usernameGenerator | simple script that creates potential usernames
kandi X-RAY | usernameGenerator Summary
kandi X-RAY | usernameGenerator Summary
A simple script that creates potential usernames based on a person's first and last names
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QUESTION
I'm having this code where after I get the http request fulfilled, I'm calling the state updater function i.e., setUserName
with the response I get from the async function. But I see that UsernameGenerator()
just gets called repeatedly like in an infinite loop. I think somehow repeated rendering is taking place here because I have used the UserName as a value for an input in my code.
The thing I want is to set the res as the initial value
for the state variable and after setting the value once UsernameGenerator()
should never be called again.
Here is the snippet of my code
...ANSWER
Answered 2021-Feb-13 at 07:52You need to put a call in useEffect hooks, like -
QUESTION
I'm semi-new to python, and i'm trying to make a random username and password generator, but nothing that I've been having trouble setting up a random username
I've tried just generating a random string of ten characters, but it ends up being way too long, and quite repetitive. Here's the code I tried
...ANSWER
Answered 2019-Oct-27 at 17:59username.join(nameExtra)
means "take each of the characters in nameExtra
, and put the full value of username
between each of them". This is why it's appearing several times. To fix this problem, do username + nameExtra
instead of username.join(nameExtra)
.
Also, you're not building a string correctly, so it's using . at 0x0000020B09A5DE48>
as the string, instead of the text you wanted it to use. To fix this problem, do ''.join(str(random.randint(0, 9)) for i in range(2))
instead of ''.join(str(random.randint(0, 9) for i in range(2)))
. Note the subtle difference in the closing parentheses.
QUESTION
I'm working in a logic to pick it up the ID from an entity called "Group", i need set a variable from another entity, called User, with this value.
I created a function that search in mongo for an document with name "admin" and return his id. I think the problema is that the function is asynchronous, so, i only get this value later.
Here's what i trying to do:
...ANSWER
Answered 2018-Dec-28 at 11:17Using callbacks is probably the most common way of doing async programming in JavaScript (and Node.js). However as of ES2017, one can use Promises in conjunction with async/await to write some non-blocking-async code which looks like synchronous code.
We can rewrite getAdminId
function so it returns a promise instead of returning values in the callback (which doesn't work anyways because in CPS programming return values in callbacks don't matter):
QUESTION
I have to write method to generate random username which contains 8 characters, consisting of lowercase letters and up to 3 digits. So I wrote following method:
...ANSWER
Answered 2018-May-11 at 10:51Sorry, my previous answer was irrelevant to your issue. I'm writing a new better one now.
So, you generate some sequence of eight NON-UNIQUE characters. Say, it is "koabwbaq". Then you use
QUESTION
How can I change the code so that it prints out like the way I want it to be printed out? I want the userNameGenerator to be printed out first, with an arrow (->) in front of it, and the personName to be displayed with open and close square brackets ([]) beside it. I also want to remove the commas at the end. I've done a bit of it already as you can see below:
Code that needs changing:
...ANSWER
Answered 2018-Feb-27 at 20:57I am looking through the double for each loop and I believe I have narrowed down your issue. In the second for each loop, you print out the name of the person followed by the comma. But you do this for every element, including the last one. Include a conditional in there that once it reaches the length of the row, only print out the name not the comma.
QUESTION
I'm trying to create a program that (1) prompts for a user's full name and then generates a username; (2) prompts for a number and then determines if the number is odd or even. I wrote out the code for the username and odd/even classes and would like to call them from the main class. However, when called from the main class, the username method prompts the user twice before generating the username and the odd/even method doesn't actually determine if the number the user inputted is odd/even. When I remove the scanner object from the username class, I get a out of bounds compilation error so I'm forced to put it back in just so the program will run. Should I be using return statements?
Username
...ANSWER
Answered 2017-Dec-16 at 18:16You should change your code like below
inside main method
QUESTION
I am working on a personal Java project and learning how to print out data from a text file. My code (as you can see below) prints out the userNameGenerator and personName data perfectly fine but I want it to be printed out from the toString in my Java Class. How can I change my code to print it out from there?
This is how my toString looks like:
...ANSWER
Answered 2017-Dec-06 at 23:11Everything looks right in your code.
I think you should just call the method when you are trying to print it out:
QUESTION
I want the output to list the userNameGenerator in alphabetical order. I converted the HashSet into an ArrayList because sets cannot be sorted, so I changed it to an ArrayList to sort out the list in alphabetical order. I used Collections.sort to sort the list of strings in alphabetical order, however, the output is still the same.
Code I used for alphabetical order:
...ANSWER
Answered 2017-Dec-06 at 22:15As @phatfingers commented, a TreeSet will respect the natural order of the entries in the set.
Since Codes2 already implements Comparable, you could simply replace your original HashSet with a TreeSet and call it a day.
Note this from the TreeSet documentation, however:
Note that the ordering maintained by a set (whether or not an explicit comparator is provided) must be consistent with equals if it is to correctly implement the Set interface. (See Comparable or Comparator for a precise definition of consistent with equals.) This is so because the Set interface is defined in terms of the equals operation, but a TreeSet instance performs all element comparisons using its compareTo (or compare) method, so two elements that are deemed equal by this method are, from the standpoint of the set, equal. The behavior of a set is well-defined even if its ordering is inconsistent with equals; it just fails to obey the general contract of the Set interface. (emphasis added)
What this means is that, while simply using a TreeSet probably work by itself, you may still want to consider overriding equals() and hashCode() in your Codes2 class so that the ordering behavior is consistent with equals.
QUESTION
I want to remove the duplicates of userNames in the ArrayList. I've tried to convert the ArrayList to an HashSet, but for some reason it doesn't work. The reason why I chose to convert the ArrayList into a HashSet is because it does not allow duplicated values, however, when I use it on my code, it only changes the order in the list:
My code output:
...ANSWER
Answered 2017-Dec-05 at 16:30You need to override the equals
and hashCode
methods on your Person object in order for Set
to know which objects are considered the same.
It seems you want any two people with the same userNameGenerator
field to be considered equal. In that case, the following will suit your needs:
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