javascript-tutorial | JavaScript 教程 https : //wangdoc.com/javascript | Script Programming library
kandi X-RAY | javascript-tutorial Summary
kandi X-RAY | javascript-tutorial Summary
本教程全面介绍 JavaScript 核心语法，覆盖了 ES5 和 DOM 规范的所有内容。. JavaScript 后续新增的 ES6 语法，请看《ES6 标准入门教程》。.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of javascript-tutorial
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javascript-tutorial Examples and Code Snippets
Lines of Code : 33License : Non-SPDX
Copyfunction SubscribePane(elem, url) {
function showMessage(message) {
let messageElem = document.createElement('div');
messageElem.append(message);
elem.append(messageElem);
}
async function subscribe() {
let response = await fe function accept(req, res) {
if (req.url == '/ws' && req.headers.upgrade &&
req.headers.upgrade.toLowerCase() == 'websocket' &&
// can be Connection: keep-alive, Upgrade
req.headers.connection.match(/\bupgr function getWeekDay(date) {
let days = ['SU', 'MO', 'TU', 'WE', 'TH', 'FR', 'SA'];
return days[date.getDay()];
} Community Discussions
Trending Discussions on javascript-tutorial
QUESTION
I have this javascript code that make a get request. It works fine.
...ANSWER
Answered 2020-Nov-27 at 18:54From your test, it's not entirely clear whether you know what getReq is supposed to do. You mock it out* to return 123, but assuming the implementation is mostly correct it would actually return a promise of an array of strings where each string is the first character of a sha (actually it returns undefined, because you don't return the promise chain, and maybe you actually wanted it to return the complete sha of the first commit rather than the first character of the sha for every commit?)
Similarly in your previous attempt your mock for fetch didn't make sense:
QUESTION
ANSWER
Answered 2020-Aug-26 at 11:37It depend on how long you are planning to run this program. Your loop might go forever but the recursion one will throw an error.
All the function calls you do are placed in a stack. At some point, your stack is going to be full, causing a Stackoverflow Exception.
The stack limit depends on the browser, but pass that limit, the Recursion one will stop in an error while the loop will continue.
QUESTION
To my understanding of the event loop, the following code will output 'Sync 2' then 'Sync 4' first (synchronous code), then 'Promise 3' (fetch returns a Promise which would be placed in the microtask queue and will be executed after the synchronous code finishes and data comes back from the API), finally 'Async 1' (setTimeout would be placed in the macrotask/callback queue with the lowest priority).
However, in the lastest version Chrome, I always got 'Async 1' before 'Promise 3' if I set setTimeout() to 0 like below. Is there anything I misunderstand? Is it possible that a not-yet-resolved Promise gets lower priority than something in the macrotask queue here?
...ANSWER
Answered 2020-May-19 at 12:14(fetch returns a Promise which would be placed in the microtask queue and will be executed after the synchronous code finishes and data comes back from the API)
This is only true if the Promise that is returned resolves immediately - for example, with Promise.resolve. If the Promise returned by fetch resolved immediately, you'd be right, and the Promise 3 would log before the setTimeout's.
But fetch does not resolve immediately - it requires the endpoint to respond first, and that takes some time, so you see the setTimeout log first.
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