vector | highly reliable , observability data pipeline | Analytics library
kandi X-RAY | vector Summary
kandi X-RAY | vector Summary
A high-performance, highly reliable, observability data pipeline.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of vector
vector Key Features
vector Examples and Code Snippets
def softmax(vector):
"""
Implements the softmax function
Parameters:
vector (np.array,list,tuple): A numpy array of shape (1,n)
consisting of real values or a similar list,tuple
Returns:
softmax_vec (np.arr
def __mul__(self, other: float | Vector) -> Vector | Matrix:
"""
implements the matrix-vector multiplication.
implements the matrix-scalar multiplication
"""
if isinstance(other, Vector): # matrix-vector
def relu(vector: list[float]):
"""
Implements the relu function
Parameters:
vector (np.array,list,tuple): A numpy array of shape (1,n)
consisting of real values or a similar list,tuple
Returns:
relu_vec (np
Community Discussions
Trending Discussions on vector
QUESTION
Giving a bit of context. I'm using c++17. I'm using pointer T* data
because this will interop with cuda code. I'm trying write a parallel version (on CPU) of a histogram creator. The sequential version:
ANSWER
Answered 2021-Jun-16 at 00:46The issue you are having has nothing to do with templates. You cannot invoke std::async()
on a member function without binding it to an instance. Wrapping the call in a lambda does the trick.
Here's an example:
QUESTION
I'm learning C++ and have come to a bit of a halt. I'm trying to iterate over a vector with a range-based for loop and update a property on each of the objects that belong to it. The loop is inside of an update function. The first time it fires, it works fine; I can see the property gets updated on each member of the vector. However, the next time the for loop is initiated, it's still updating the original data, as if the previous run did not actually update the source values. Is my range declaration configured correctly? Pointers are still a bit of a mystery to me. In general I'd be very thankful for any help!
...ANSWER
Answered 2021-Jun-15 at 23:19Vector3 position = point.position;
makes a copy of point.position
. The following code then updates this copy, which in turn is thrown away when it goes out of scope at the end of the if
statement.
The solution is simple enough - use a reference instead: Vector3 &position = point.position;
. The rest of the code can be left as-is.
QUESTION
I have this code which prints multiple tables
...ANSWER
Answered 2021-Jun-15 at 20:59So, this is a good opportunity to use purrr::map
. You are half way there by applying code to one dataframe.
You can take the code that you have written above and put it into a function.
QUESTION
so I'm struggling with these things:
I have method that returns istream input and takes istream input as a parameter, sends values to vector and stores them in it. Now, when I've entered 1 value, I'm trying to make a check if vector already contains that value, here is my code to understand it better:
...ANSWER
Answered 2021-Jun-15 at 20:14first of all, you can check count of std::vector to see if given key exists
QUESTION
I have a simple code where I try to define a vector as one of two initializer lists using a ternary operator:
...ANSWER
Answered 2021-Jun-15 at 21:48Because you can't have braces in that context. If you look at cppreference on list initialization, you see that the case inside a ternary operator isn't defined. So it can't be parsed correctly and you get the error you have.
You'd have to use something like this :
QUESTION
I've been attempting to create a node class which mimics a node on a graph. Currently, storage of the predecessor and successor nodes are stored via a node pointer vector: std::vector previous
. The vectors for the predecessor/successor nodes are private variables and are accessible via setters/getters.
Currently, I am dealing with updating the pointer values when adding a new node. My current method to update the predecessor/successor nodes is through this method (the method is the same for successor/previous nodes, just name changes):
...ANSWER
Answered 2021-Jun-15 at 20:20I think this should get you going (edge-cases left to you to figure out, if any):
QUESTION
I am using a method to remove univariate outliers. This method only works if the vector contains outliers.
How is it possible to generalize this method to work also with vectors without outliers. I tried with ifelse
without success.
ANSWER
Answered 2021-Jun-15 at 19:58Negate (!
) instead of using -
which would work even when there are no outliers
QUESTION
I’d be grateful for suggestions as to how to remap letters in strings in a map-specified way.
Suppose, for instance, I want to change all As to Bs, all Bs to Ds, and all Ds to Fs. If I do it like this, it doesn’t do what I want since it applies the transformations successively:
...ANSWER
Answered 2021-Jun-15 at 18:21We could use chartr
in base R
QUESTION
Good day, everyone.
I want to have two separate TensorFlow models (f
and g
) and train both of them on the loss of f(g(x)). However, I want to use them separately, like g(x) or f(e), where e is an embedded vector but received not from g.
For example, the classical way to create the model with embedding looks like this:
...ANSWER
Answered 2021-Jun-15 at 10:53This can be achieved by weight sharing or shared layers. To share layers in different models in keras, you just need to pass the same instance of layer to both of the models.
Example Codes:
QUESTION
I am trying to compute the divergence of a vector field:
...ANSWER
Answered 2021-Jun-15 at 15:26Let me 1. explain the reason behind this observation, and 2. how to fix it.
Reason:One needs to be careful about how the data is oriented when computing the divergence (or the gradient in general), since it is important to compute the gradient along the correct axis to obtain a physically valid result.
np.meshgrid can output the mesh in two ways, depending on how you set the index parameter
Index "xy" : Here, for every y value, we sweep the x-values.Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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