better-monadic-for | Desugaring scala ` for ` without implicit ` withFilter ` s | Compiler library

 by   oleg-py Scala Version: 0.3.0-M1 License: MIT

kandi X-RAY | better-monadic-for Summary

kandi X-RAY | better-monadic-for Summary

better-monadic-for is a Scala library typically used in Utilities, Compiler applications. better-monadic-for has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Desugaring scala `for` without implicit `withFilter`s
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              better-monadic-for has a low active ecosystem.
              It has 676 star(s) with 31 fork(s). There are 21 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 9 open issues and 26 have been closed. On average issues are closed in 15 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of better-monadic-for is 0.3.0-M1

            kandi-Quality Quality

              better-monadic-for has no bugs reported.

            kandi-Security Security

              better-monadic-for has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              better-monadic-for is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              better-monadic-for releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            better-monadic-for Key Features

            No Key Features are available at this moment for better-monadic-for.

            better-monadic-for Examples and Code Snippets

            No Code Snippets are available at this moment for better-monadic-for.

            Community Discussions

            QUESTION

            Scala Doobie not inserting values into database
            Asked 2021-Apr-24 at 18:08

            My code to insert values is:

            ...

            ANSWER

            Answered 2021-Apr-24 at 18:08

            As written by @LuisMiguelMejíaSuárez

            As the error clearly says, IO does not have a withFilter method. (You can check the scaladoc here). When you put the type explicitly, you are basically filtering all elements that match such type. And, since the method does not exists, it won't compile. - And no, I do not know any workaround.

            But, I can think on at least ne reason of why it should not have it. IO is not exactly a "container" of elements, like List, since it only is a description of a computation, and if you ant to see it like a container it will only had one element, like Option. But, unlike the former, there is not concept of empty IO. Thus, filtering an IO would not make sense.

            The workaround that I have found is moving the filter inside another function :

            Source https://stackoverflow.com/questions/67230763

            QUESTION

            top-level class without companion can only expand either into an eponymous class or into a block consisting in eponymous companions
            Asked 2020-Jun-20 at 19:36

            I am trying to use https://github.com/estatico/scala-newtype as follows:

            ...

            ANSWER

            Answered 2020-Jun-20 at 19:07

            The README.md of scala-newtype says:

            This expands into a type and companion object definition, so newtypes must be defined in an object or package object.

            Macros are allowed to expand classes into other classes with the same name and companion objects, but from what I can tell, the newtype annotation turns your case class into an object of the same name (along with a type alias like type DbUrl = DbUrl.Type). This behavior (turning a top-level annottee into a tree of some other kind) isn't allowed. If the annotation had generated a class DbUrl, and maybe an object of the same name, though, it would have been all right, but pretty much anything else won't work.

            To fix your problem, all you need to do is move this into a package object (or some other scope, as long as it isn't top-level).

            Edit: As Dmytro Mitin pointed out, the created type is not the type of DbUrl but rather something like type DbUrl = DbUrl.Type with an uppercase "T", where the definition of DbUrl.Type looks something like this (I'm just copying this from the README):

            Source https://stackoverflow.com/questions/62489970

            QUESTION

            How to create WAR instead JAR?
            Asked 2020-May-23 at 23:43

            I would like to compile via sbt to WAR instead of JAR file and I followed this guide.

            I have changed the build.sbt to:

            ...

            ANSWER

            Answered 2020-May-23 at 23:43

            There is a bug in documentation - see https://github.com/sbt/sbt/issues/4490

            Try using dedicated sbt plugin - xsbt-web-plugin - instead of reading that website. According to current docs you need to add to project/plugins.sbt

            Source https://stackoverflow.com/questions/61978812

            QUESTION

            SBT run statement shows: No main class detected
            Asked 2020-May-23 at 22:20

            I have created a web app and when I try to run with sbt run, it shows:

            ...

            ANSWER

            Answered 2020-May-23 at 22:20

            You don't have a main class, the entrypoint to your program defined. On JVM you have to have at least one class which defines

            Source https://stackoverflow.com/questions/61979156

            QUESTION

            Spark tests failing when running with sbt test
            Asked 2020-Feb-20 at 08:12

            We've have written unit tests for spark, in local mode with 4 threads.

            When launched one by one, for example through intellij or sbt testOnly, each test runs fine.

            When launched with sbt test, they fail with errors like

            [info] java.util.ServiceConfigurationError: org.apache.spark.sql.sources.DataSourceRegister: Provider org.apache.spark.sql.execution.datasources.csv.CSVFileFormat not a subtype

            We notably upgraded sbt and spark versions to the latest, tried to run with fork in test := true in the build.sbt, but this didn't help.

            Spark is in version 2.4.3, sbt 1.2.8 and scala in 2.12.8.

            sbt config is nothing special:

            ...

            ANSWER

            Answered 2020-Feb-20 at 08:12

            I just hit this exception in a test, and it was caused by trying to run a Spark action in a thread that was different from the thread where I started the SparkSession. You might want to disable parallelExecution in Test (this is recommended for Spark integration tests anyway).

            Specifically, I was trying to execute multiple Spark actions in parallel, and I tried doing that in Scala's ExecutionContext.global thread pool. When I created a newFixedPoolExecutor instead, everything started working fine.

            AFAICT this is because in DataSource.scala:610, Spark gets the thread's ContextClassLoader:

            Source https://stackoverflow.com/questions/56700351

            QUESTION

            How to share a ZIO Queue between ZIO Tasks via the ZIO Environment
            Asked 2019-Oct-01 at 14:56

            I'm somewhat new to Scala and ZIO and have run into something of an odd puzzle.

            I would like to setup a ZIO Environment containing a ZIO Queue and later have different ZIO Tasks offer and take from this shared Queue.

            I tried defining my environment like this

            ...

            ANSWER

            Answered 2019-Oct-01 at 14:56

            In the Official Gitter Channel for ZIO Core, Adam Fraser suggested

            You would want to have you environment just have a Queue[String] and then you would want to use a method like provideM with Queue.unbounded to create one queue and provide it to your whole application. That's where provideM as opposed to provide comes in. It let's you satisfy an environment that requires an A by providing a ZIO[A].

            A little digging into the ZIO source revealed a helpful example in DefaultTestReporterSpec.scala.

            By defining the Environment as

            Source https://stackoverflow.com/questions/58178210

            QUESTION

            Why subprojects does not recognize dependencies?
            Asked 2019-Sep-18 at 19:44

            I've defined two sub projects that looks as follow:

            ...

            ANSWER

            Answered 2019-Sep-18 at 19:44

            Put libraryDependencies ++= dependencies into settings.

            global, core and serversupervisor are three different subprojects. They can have different library dependencies. Currently you add them to global but not to core and serversupervisor.

            Alternatively you can move libraryDependencies ++= dependencies to Global or ThisBuild scope rather than specific subproject scope. You can add at top

            Source https://stackoverflow.com/questions/57999020

            QUESTION

            Can not resolve symbol Arbitrary
            Asked 2019-Sep-17 at 22:48

            I am trying to implement Arbitrary for my type as follow:

            ...

            ANSWER

            Answered 2019-Sep-17 at 22:48

            You use this in the Compile scope (i.e. sources in src/main), so you need to remove % "test" from the ScalaCheck dependency. Or move that source to the Test scope (i.e. in src/test)

            Source https://stackoverflow.com/questions/57980932

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install better-monadic-for

            The plugin is available on Maven Central.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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