conc | Conc is a concatenative programming language | Interpreter library
kandi X-RAY | conc Summary
kandi X-RAY | conc Summary
Conc is a concatenative programming language. WIP. Read for more details.
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QUESTION
Context: I have a dataframe with a numeric column Type
recorded for two categories (conc
and uptake
in the example below). With my real data, I need to make a facetted plot as presented below.
Problem: Setting scales = "free_y"
does not "free" the y scale for facets of the same line, indeed, when values of the category conc
are much bigger than the values of the category uptake
, the latter is "crushed".
Question: is it possible to free the y axis scale for facets of the same line using facet_grid()
or change facet-label from facet_wrap()
to match those of facet_grid()
?
Trials and errors: I have tried facet_wrap()
but I did not acheived the neat layout of facet_grid()
while the y-axis scale was good. Maybe there is a way to define facet_wrap()
facet-labels but playing around with switch
(i.e. strip_position
) arguments has not been a success.
I am aware that some SO post are already looking for something similar (see How to position strip labels in facet_wrap like in facet_grid) but maybe (I hope ^^) another, maybe "easier" solution came out since.
...ANSWER
Answered 2022-Mar-30 at 13:24The ggh4x::facet_grid2()
function has an independent
argument that you can use to have free scales within rows and columns too. Disclaimer: I'm the author of ggh4x.
QUESTION
I am working with a mongo database model building using mongoengine. I want to modify DictField
by the result created in another function
ANSWER
Answered 2022-Mar-26 at 19:19Maybe you need something like this:
QUESTION
I am trying to put Several RColorBrewer Palettes that goes from lower tones to darker tones in one ggplot. But so far I've been unsuccessful and I've found that I can only use one.
My data set data
:
ANSWER
Answered 2022-Mar-20 at 20:12You would really have to create your own combined Brewer palette and apply it to the interaction of the two grouping variables (conc
and Treatment
)
QUESTION
So I have sampled a set of lakes at x timepoints throughout the year. I also have deployed loggers etc. in the water and I want to use daily averages from these loggers, at the timepoint of the visit to x days/hours before. Sometimes I also just grab the a sample for the timepoint of the visit.
This is my solution, it works just fine but since I experiment alot with some model assumptions and perform sensitivity analyses it operates unsatisfactory slow.
I seem to have solved most of my R problems with loops and I often encounter more efficient scripts, it would be very interesting to see some more effective alternatives to my code.
Below code just generates some dummy data..
...ANSWER
Answered 2022-Mar-19 at 22:01My guess is that this part using grepl
:
QUESTION
Problem: Given a binary search tree in which the keys are numbers, we'll define the operation 'cumsum' ( shorthand for cumulative sum ) that switches the key of every node in the tree with the sum of all the keys that are smaller or equal to it.
For example,
In this example,
The key 5 in the root is switched to the value 10: the sum of the original key in the root ( which is 5 ) and all smaller keys than it ( which are 2 and 3 ).
The key 3 is switched with the value 5: sum of the original key in this node ( meaning, 3 ) and all the smaller keys than it ( which is 2 ).
The key 12 in the rightmost node is switched with the value 45: sum of the original key in this node ( meaning, 12 ) and all the smaller keys than it ( which are 2,3,5,6,8 and 9 ).
Note that the method needs to be an envelope function that envelopes a recursive function. Also note that the method cumsum does not return a new tree but rather updates the tree itself ( in-place )
My attempt:
...ANSWER
Answered 2022-Jan-02 at 16:50Here's one implementation that doesn't require keeping the extra list; it just adds the numbers up as it goes.
QUESTION
I'm working on this figure and wondering if it's possible to get a mean line (like the black line in the figure) but for each concentration group.
Sorry I can't share the data with you. Ideas?
...ANSWER
Answered 2021-Dec-28 at 16:10You could loop through the different conc
values, and call the dummy boxplot for each of them.
Here is an example using the standard tips dataset:
QUESTION
I'm trying to edit the facet label's text produced by emmean's arrow plot using ggplot2's syntax to override the default.
...ANSWER
Answered 2021-Dec-18 at 20:44You were almost there. (1) You need a named vector (I think), not a list; (2) the names of the list should match the elements of the faceting variable, not the already-labeled values (i.e. the strip labels).
QUESTION
I have recieved a exercice to learn about data types in haskell and I can't figure out how to solve this one.
They got me a data like : data CatLista a = Nil | Unit a| Conc (CatLista a) (CatLista a) deriving Eq
and I need to make the data types become: Nil -> [] , Unit x -> [x] , Conc -> same operator as (++)
So if you run Conc (Unit 9)(Conc (Unit 5) (Unit 3)) == Conc (Conc (Unit 9) (Unit 5))(Conc (Unit 3) Nil)
should give true and Conc (Unit 9)(Unit 3) == Conc (Unit 3) (Unit 9)
should give false.
I already tried instancing the show class like this:
...ANSWER
Answered 2021-Dec-08 at 20:49Two values are not equivalent if these produce the same String
when calling show
on these. The (==) :: Eq a => a -> a -> Bool
function is implemented by the Eq
typeclass. You thus need to implement the instance
of Eq
for your CatLista
yourself.
The default implementation for Eq
, if you use deriving Eq
is that two values are the same if they have the same data constructor, and the parameters are elementwise equivalent by calling (==)
on these.
You thus can implement the instance for Eq
yourself with:
QUESTION
I am attempting to display a linear model for low x values and a non-linear model for higher x values. To do this, I will use DNase as an example:
...ANSWER
Answered 2021-Dec-03 at 17:51You can provide specific data to each geom
. In this case use subset data_1
using range
to only provide the relevant data to each stat_smooth()
call (and the whole frame to geom_point()
QUESTION
I am fitting the same linear model in two different ways, resulting in the same parameter estimates but differing R-squared values. Where does the difference come from? Is this a bug in R? Here is my code:
...ANSWER
Answered 2021-Nov-20 at 01:54StupidWolf gave you the answer. You are estimating two different regression models.
Because your second model specification m2 <- lm(y ~ 0 + X). You are not estimating an intercept and you have a extra variable variable X(intercept).
To get the same R^2 just correct the model
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