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files for my bash-scripting course on Safari Live
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Trending Discussions on bash-scripting
QUESTION
I am in the very basic of the basic with Shell. In general, I only use the WSL2 for ssh. Now, I write a loop, so I google for an example to see how it works. Here is my ref:https://ryanstutorials.net/bash-scripting-tutorial/bash-loops.php. The problem is that even if I just copy and paste their examples, I get the error:
...ANSWER
Answered 2021-Jan-19 at 18:00The problem is probably that you copy-pasted the script from Windows and tried to execute it from Linux. Windows uses CR in addition to NL for new lines, where Linux uses only '\n' and finds the former ('\r') strange.
Try something like this from your WSL2 terminal:
QUESTION
Hope you are all well!
I am after achieving this relatively simple task, yet I am failing in getting optimal results, so I need your help.
Scenario:
I have the following files and folders (directories) structure:
...ANSWER
Answered 2020-Oct-20 at 11:59Here is a working solution I have come up with so far which needs to be optimised and cleaned up, its rudimentary and I can use optimisation tips:
QUESTION
Currently, I am using a bash-script in order to enable sharding for DB and then shard collection. I am using eval:
...ANSWER
Answered 2020-Sep-04 at 15:52Your command client.admin.command('enableSharding', db_name)
is correct; however it can only be run against a mongos
instance; I suspect you are trying to run it against a mongod
instance.
QUESTION
i am newbie in bash-scripting and linux. I want to write a script to get a username from the terminal and say whether that username is on the passwd or not. i wrote and tried below script but it doesn't work. help me that what i can do.
...ANSWER
Answered 2020-Mar-19 at 01:13Your script could look like that:
QUESTION
first of all, i've read the question for loop with multiple conditions in Bash scripting but it does not work for what i intend to do. In the following script, a first for loop assign f quantity of arrays to a pair of variables (CON_PERC and CON_NAME)
...ANSWER
Answered 2019-Dec-17 at 14:23You need to nest them like this (untested in your examples)
QUESTION
I'm having some trouble writing a do-while loop in bash with multiple conditions.
My code currently works when it is like this:
...ANSWER
Answered 2019-Oct-07 at 10:25You can use for
loop:
QUESTION
I know that there are arrays in bash-scripting. For example:
...ANSWER
Answered 2018-Dec-12 at 14:35bash
doesn't have array values at all; it provides array syntax to use with names that have an array
attribute set:
QUESTION
Bash's builtin read
command has a -i
option, which specifies an initial input, which the user can accept as it is or edit or add to. I cannot find anything similar for Zsh's read
command.
None of the options listed in the zshbuiltins
man page seem relevant:
ANSWER
Answered 2018-Nov-29 at 16:04In zsh you could manually set the variable and use vared
instead of read
:
QUESTION
Include all objects from a paginated REST API call in a single JSON file using cURL and Bash. This combined list will be fed into a Power BI report.
DetailsA request returns a maximum of 100 objects. There are 400+ objects total. The total grows over time. I don't want to maintain a script that includes something like for set in 0 100 200 300 400 ; do
because it requires me to manually match the sets to the current number of objects. To save labor, I would like a script to auto-detect when the final page has been processed and then break.
To achieve my goal, the plan I have come up with so far is to extract each incremental set of 100 items into its own JSON file, then assemble them with cat
and extract relevant JSON keys/values using JQ. The reason for Bash is that it is the only programming I know.
(Based on this question and answer)
...ANSWER
Answered 2018-Aug-30 at 02:52Assuming my theory about startIndex
holds water and implementing @CharlesDuffy's suggestion about jq
, this becomes
QUESTION
Would someone please care to explain how on earth this is supposed to make sense:
Contents of insanity.sh
:
ANSWER
Answered 2018-Aug-07 at 17:58It is happening because you're not quoting $ARG
inside [ ... ]
.
Without quoting your code is effectively running as:
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