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QUESTION
I'm trying to get the coefficients of a numpy.polynomial.polynomial.Polynomial
obtained via
the fit
method:
ANSWER
Answered 2021-May-27 at 18:57Per documentation, the .fit()
method returns
A series that represents the least squares fit to the data and has the domain and window specified in the call. If the coefficients for the unscaled and unshifted basis polynomials are of interest, do new_series.convert().coef.
Running c.convert().coef
on your data produces:
array([2.25, 7.5 , 6.25])
QUESTION
I'm trying to cross-validate some stuff in python but using this:
...ANSWER
Answered 2021-Jan-31 at 06:49Well it looks like the way to correctly Cross-Validate this is with
QUESTION
I used numpy's polyfit
to fit some noisy data and then wanted to use polyval
to evaluate the fit at some new points. For some reason, fitting works fine but polyval
only gives correct results when I reverse the order of the coefficients of the polynomial:
ANSWER
Answered 2020-May-14 at 19:18I dug around a lot and found out what was going on. It turns out numpy has two sets of polynomial tools, one in the base numpy library, and another in numpy.polynomial
and they expect things in opposite order. Both polyfit
and polyval
are found in both libraries and appear to operate the same on this simple case, but their parameters are different:
From numpy
:
QUESTION
I am studying the stability of numerical derivatives as a function of the step I take to compute these derivatives. With a derivative with 15 points (obtained by the finite difference method), I get the following plot (each multipole "l
" corresponds to a parameter whose depends the derivative but it doesn't matter) :
Now, I would like to compare this derivative of 15 points with the derivative computed with 3, 5 and 7 points. For this, I have just plotted the relative difference like (with absolute differences) :
...ANSWER
Answered 2019-Nov-29 at 21:58I have to say that I find your question formulation very confusing, so I can only help you with a bit general answer. Perhaps you could split your big question in several smaller ones next time.
To start with, I assume that your question is: how does the amount of points in a differentiation stencil matter, when I will do polynomial interpolation on the derivative afterwards?
The number of points in a stencil generally increases the accuracy of the computation of the derivative. You can see that by filling in Taylor expansions for the variables in the numerical derivative. After terms cancels you are left with some higher-order term that gives you a lower bound on the error that you make. The underlying assumption however is, that the function (in your case C) of which you compute the derivative is smooth on the interval that you compute the derivatives on. Meaning that if your function is not nicely behaved on your 15-point stencil, then that derivative is essentially worthless.
The order of the polynomial in polynomial regression is usually a free parameter chosen by the user because the user might know that their series is behaved like a polynomial up to certain degree, but unaware of the polynomial coefficients. If you know something about your data, you can set the degree yourself. For instance if you know your data is linear correlated with step, you could set the degree to 1 and you have linear regression. In this case you don't want to specify any higher degree because your data will likely fit to a polynomial, which you know is not the case. In a similar way, if you know your data behaves like a polynomial of some degree, you certainly don't want to fit any higher. If you have really no clue what degree the polynomial should be, then you should make an educated guess. A good strategy is just to plot the polynomial going through the data points, upping the polynomial one degree at the time. You then want the line to go in between the points, and not diverge towards specific points. In case you have many outliers, there exists method that are better suited than least-squares.
Now onward to your problem specifically.
- There is no way to compute an optimal degree, unless you have more information about your data. Degree is a hyperparameter. If you want an optimum for it, you need to put additional prior information, such as "I want the lowest degree polynomial that fits the data with an error epsilon."
- Overfitting is simply fixed by choosing a lower degree polynomial. If that does not fix it, then least-squares regression is not for you. You need to look into a regression method that chooses a different metric, or you need to preprocess your data, or you need a non-polynomial fit (fit a function of certain shape, then use Levenberg-Marquardt for instance).
- 15-step derivative looks very questionable, you do likely not have this kind of smoothness in your data. If you have a good reason for this, tell us, otherwise just use 2 points for the first derivative, or 3 or 5 for the second.
