log | Fancy logging library for Scala

 by   wvlet Scala Version: Current License: Apache-2.0

kandi X-RAY | log Summary

kandi X-RAY | log Summary

log is a Scala library typically used in Logging applications. log has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

NOTICE: wvlet-log has been renamed to Airframe Log and merged into Airframe project. You can find the latest source code under wvlet/airframe.
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            kandi-support Support

              log has a low active ecosystem.
              It has 60 star(s) with 2 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 6 have been closed. On average issues are closed in 26 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of log is current.

            kandi-Quality Quality

              log has no bugs reported.

            kandi-Security Security

              log has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              log is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              log releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            log Key Features

            No Key Features are available at this moment for log.

            log Examples and Code Snippets

            No Code Snippets are available at this moment for log.

            Community Discussions

            QUESTION

            how to get jstree instance from iframe source?
            Asked 2021-Jun-16 at 03:07

            I have prepare 2 tree view in separate iframe using jstree. The right tree view should control the left tree view. When user click one one the list in right tree view, the respective item folder will open and selected on left tree view. I can make it happen using div in single page. I control the left tree view using instance of left tree view in right jstree div var instance = $('#left').jstree(true);.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:07

            I had used document.getElementById('1').contentWindow.jQuery('#left').jstree(true); to get instance from iframe with id='1'. In order to listen to right iframe(with id='2') if any menu has been clicked, I used document.getElementById('2').contentWindow.jQuery('#right').on("changed.jstree",function(e,data){}). I get the instance of left iframe within this function. By using this instance, I has deselect previous selection, select current selection, and open children of selected menu.

            index-12.html

            Source https://stackoverflow.com/questions/67933193

            QUESTION

            Elastic beanstalk deploy fails when deploying more than 4 containers using docker compose
            Asked 2021-Jun-16 at 03:01

            I am having this weird issue with elastic beanstalk. I am using docker compose to run multiple docker containers on same elastic beanstalk instance.

            if I run 4 docker containers everything works fine. but if i make it 5, deploy fails with error Instance deployment failed to download the Docker image. The deployment failed. and if I check eb-engine.log. it retries to docker pull command and fails with error.

            this is really weird error. bcs all docker images are valid and correctly tagged. it just the number of services that I am adding in docker compose file. if number is greater than 4, deploy fails

            my question is, is there any limit of docker services that can be run using docker compose ? or is there any timeout in elastic beanstalk to pull images?

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:01

            Based on the comments.

            The issue was that t2.micro instance was used. The instance has only 1 vCPu and 1GB of ram. This was not enough to run 5 docker containers. Changing instance type to t2.large with 8GB ram and 2 vCPUs solved the problem.

            docker-compose allows to specify cpu and memory limits. Maybe you can set them up to keep your containers resource requirements in check.

            Source https://stackoverflow.com/questions/67977894

            QUESTION

            How to sort google drive files by size in a spreadsheet?
            Asked 2021-Jun-16 at 02:55

            I am using a script to recursively list all the files in a Google drive folder to a spreadsheet. It is working fine but i need to sort the file listing by size ( highest size on top ). Also drive api returns value of size in bytes but i need them in GB's . I haven't found any way to do it through api directly ,so i want to divide the size value of each file by 1073741824 upto 1 decimal rounding it off ( 1 GB = 1073741824 bytes )

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:55
            Modification points:
            • In your script, the values are put to the Spreadsheet using appendRow in the loops. In this case, the process cost will be high. Ref And also, in this case, after the values were put to the Spreadsheet, it is required to sort the sheet.
            • So, in this answer, I would like to propose the following flow.
              1. Retrieve the file list and put to an array.
              2. Sort the array by the file size.
              3. Put the array to the Spreadsheet.

            When above points are reflected to your script, it becomes as follows.

            Modified script:

            Source https://stackoverflow.com/questions/67995533

            QUESTION

            Why is this printing twice to my console?
            Asked 2021-Jun-16 at 02:48

            I am running the following in my React app and when I open the console in Chrome, it is printing the response.data[0] twice in the console. What is causing this?

