xkcdpass | Generate passwords like Randall Munroe

by danielmcgraw Shell Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | xkcdpass Summary

xkcdpass is a Shell library. xkcdpass has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Generate passwords like Randall Munroe (

Support

Quality

Security

License

Reuse

Support

xkcdpass has a low active ecosystem.

It has 22 star(s) with 5 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 1 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of xkcdpass is current.

Quality

xkcdpass has 0 bugs and 0 code smells.

Security

xkcdpass has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

xkcdpass code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

xkcdpass is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

xkcdpass releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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xkcdpass Key Features

No Key Features are available at this moment for xkcdpass.

xkcdpass Examples and Code Snippets

No Code Snippets are available at this moment for xkcdpass.

Community Discussions

Trending Discussions on xkcdpass

Push to heroku fails

QUESTION

Push to heroku fails

Asked 2019-Aug-28 at 17:06

I am following this tutorial https://www.codementor.io/jamesezechukwu/how-to-deploy-django-app-on-heroku-dtsee04d4 for deploying my Django app to heroku. This is my first Django app:

Push rejected, failed to compile Python app.

I'm currently running python 3.7.0. this is set in my runtime.txt file: python-3.7.0

stack trace:

...

ANSWER

Answered 2019-Aug-28 at 17:06

The version of paramiko (1.15.2) isn't compatible with python 3.7. Use a newer version. It uses the async keyword which is reserved as argument in a function call.

If you look at the latest version, you'll see that this particular line of code is now using async_.

You should always use the same version of python on your local machine as on production to spot these errors earlier.

I also suggest you look at some of the other dependencies, your version of gunicorn is also more than 5 years old, it contains security vulnerabilities, so may some other (old) packages you're using.

Finally, use pip freeze to compare what's installed in your local virtualenv compared to requirements.txt. And make sure they are the same!

Source https://stackoverflow.com/questions/57696405

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install xkcdpass

xkcdpass is a shell script, so drop it and the dictionary in the same place and make sure it's added to your $PATH.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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