genco | aware quasiquoter for beautiful code generation | Code Quality library

by udoprog Rust Version: 0.17.0 License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | genco Summary

genco is a Rust library typically used in Code Quality applications. genco has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A whitespace-aware quasiquoter for beautiful code generation. Central to genco are the quote! and quote_in! procedural macros which ease the construction of token streams.

Support

Quality

Security

License

Reuse

Support

genco has a low active ecosystem.

It has 111 star(s) with 6 fork(s). There are 4 watchers for this library.

It had no major release in the last 12 months.

There are 3 open issues and 14 have been closed. On average issues are closed in 111 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of genco is 0.17.0

Quality

genco has 0 bugs and 0 code smells.

Security

genco has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

genco code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

genco is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

genco releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

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genco Key Features

No Key Features are available at this moment for genco.

genco Examples and Code Snippets

No Code Snippets are available at this moment for genco.

Community Discussions

Trending Discussions on genco

mpi4py Send characters

How to read Json file and convert it to dataframe

QUESTION

mpi4py Send characters

Asked 2021-Feb-26 at 00:12

I'd like to use the faster Send (not the slower send) method to transmit some characters from one process to another, but haven't been able to get a working solution with mpi4py (restricted to using this language, Python3)

Here's my toy code - if anyone can point out what I'm doing wrong (and how to fix it), I'd be very grateful.

...

ANSWER

Answered 2021-Feb-26 at 00:12

The problem is that your buffer buf in this case is not big enough to fit your message when it tries to receive it as it is of length 0.

The solution here is to use a bytearray as you can initialise it on a fixed size, so your example will be:

Source https://stackoverflow.com/questions/66376707

QUESTION

How to read Json file and convert it to dataframe

Asked 2020-Jul-30 at 14:42

I was trying to read the JSON file and convert to JSON, but I am finding difficulties here as i dont have much knowledge on this.

...

ANSWER

Answered 2020-Jul-30 at 14:42

Your sample is not in the JSON standard(or it is only a sample?). The word "ObjectId" is not a string or number. I think you can try https://www.json.cn to verify your JSON file first. This error is about json not DataFrame.

Source https://stackoverflow.com/questions/63175247

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install genco

You can download it from GitHub.
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.