beep | A collection of bash scripts playing various music | Script Programming library
kandi X-RAY | beep Summary
kandi X-RAY | beep Summary
A collection of bash scripts playing various music using beep .
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QUESTION
I'm using glutin
and so have a move closure for my program's main loop and I'm trying to play an audio file with the rodio
crate. With the following code everything works and I get one beep every time the program loops:
ANSWER
Answered 2021-Jun-15 at 16:27Basically, the problem at hand is that rodio::Decoder::new
consumes the value which it reads from (well, actually it is already consumed by BufReader::new
). So, if you have a loop or a closure that can be called multiple times, you have to come up with a fresh value each time. This what File::open
does in your first code snipped.
In your second code snipped, you only create a File
once, and then try to consume it multiple times, which Rust's ownership concept prevents you from doing.
Also notice, that using reference is sadly not really an option with rodio
since the decoders must be 'static
(see for instance the Sink::append
trait bound on S
).
If you think your file system is a bit slow, and you want to optimize this, then you might actually want to read the entire file up-front (which File::open
doesn't do). Doing this should also provide you with a buffer (e.g. a Vec
) that you can clone, and thus allows to repeatedly create fresh values that can be consumed by the Decoder
. Here is an example doing this:
QUESTION
I am trying to get my robot to communicate with my PC via sockets by using local IP addresses on my own home network (not devices outside my network). The robot is acting as the server and my own PC is acting as the client/host. I don't really know what ports are open on my robot but I do definitely know that port 22 on the robot is open (which is the SSH port). The robot is a lego EV3 robot apart from it has had some ev3python software put onto it. When I run my program I am getting the following error on the server (my robot):
...ANSWER
Answered 2021-Jun-14 at 12:24hostIPAddress = "xx.xx.xx.xx" #the local IP address of my PC on my home network
backlog = 1
size = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((hostIPAddress,22))#22 is the port number I am using. (THIS IS ALSO THE LINE WHERE THE ERROR IS COMING FROM)
s.listen(backlog)
QUESTION
I can actually run the bot, it will let mi interact with the other 3 commands, but when trying to do the "kickembed" it will fail and give me the error "client.commands.get('kickembed').execute(message,args,Discord)" ^ Cannot read property of 'execute' of undefined
tbh, i tried everithing, my little brain cant work this out, tysm for your time!
...ANSWER
Answered 2021-Jun-10 at 03:07your kickembed
files have wrong name it is kick
So it should be like:
QUESTION
I can easily make an alert on a website using:
...ANSWER
Answered 2021-Jun-05 at 12:56The answers here probably help you: Playing a sound in a browser (Chrome), from javascript
Besides that, I would create a function like this and call it instead of the native alert function:
QUESTION
I am currently trying to make a .wav file that will play sos in morse.
The way I went about this is: I have a byte array that contains one wave of a beep. I then repeated that until I had the desired length. After that I inserted those bytes into a new array and put bytes containing 00 (in hexadecimal) to separate the beeps.
If I add 1 beep to a WAVE file, it creates the file correctly (i.e. I get a beep of the desired length). Here is a picture of the waves zoomed in (I opened the file in Audacity): And here is a picture of the entire wave part:
The problem now is that when I add a second beep, the second one becomes completely distorted: So this is what the entire file looks like now:
If I add another beep, it will be the correct beep again, If I add yet another beep it's going to be distorted again, etc. So basically, every other wave is distorted.
Does anyone know why this happens?
Here is a link to a .txt file I generated containing the the audio data of the wave file I created: byteTest19.txt
And here is a lint to a .txt file that I generated using file format.info that is a hexadecimal representation of the bytes in the .wav file I generated containing 5 beeps (with two of them, the even beeps being distorted): test3.txt
You can tell when a new beep starts because it is preceded by a lot of 00's.
As far as I can see, the bytes of the second beep does not differ from the first one, which is why I am asking this question.
If anyone knows why this happens, please help me. If you need more information, don't hesitate to ask. I hope I explained well what I'm doing, if not, that's my bad.
EDIT Here is my code:
...ANSWER
Answered 2021-Jun-04 at 09:07The problem
Your .wav file is Signed 16 bit Little Endian, Rate 44100 Hz, Mono
- which means that each sample in the file is 2 bytes long, and describes a signed amplitude. So you can copy-and-paste chunks of samples without any problems, as long as their lengths are divisible by 2 (your block size). Your silences are likely of odd length, so that the 1st sample after a silence is interpreted as
QUESTION
I'm coding a discord bot and I don't know what to do with first(). Could someone help. kick.js:
...ANSWER
Answered 2021-Jun-01 at 22:12You made a small typo - instead of msg.mentions.user.first()
, you need to do msg.mentions.users.first()
QUESTION
I'm working on a simple project to play a beeping noise in a C# application. I assume you can't use the System.Console.Beep(100, 100);
function, because you need a console for that to work. Is there an alternative function I can use that let's me specify the frequency and duration of the beep?
ANSWER
Answered 2021-May-28 at 20:26For playing audio of any kind I usually use https://www.nuget.org/packages/NetCoreAudio/ because it's cross platform and just works.
QUESTION
I have a list of Keywords
...ANSWER
Answered 2021-May-25 at 15:03No need to use a regex when Python's standard in
operator will do the job, IMO:
QUESTION
I'm using discord.js and here is my code:
...ANSWER
Answered 2021-May-24 at 03:11As you can see client.command
not having .set
, but client.commands
is
Solution:
client.commands.set(command.name, command);
QUESTION
I found a nice function on OSF, which I would like to apply to my own data: https://osf.io/huy8b/
However, if I try to use the lapply function, I get an error. My code and sample data (my own dataset is much bigger) are here.
...ANSWER
Answered 2021-Mar-29 at 13:49These are not suitable places to use lapply
. The functions just take the data frames as inputs, so you can just use the functions. For example:
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