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:48

            You have included fetching function in the component as it is, so it fires every time component being rendered. You better to include fetching data in useEffect hook just like this:

            Source https://stackoverflow.com/questions/67995505

            QUESTION

            There was a problem saving the text in EditText to a file
            Asked 2021-Jun-16 at 01:47

            This code receives information from an acquaintance you want to register in editText, and then clicks finButton to save the information you receive as a file called friendlist.txt. However, the Toast message is outputted from the try-catch statement that is currently performed when finButton is pressed. Also, the checkpermission does not work, which is wrapped in a try~catch statement, but does not have output on the logcat.

            And manifest.

            uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"

            uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"

            is written.

            Please let me know the solution. And this content is written with a translator, so the sentence can be strange.

            when you press finButton, the logcat is shown below.

            The code corresponding to the 116th line is this.

            FileOutputStream outstream = openFileOutput("friendList.txt", Activity.MODE_WORLD_WRITEABLE);

            logcat

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:47

            Try with Context.MODE_APPEND or Context.MODE_PRIVATE instead of Activity.MODE_WORLD_WRITEABLE

            Source https://stackoverflow.com/questions/67995297

            QUESTION

            why does var behave differently in a with statement depending on whether or not the passed object has a property with the same name?
            Asked 2021-Jun-16 at 01:14

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:14

            The difference in behaviour can be accounted for by this behaviour, described in (for instance) the following note in ECMAScript 2022 Language Specification sect 14.3.2.1:

            NOTE: If a VariableDeclaration is nested within a with statement and the BindingIdentifier in the VariableDeclaration is the same as a property name of the binding object of the with statement's object Environment Record, then step 5 will assign value to the property instead of assigning to the VariableEnvironment binding of the Identifier.

            In the first case:

            Source https://stackoverflow.com/questions/67994931

            QUESTION

            Parallelization in Durable Function
            Asked 2021-Jun-16 at 01:02

            I'm trying to understand how parallelization works in Durable Function. I have a durable function with the following code:

            ...

            ANSWER

            Answered 2021-Jun-10 at 08:44

            There are two approaches that are possible. The first is to use a suborchestrator for each job so that each suborchestrator handles just a specific job. Here is the docs for this approach https://docs.microsoft.com/en-us/azure/azure-functions/durable/durable-functions-sub-orchestrations?tabs=csharp Example from docs seem to be alike to yours.

            The other is to use ContinueWith so that each job has its own "chain"

            Source https://stackoverflow.com/questions/67910695

            QUESTION

            Error accessing nested array of objects in Typescript
            Asked 2021-Jun-16 at 00:23

            I'm trying to consume json coming from a webapi. When debugging, the data is coming through correctly as per picture below:

            Surprisingly when I try to loop through the objects in the report.subreport array, I get told it's undefined:

            ...

            ANSWER

            Answered 2021-Jun-16 at 00:21

            Javascript is case sensitive. I see that you used subreport and it should be subReport with a capital R.

            Source https://stackoverflow.com/questions/67994851

            QUESTION

            Fetch data from Cloud Firestore and store it in a constant
            Asked 2021-Jun-15 at 23:56
            const set = firebase.firestore().collection("workoutExercises").doc(firebase.auth().currentUser.uid).get()
              console.log(set)
            
            ...

            ANSWER

            Answered 2021-Jun-15 at 23:56

            Firebase calls like this are asynchronous, meaning they don't return immediately. In Javascript, you can deal with this in a couple of different ways, using async/await or Promises.

            Here's an example using a Promise:

            Source https://stackoverflow.com/questions/67994072

            QUESTION

            How can I enter main() without it looping login()
            Asked 2021-Jun-15 at 23:29

            I am new in Python, I would like to ask how can make my code work. in login() function, if the username and password are correct, log = True, then when go to main() function, log variable is not defined.

            Then i found online where add log = login() in main() function, like this

            ...

            ANSWER

            Answered 2021-Jun-15 at 06:55

            I modified your code.this will works fine
            but the customerMian() and adminMain() function not defined.

            Source https://stackoverflow.com/questions/67981073

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install log

            You can download it from GitHub.

            Support

            The most convenient way to use wvlet-log is adding LogSupport to your class:. The logger name will be determined from your class name (e.g., MyApp).
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