sssp | S3 Proxy Mesos Framework | Job Orchestrator library
kandi X-RAY | sssp Summary
kandi X-RAY | sssp Summary
JSON routing configuration — mapping prefixes in SSSP to buckets in S3 — can be POST`ed to the root resource (/) as well as added to a configuration file (`conf/s3.json by default). The JSON configuration is a map of prefixes to JSON objects containing a bucket name and AWS access credentials:. The prefixes are always treated as though they started and ended with a slash (though both slashes can be safely omitted from the configuration). Thus, to obtain the S3 object s3://memes.example.com/m/molly/glasses.gif given the above configuration, one would issue GET /gifs/team/m/molly/glasses.gif to SSSP.
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QUESTION
I'm trying to print out the SSSP in a specific order but I'm stucked.
lets say I have 2 array:
node = [0, 1, 2, 3] pred = [-1, 2, 0, 1]
This is the code I've come up with:
...ANSWER
Answered 2022-Mar-18 at 15:41Just move theprintf
node statement to execute after the recursive call.
QUESTION
I tried to run the below OPenACC program on cluster:
...ANSWER
Answered 2022-Mar-09 at 15:53What could be the reason?
In order to be interoperable with g++, pgc++ (aka nvc++) uses the g++ STL and system header files. Since the location of these headers can vary, on installation a configuration file, "localrc", is created to store these locations.
What could be happening here is that on install, a single system install was selected and hence the generated localrc is for the system from which the compilers were installed, not the remote system.
If this is the case, consider re-installing with the "network" option. In this case, the creation of the localrc is delayed until the first compiler invocation with a unique localrc generated for each system.
Another possibility is that creating of the localrc file failed for some unknown reason. Possibly a permission issue. To check, you can run the 'makelocalrc' utility to see if any errors occurred.
Note for newer versions of nvc++, we are moving away from using pre-generated config files and instead determining these config items each time the compiler is invoked. The pervious concern being the overhead involved in generating the config, but this has become less of a problem.
QUESTION
The following code runs well, it print out the shortest path length between two vertexes. But how can I print out the real path or the detail edges (not only the length) between two vertexes?
...ANSWER
Answered 2021-Nov-11 at 05:08You can use graphFrame.
QUESTION
How can I improve the performance of the networkx function local_bridges
https://networkx.org/documentation/stable//reference/algorithms/generated/networkx.algorithms.bridges.local_bridges.html#networkx.algorithms.bridges.local_bridges
I have experimented using pypy - but so far am still stuck on consuming the generator on a single core. My graph has 300k edges. An example:
...ANSWER
Answered 2021-Feb-21 at 12:44You can't consume a generator in parallel, every non-trivial generator's next state is determined by its current state. You have to call next()
sequentially.
From https://github.com/networkx/networkx/blob/master/networkx/algorithms/bridges.py#L162 this is how the function is implemented
QUESTION
I'm trying to convert a cpu bound algorithm I have to a GPU one, and I'm having all sorts of trouble with cugraph. Some of it is my ignorance, the other part is just the infancy and underdevelopment of cugraph, and the final part is me just sucking at figuring out elegant vectorized approaches.
Let's say I have m data observations consisting of n features. I create a distance matrix by computing the euclidean distance for all observations from all observations (NOTE: This isn't the part I need help with nor is it meant to be optimal. Just adding this part for easily understood, reproducible code)
...ANSWER
Answered 2020-Nov-02 at 22:52It looks like the answer to your first question -- initialization of the Euclidian distance matrix -- was answered in Using cupy to create a distance matrix from another matrix on GPU, but you can certainly optimize the creation of the graph and computation of Dijkstra's matrix utilizing cuDF and cuGraph.
To create the graph efficiently you can construct a cuDF dataframe listing the edges and their weights. This is straightforward due to structure of the Euclidian distance matrix. cuGraph takes in this dataframe as an edge list and returns the graph. Then you can loop over the nodes to compute shortest to applicable vertices. This could later be parallelized or distributed with Dask if the problem size increases.
The code below is about 40x faster than utilizing nx.all_pairs_dijkstra_path_length for this problem size, it also includes the initial distance computation.
QUESTION
I am attempting to perform some processing on email messages in mbox format.
After searching, and a bit of trial and error tried https://docs.python.org/3/library/mailbox.html#mbox
I have got this to do most of what I want (even though I had to write code to decode subjects) using the test code listed below.
I found this somewhat hit and miss, in particular the key needed to look up fields 'subject' seems to be trial and error, and I can't seem to find any way to list the candidates for a message. (I understand that the fields may differ from email to email.)
Can anyone help me to list the possible values?
I have another issue; the email may contain a number of "Received:" fields e.g.
...ANSWER
Answered 2020-Sep-03 at 07:10The email message object provides a get_all method which returns all instances of a header, so we can use this to obtain all the values of the received header.
QUESTION
I was working on this problem and I decided to use Dijkstra's algorithm to solve it. However, I am unsure of how to account for the blocked path from a to b and how to account for the waiting time of 60 minutes when the path is blocked. Do I need more than one SSSP to solve this problem? How can I approach solving this problem?
Image credits: National University of Singapore
My code is as follows:
...ANSWER
Answered 2020-May-01 at 01:16Okay, so what you need to do is find the shortest path from the airport to the destination, then add 60 to all of the edges in that path, then perform dijkstra's algorithm again starting from your house and going to the office. There's probably a more efficient way to do it in one pass, but that'll get you started.
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