sangria | Scala GraphQL implementation | GraphQL library
kandi X-RAY | sangria Summary
kandi X-RAY | sangria Summary
Sangria is a scala GraphQL library.
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Community Discussions
Trending Discussions on sangria
QUESTION
I have the following case class with option fields:
...ANSWER
Answered 2017-Aug-20 at 16:26In order to deserialize the input in the BusinessUserRow
case class, you need to provide an instance of FromInput[BusinessUserRow]
type class. You can find more docs on it here:
http://sangria-graphql.org/learn/#frominput-type-class
So if you are, for instance, using spray-json, then you need to define JsonFormat
for BusinessUserRow
QUESTION
I am not able to use postman to query a graphql server written in scala using its sangria library. I get a request malformed error in postman if I use the content-type as "application-json" and if I use plain text I get content type not supported. The postman version I am using is Version 6.2.4. The code is pretty straightforward in which I read data from hbase. I use the sangria macro function deriveObjectTypeUnit, myCaseClass to define an object. I am however able to use the graphiql console by concatenating a graphiql.html file from the resources to the route created. The issue with the graphiql console is that it marks all the arguments and fields as non-nullable which it should not as by default the fields are all nullable in graphql. I checked this from the documentation tab of the graphiql console where I can see all my fields and the parameters are marked as non-nullable(Suffixed with an exclamation mark !). Sample query is as follows:
...ANSWER
Answered 2020-May-08 at 18:22Field might by nullable by default in GraphQL schemas but in Scala null
s are almost always programming errors (and surely always if you pass or return them as parameters) - you want nullable, you explicitly model them with Option
. If you want to stick to GraphQL convention just write all fields in your case classes as Option
al.
QUESTION
I'm working on a Many-to-Many relation with Sangria and Slick. I have 3 objects: Role, Permission and RolePermission (a mapping table)
...ANSWER
Answered 2020-Feb-14 at 08:39You have to define Relation
type for both related entities. It's not easy to answer in short comment on StackOverflow, but I've explained such kind of relation in my blog post: https://scalac.io/akka-http-sangria-graphql-backend#implementing-many-to-many-relation I hope it helps..
QUESTION
I'm new to GraphQL and I'm trying to figure out how can I programmatically send a GraphQL POST query that I have implemented in a separate micro-service.
In my main application I'm using Java + Spring REST Template to send the query while attaching the POST Body as a String GraphQL query e.g.
...ANSWER
Answered 2017-May-29 at 10:43You are providing graphql query in wrong format. The actual graphql
query is not a valid JSON
format and you are providing in that format and hence you will definitely get invalid JSON exception. Therefore you need to provide graphql
query as value instead of body. As your receiving method is parsing query
, opertionName
and variables
field, you need to provide request body in following format:
QUESTION
I am working on creating dynamic HTML table from JSON Data, I have already created the table dynamically but now I have to Change it with new Requirement
What I am doing
- I have array of objects from which i am creating the table and spiting the table into four columns by dividing the length of JSON to 4
- My table is rendering perfectly into 4 columns
What I am trying to Do
I want to show only 5 Rows in a single go then reloads the div and render the next five rows in same dive and so on until all data gets render
Currently I have 68 total data so i am populating it as 17 rows of 4 columns
Now on one go when page lodes I want to show 5 rows then after
5 seconds
Next 5 rows in same divIn simple terms I want to split my JSON data into part of 5-5 rows and show only 5 rows at once then next five after
5 seconds
Spiting the Table into Four Columns I have done already,now just want to Show only five rows at a time
I am lacking with idea or approach how to do this, How can i divide my JSON in five-five rows and show them at each time interval of 5 seconds
What I am have done
...ANSWER
Answered 2019-May-28 at 09:51Instead of creating the rows after every 5 seconds, you can create the rows in one go and hide them all using a class .hidden
. Then every 5 seconds make first 5 hidden rows visible.
QUESTION
I am working with Dynamic HTML table in which I am showing my data as in HTML table as my data is in large amount so what I am doing is showing amount of data which will be fixed to one screen, So here i am showing 12
rows at one time then after 5 seconds page refresh hen next 12 and so on, When it reaches to the last page than what I am doing is calling the JSON object again and doing whole process again because in my code that JSON data will be dynamic
Issue I am facing
- I have done all the things to refresh page after 5 seconds and calling whole data when it reaches to last page
- Now what I am trying to do is when it is the last page than after that want to show a
image
for 10seconds
than again call the whole process - Now the whole process on first go will be like table will show 12 rows than if there is more data it will show next 12 row of table and when it reaches the last page I want to show an Image for 10 seconds then call the JSON object again to go through whole process again
- In my code I have commented What I am doing where
ANSWER
Answered 2019-Jun-03 at 07:15I think this will help you.
QUESTION
I am working on HTML table and i am stuck here for very long now, I have a requirement of displaying table into four columns/grid which i have done
Now when i am rendering the table i am displaying first 17 rows in one go than next 17 after five seconds
What is the issue
- some
ItemNames
are big likeBIG BANAYAN CARBINET SAUVIGNON BY GLASS
- So when page is refreshing after five seconds the the column which contains this long name gets very large width which is not good to see as on UI
- I am trying to make the width of each column uniform all four will have same width
- So when the long ITEM NAME is coming what I am trying to do is to use
word-wrap: normal;
to break it after some width,but it is not working - I am dividing the four columns into equal part, which ever screen it is rendering the table it should be divided into 4 parts and when ITEMNAME is large i want to display it into same row but in new line after that exceeds the width of column
- I think i have to give some sort of height to all the rows when it can accept one single small item name then it will show in single row but when the name is large it should show in same row but in two lines with same font
ANSWER
Answered 2019-May-29 at 09:24You are getting the data in four rows using the for loop. I would suggest you should use bootstrap class="col-sm-3"
in your html file table tag. This wraps the string how long it is and displays four rows with equal space. Also import
QUESTION
I am working on HTML tables. Here I have made a table and split into four columns to show up on a display screen, the table is fully dynamic.
Now what I have to do is to show 5 rows at a time on the screen. I am using CSS to do that. What I am doing is creating table in one go and populating the first 5 rows at once; then after 5 seconds that content gets refreshed and I have to show next five rows this will go on until the all the data loads
What I have tried
...ANSWER
Answered 2019-May-28 at 16:38Your function showRows() only removes class hidden, it won't hide the previous five. And your selector is based on the element that has hidden class. So, even though if you hid the previous five, it will just show that five items again. The easy way to fix this is giving each table row an index and hide item based on their index, or rework your selector to select which five you want to display.
QUESTION
I'm trying to execute an introspection query against a schema having optional Enum input and a default value for it.
Below is a sample code
...ANSWER
Answered 2018-Dec-18 at 04:43After adding a Decoder it works fine
QUESTION
I'm using Sangria for a Play application and currently struggling to implement the schema definition. The Problem is, that the service does not return the needed object directly, it returns an EitherT containing the object.
Here are some code examples
case class
...ANSWER
Answered 2018-Mar-01 at 13:14You can still derive the User
object type since it is just a simple case class. For other GraphQL fields that load the users and return EitherT
you would need to transform the value to something that sangria can work with (which means that these fields need to be defined manually, but you still can use derive*
macros for other fields). The most simple approach would be to fold it to a simple Future[User]
. Future
is able to hold the error or the success result. If you would have a list of errors inside of the Either
, then you can just wrap it in some custom exception, and then unwrap and properly render it in the ExceptionHandler
.
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