broom | A disk cleaning utility for developers

by nicoulaj Shell Version: Current License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | broom Summary

broom is a Shell library. broom has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitLab, GitHub.

A disk cleaning utility for developers.

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Quality

Security

License

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Support

broom has a low active ecosystem.

It has 37 star(s) with 5 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

There are 13 open issues and 26 have been closed. On average issues are closed in 135 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of broom is current.

Quality

broom has no bugs reported.

Security

broom has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

broom is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

broom releases are not available. You will need to build from source code and install.

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broom Key Features

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broom Examples and Code Snippets

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Community Discussions

Trending Discussions on broom

including regression coefficient and pvalue in the ggplot2

Transform a class "perm.htest" objects, from (multiple permutation t test) into a data frame

Extract slope and r squared from grouped linear models using broom

How to read nested json file and pull information from dataframe inside dataframe in r?

How to write a function to use lapply or purrr to broom::tidy a list of (polr) model outputs?

Convert summary of data.frame into a dataframe

Error with lapply in dplyr package: group_by

for loop not iterating in R

Error: No tidy method for objects of class function :: broom.mixed

ASP .NET Pass DateTime Value from Views to Controller

QUESTION

including regression coefficient and pvalue in the ggplot2

Asked 2021-Jun-04 at 10:33

I did linear regression analysis between the response variable(y) and predictor variables in the surgical data set considering pindex as a confounding variable. I aim to plot the response variable(y) against the experimentally determined values of the predictor variables and to this end, I am Successful. However, could not able to indicate the estimated regression and p-value in the ggplot2. In the code below, trying to do the analysis and the plot. It would be much appreciated if someone could show me how to indicate the estimated regression and p-values inside the ggplot2.

...

ANSWER

Answered 2021-Jun-04 at 10:33

You can add the equation and p-value to the plot using the "stat_poly_eq" function from the ggpmisc package:

Source https://stackoverflow.com/questions/67835224

QUESTION

Transform a class "perm.htest" objects, from (multiple permutation t test) into a data frame

Asked 2021-Jun-01 at 07:48

I have some results from a perm.t.test that I would like to transform into a data frame. I've tried a lot and searched a lot but I don't manage to fix this, I'm still new to R.

This is a reduced version of my dataset:

...

ANSWER

Answered 2021-Jun-01 at 05:32

library(tidyverse)

tidy_result <- function(result) {
  tibble(
    estimate = result$estimate,
    statistic = result$statistic,
    conf.low = result$conf.int[1],
    conf.high = result$conf.int[2],
    perm.p.value = result$perm.p.value
  )
}

combn(levels(data$t), 2, function(x) {
  perm.t.test(exparat~t,data = subset(data, t %in% x), R=999, paired = T)
}, simplify = FALSE) -> result

map_dfr(result, tidy_result)


# # A tibble: 6 x 5
#   estimate statistic conf.low conf.high perm.p.value
#                            
# 1   -0.015    -0.116   -0.307    0.277         0.918
# 2   -0.073    -0.764   -0.289    0.143         0.470
# 3   -0.04     -0.670   -0.175    0.0950        0.528
# 4   -0.058    -0.482   -0.330    0.214         0.593
# 5   -0.025    -0.220   -0.282    0.232         0.824
# 6    0.033     0.292   -0.222    0.288         0.748

Source https://stackoverflow.com/questions/67782979

QUESTION

Extract slope and r squared from grouped linear models using broom

Asked 2021-May-29 at 19:28

I have a dataframe that I want to run linear models on by group, then use the broom package to extract the slope and r squared for each model. So far I am trying this:

...

ANSWER

Answered 2021-May-29 at 18:02

I think simply adding ungroup() achieves what you need:

Source https://stackoverflow.com/questions/67753874

QUESTION

How to read nested json file and pull information from dataframe inside dataframe in r?

Asked 2021-May-26 at 07:50

I am reading a json file as a response from api which is nested and when I look at them in a dataframe/table structure format then there are data frame under data frame.

I have saved file at github location.

...

ANSWER

Answered 2021-May-26 at 07:50

You can unnest the sessions variable and the slots variable within it to get a long dataframe.

Source https://stackoverflow.com/questions/67700631

QUESTION

How to write a function to use lapply or purrr to broom::tidy a list of (polr) model outputs?

Asked 2021-May-25 at 03:35

I'm running a list of ordered logit models with different variables etc. I want to convert the output into a tidy tibble to use in ggplot etc. (I also want to save the 'regular model output' so I want to do this separately.)

I want to do this in an automated way, using purrr or lapply or some such, to be able to first 'run all the models' (automating that is another question for later) and then 'tidy all the models', the latter presumably generating a list of tibbles.

I've tried the following, but it throws: Error: No tidy method recognized for this list.

...

ANSWER

Answered 2021-May-19 at 03:22

Something like this ?

Source https://stackoverflow.com/questions/67596260

QUESTION

Convert summary of data.frame into a dataframe

Asked 2021-May-23 at 00:20

How can I convert the summary run on a data.frame into a data.frame itself? I need a data.frame as an output to knitr::kable in RMarkdown.

In particular I have this dataframe

...

ANSWER

Answered 2021-May-23 at 00:20

We could use the matrix route

Source https://stackoverflow.com/questions/67655132

QUESTION

Error with lapply in dplyr package: group_by

Asked 2021-May-18 at 03:17

I found a nice function on OSF, which I would like to apply to my own data: https://osf.io/huy8b/

However, if I try to use the lapply function, I get an error. My code and sample data (my own dataset is much bigger) are here.

...

ANSWER

Answered 2021-Mar-29 at 13:49

These are not suitable places to use lapply. The functions just take the data frames as inputs, so you can just use the functions. For example:

Source https://stackoverflow.com/questions/66853846

QUESTION

for loop not iterating in R

Asked 2021-May-16 at 20:42

I have a large df that follows the structure below. For each of 200 groups, I want to fit a linear model to 30 years of data, then extract the slope and the R squared.

...

ANSWER

Answered 2021-May-16 at 20:22

Just putting i after a variable name won't automatically create a new object. I think what you want to do is make a list with 200 indices containing the individual data frames that you want.

Source https://stackoverflow.com/questions/67561206

QUESTION

Error: No tidy method for objects of class function :: broom.mixed

Asked 2021-May-14 at 14:26

I am trying to perform a linear regression fit using tidymodels,parsnip but encounters the following error:

...

ANSWER

Answered 2021-May-14 at 14:26

The main issue is that you need to assign the fitted model to an object; in your case it would also be fit.

There are two other points to consider:

it's confusing/not best practice to assign variables with the same name as R functions (i.e. you might want to call your fit fit0 or my_fit or something rather than fit); usually you can get away with it but it breaks, confusingly, in some contexts
broom.mixed is a red herring. The broom package is actually used for lm fits (and you don't need to load it, apparently tidymodels loads it (and parsnip) automatically ...)

Source https://stackoverflow.com/questions/67535785

QUESTION

ASP .NET Pass DateTime Value from Views to Controller

Asked 2021-May-03 at 13:39

When in view mode, I try to fill in and get the date, it always turns out to be empty, but for example, the string field is filled in. And if I don't use the ViewModel, but only the Booking model, the date is filled in. I would like the date to be filled in with the viewmodel as well...

Controller:

...

ANSWER

Answered 2021-May-03 at 13:39

The problem is, you're posting CheckInDate and CheckOutDate in the html form, while it should be booking.CheckInDate and booking.CheckOutDate. Remove the name in your view, so name will be set with the value provided in asp-for.

Source https://stackoverflow.com/questions/67369046

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install broom

You can download it from GitLab, GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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