sangria | Scala GraphQL implementation | GraphQL library

 by   sangria-graphql Scala Version: v4.0.0 License: Apache-2.0

kandi X-RAY | sangria Summary

kandi X-RAY | sangria Summary

sangria is a Scala library typically used in Web Services, GraphQL applications. sangria has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Sangria is a scala GraphQL library.
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              sangria has a medium active ecosystem.
              It has 1942 star(s) with 219 fork(s). There are 60 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 51 open issues and 401 have been closed. On average issues are closed in 873 days. There are 11 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of sangria is v4.0.0

            kandi-Quality Quality

              sangria has no bugs reported.

            kandi-Security Security

              sangria has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              sangria is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              sangria releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            sangria Key Features

            No Key Features are available at this moment for sangria.

            sangria Examples and Code Snippets

            No Code Snippets are available at this moment for sangria.

            Community Discussions

            QUESTION

            Sangria-graphql: error when passing in derivedInputObjectType as an mutation argument
            Asked 2020-May-29 at 11:28

            I have the following case class with option fields:

            ...

            ANSWER

            Answered 2017-Aug-20 at 16:26

            In order to deserialize the input in the BusinessUserRow case class, you need to provide an instance of FromInput[BusinessUserRow] type class. You can find more docs on it here:

            http://sangria-graphql.org/learn/#frominput-type-class

            So if you are, for instance, using spray-json, then you need to define JsonFormat for BusinessUserRow

            Source https://stackoverflow.com/questions/45784283

            QUESTION

            All fields and parameters marked as non-null in Graphiql : Sangria, scala
            Asked 2020-May-08 at 18:22

            I am not able to use postman to query a graphql server written in scala using its sangria library. I get a request malformed error in postman if I use the content-type as "application-json" and if I use plain text I get content type not supported. The postman version I am using is Version 6.2.4. The code is pretty straightforward in which I read data from hbase. I use the sangria macro function deriveObjectTypeUnit, myCaseClass to define an object. I am however able to use the graphiql console by concatenating a graphiql.html file from the resources to the route created. The issue with the graphiql console is that it marks all the arguments and fields as non-nullable which it should not as by default the fields are all nullable in graphql. I checked this from the documentation tab of the graphiql console where I can see all my fields and the parameters are marked as non-nullable(Suffixed with an exclamation mark !). Sample query is as follows:

            ...

            ANSWER

            Answered 2020-May-08 at 18:22

            Field might by nullable by default in GraphQL schemas but in Scala nulls are almost always programming errors (and surely always if you pass or return them as parameters) - you want nullable, you explicitly model them with Option. If you want to stick to GraphQL convention just write all fields in your case classes as Optional.

            Source https://stackoverflow.com/questions/61683745

            QUESTION

            Graphql Sangria Many-to-Many example
            Asked 2020-Feb-14 at 08:39

            I'm working on a Many-to-Many relation with Sangria and Slick. I have 3 objects: Role, Permission and RolePermission (a mapping table)

            ...

            ANSWER

            Answered 2020-Feb-14 at 08:39

            You have to define Relation type for both related entities. It's not easy to answer in short comment on StackOverflow, but I've explained such kind of relation in my blog post: https://scalac.io/akka-http-sangria-graphql-backend#implementing-many-to-many-relation I hope it helps..

            Source https://stackoverflow.com/questions/60197953

            QUESTION

            Java Programmatically send GraphQL REST Query
            Asked 2019-Nov-16 at 01:48

            I'm new to GraphQL and I'm trying to figure out how can I programmatically send a GraphQL POST query that I have implemented in a separate micro-service.

            In my main application I'm using Java + Spring REST Template to send the query while attaching the POST Body as a String GraphQL query e.g.

            ...

            ANSWER

            Answered 2017-May-29 at 10:43

            You are providing graphql query in wrong format. The actual graphql query is not a valid JSON format and you are providing in that format and hence you will definitely get invalid JSON exception. Therefore you need to provide graphql query as value instead of body. As your receiving method is parsing query, opertionName and variables field, you need to provide request body in following format:

            Source https://stackoverflow.com/questions/44237758

            QUESTION

            How To make 2 or more tables From one JSON data
            Asked 2019-Jun-30 at 05:35

            I am working on creating dynamic HTML table from JSON Data, I have already created the table dynamically but now I have to Change it with new Requirement

            What I am doing

            • I have array of objects from which i am creating the table and spiting the table into four columns by dividing the length of JSON to 4
            • My table is rendering perfectly into 4 columns

            What I am trying to Do

            • I want to show only 5 Rows in a single go then reloads the div and render the next five rows in same dive and so on until all data gets render

            • Currently I have 68 total data so i am populating it as 17 rows of 4 columns

            • Now on one go when page lodes I want to show 5 rows then after 5 seconds Next 5 rows in same div

            • In simple terms I want to split my JSON data into part of 5-5 rows and show only 5 rows at once then next five after 5 seconds

            • Spiting the Table into Four Columns I have done already,now just want to Show only five rows at a time

            • I am lacking with idea or approach how to do this, How can i divide my JSON in five-five rows and show them at each time interval of 5 seconds

            What I am have done

            ...