- The expression with the Landau symbol (big-O) is not switching fourth order to second. If you subtract the two equations and divide by
h^2
theO(h^4)/h^2
becomesO(h^2)
.
QUESTION
#plotting values
x_max = np.max(X) + 100
x_min = np.min(X) - 100#calculating line values of x and y
x = np.linspace(x_min, x_max, 1000)
y = b0 + b1 * x #plotting line
plt.plot(x, y, color='#00ff00', label='Linear Regression')#plot the data point
plt.scatter(X, Y, color='#ff0000', label='Data Point')# x-axis label
plt.xlabel('Time')#y-axis label
plt.ylabel('Signal Strength MHz')
plt.legend()
plt.show()
...ANSWER
Answered 2019-Nov-22 at 18:31You have switched the order of polynomial coefficients and the x-values. As per docs, the first argument is the polynomial coefficients:
numpy.polyval(p, x)
Parameters:
p : array_like or poly1d object 1D array of polynomial coefficients (including coefficients equal to zero)
x : array_like or poly1d object A number, an array of numbers, or an instance of poly1d, at which to evaluate p.
Change the following line
QUESTION
Fairly new to numpy/python here, trying to figure out some less c-like, more numpy-like coding styles.
BackgroundI've got some code done that takes a fixed set of x values and multiple sets of corresponding y value sets and tries to find which set of the y values are the "most linear".
It does this by going through each set of y values in a loop, calculating and storing the residual from a straight line fit of those y's against the x's, then once the loop has finished finding the index of the minimum residual value.
...sorry this might make a bit more sense with the code below.
...ANSWER
Answered 2019-Nov-22 at 09:06From the numpy.polynomial.polynomial.polyfit
docs (not to be confused with numpy.polyfit
which is not interchangable)
:
x : array_like, shape (M,)
y : array_like, shape (M,) or (M, K)
Your ys
needs to be transposed to have ys.shape[0]
equal to xs.shape
QUESTION
I want to speed up a process on a dataframe where every row in the dataframe are points (red points in the image), and I fit every row to a polynomial (blue points in the image):
My dataframe would look like this one:
...ANSWER
Answered 2019-Sep-30 at 12:50Since it looks like you are handling each row independently and perform curve fitting not matter what other rows look like, I think you can simply parallelize the code using joblib, so you can do
QUESTION
Say I want to fit a polynomial model of degree d
via least squares regression. There are two methods I've learned in python. One uses numpy
and the other sklearn
. After I fit the model and get the coefficients, to predict values for test data, in sklearn
, I can do:
ANSWER
Answered 2019-Aug-25 at 20:25I use numpy.polyval, docs are at https://docs.scipy.org/doc/numpy/reference/generated/numpy.polyval.html - here is a graphical polynomial fitter as an example that uses polyval.
QUESTION
I have some data that I fitted to a polynomial. My goal is to (i) plot the data and the polynomial, and (ii) define a function that estimates p(x)
for some x
in the range. I have done both, but I am not understanding how polyval
works.
According to the documentation, numpy.polyval(p,x)
is computing p[0]*x**(N-1) + p[1]*x**(N-2) + ... + p[N-2]*x + p[N-1]
. That is, the 0-th term of p corresponds to the highest degree of the polynomial.
ANSWER
Answered 2019-May-16 at 11:12def f(x_,y_):
F = np.polyval(p,x_)
return F
QUESTION
I'm plotting some data with Matplotlib but the auto axis labels are off. The X axis has negative values in the label where they should be positive and the Y axis has a very strange scale.
Here's some code:
...ANSWER
Answered 2019-Apr-01 at 21:06In general I assume Matplotlib knows the range of your data, so I'd start by looking at the data it is plotting. Looking at the x data, the y-intercept should be 3.08, while x_coefs is array([-5.13333333, 1.66666667]
so your fit functions are off somehow (ipython or print(x_coefs) is your friend here).
You need to reverse x and z in x_coefs = poly.polyfit(x, z, 1)
, similarly for y_coefs
.
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