Quality

Security

License

Reuse

Support

RustPython has a low active ecosystem.

It has 89 star(s) with 3 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

There are 18 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of RustPython is current.

Quality

RustPython has no bugs reported.

Security

RustPython has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

RustPython is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

RustPython releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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RustPython Key Features

No Key Features are available at this moment for RustPython.

RustPython Examples and Code Snippets

No Code Snippets are available at this moment for RustPython.

Community Discussions

Trending Discussions on RustPython

How can I store a `regex::Match` object in a struct without lifetime parameter?

QUESTION

How can I store a `regex::Match` object in a struct without lifetime parameter?

Asked 2019-Jul-11 at 20:16

I'm developing on the re module in rustpython using the regex crate. I want to store the Match object in a struct without lifetimes. Is there a way to do this?

So far, I simply copied the start and end values of the match object into seperate fields, but this feels odd and wrong. There should be a way to store the Match object itself. (Corresponding code lives here: https://github.com/RustPython/RustPython/blob/master/vm/src/stdlib/re.rs#L78)

...

ANSWER

Answered 2019-Jul-11 at 20:16

You can't remove the lifetime of the Match object, because it is defined like so:

Source https://stackoverflow.com/questions/56995304

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install RustPython

You can download it from GitHub.
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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