            ANSWER

            Answered 2019-May-28 at 09:51

            Instead of creating the rows after every 5 seconds, you can create the rows in one go and hide them all using a class .hidden. Then every 5 seconds make first 5 hidden rows visible.

            Source https://stackoverflow.com/questions/56339301

            QUESTION

            How to Hide / Show Image on HTML page
            Asked 2019-Jun-04 at 21:47

            I am working with Dynamic HTML table in which I am showing my data as in HTML table as my data is in large amount so what I am doing is showing amount of data which will be fixed to one screen, So here i am showing 12 rows at one time then after 5 seconds page refresh hen next 12 and so on, When it reaches to the last page than what I am doing is calling the JSON object again and doing whole process again because in my code that JSON data will be dynamic

            Issue I am facing

            • I have done all the things to refresh page after 5 seconds and calling whole data when it reaches to last page
            • Now what I am trying to do is when it is the last page than after that want to show a image for 10 seconds than again call the whole process
            • Now the whole process on first go will be like table will show 12 rows than if there is more data it will show next 12 row of table and when it reaches the last page I want to show an Image for 10 seconds then call the JSON object again to go through whole process again
            • In my code I have commented What I am doing where

            ...

            ANSWER

            Answered 2019-Jun-03 at 07:15

            I think this will help you.

            Source https://stackoverflow.com/questions/56422075

            QUESTION

            How to move text to New line of same row when text is bigger
            Asked 2019-May-29 at 10:28

            I am working on HTML table and i am stuck here for very long now, I have a requirement of displaying table into four columns/grid which i have done

            Now when i am rendering the table i am displaying first 17 rows in one go than next 17 after five seconds

            What is the issue

            • some ItemNames are big like BIG BANAYAN CARBINET SAUVIGNON BY GLASS
            • So when page is refreshing after five seconds the the column which contains this long name gets very large width which is not good to see as on UI
            • I am trying to make the width of each column uniform all four will have same width
            • So when the long ITEM NAME is coming what I am trying to do is to use word-wrap: normal; to break it after some width,but it is not working
            • I am dividing the four columns into equal part, which ever screen it is rendering the table it should be divided into 4 parts and when ITEMNAME is large i want to display it into same row but in new line after that exceeds the width of column
            • I think i have to give some sort of height to all the rows when it can accept one single small item name then it will show in single row but when the name is large it should show in same row but in two lines with same font

            ...

            ANSWER

            Answered 2019-May-29 at 09:24

            You are getting the data in four rows using the for loop. I would suggest you should use bootstrap class="col-sm-3" in your html file table tag. This wraps the string how long it is and displays four rows with equal space. Also import

            Source https://stackoverflow.com/questions/56356668

            QUESTION

            How to hide/show HTML table rows at an interval
            Asked 2019-May-28 at 16:56

            I am working on HTML tables. Here I have made a table and split into four columns to show up on a display screen, the table is fully dynamic.

            Now what I have to do is to show 5 rows at a time on the screen. I am using CSS to do that. What I am doing is creating table in one go and populating the first 5 rows at once; then after 5 seconds that content gets refreshed and I have to show next five rows this will go on until the all the data loads

            What I have tried

            ...

            ANSWER

            Answered 2019-May-28 at 16:38

            Your function showRows() only removes class hidden, it won't hide the previous five. And your selector is based on the element that has hidden class. So, even though if you hid the previous five, it will just show that five items again. The easy way to fix this is giving each table row an index and hide item based on their index, or rework your selector to select which five you want to display.

            Source https://stackoverflow.com/questions/56345863

            QUESTION

            Sangria Default value for Enum Inputs causes "sangria.schema.SchemaValidationException:"
            Asked 2018-Dec-18 at 04:43

            I'm trying to execute an introspection query against a schema having optional Enum input and a default value for it.

            Below is a sample code

            ...

            ANSWER

            Answered 2018-Dec-18 at 04:43

            After adding a Decoder it works fine

            Source https://stackoverflow.com/questions/53511889

            QUESTION

            Sangria GraphQL Schema with EitherT result
            Asked 2018-Dec-12 at 16:00

            I'm using Sangria for a Play application and currently struggling to implement the schema definition. The Problem is, that the service does not return the needed object directly, it returns an EitherT containing the object.

            Here are some code examples

            case class

            ...

            ANSWER

            Answered 2018-Mar-01 at 13:14

            You can still derive the User object type since it is just a simple case class. For other GraphQL fields that load the users and return EitherT you would need to transform the value to something that sangria can work with (which means that these fields need to be defined manually, but you still can use derive* macros for other fields). The most simple approach would be to fold it to a simple Future[User]. Future is able to hold the error or the success result. If you would have a list of errors inside of the Either, then you can just wrap it in some custom exception, and then unwrap and properly render it in the ExceptionHandler.

            Source https://stackoverflow.com/questions/49049119

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sangria

            You can download it from GitHub.

            Support

            If you've got some interesting ideas to share or discovered a nasty bug, feel free to use Sangria's issue tracker. Also feel free to fork project and create the pull requests - they are highly appreciated!. If you are facing an issue and not sure what would be the best way to describe it, the I would recommend you to use this minimal gist as a template.
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            https://github.com/sangria-graphql/sangria.git

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            gh repo clone sangria-graphql/sangria

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            git@github.com:sangria-graphql/sangria.git

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