pwait | Await process completion | Command Line Interface library
kandi X-RAY | pwait Summary
kandi X-RAY | pwait Summary
pwait waits until all arguments have terminated. If a number is passed pwait assumes it is a pid; otherwise it is handled as a process name. To wait for a process--not a pid--called "123" use the --name option. If pwait was passed a process_name or invoked using the --name option, pwait waits until all processes matching process_name have terminated, including new processes spawned after invocation. Mixing pids and process names is not supported. The primary difference between pwait and wait is the latter is limited to only child processes of the current shell, while pwait can be used to monitor any process.
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Community Discussions
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QUESTION
I am trying to implement non-blocking communications in a large code. However, the code tends to fail for such cases. I have reproduced the error below. When running on one CPU, the code below works when switch is set to false but fails when switch is set to true.
...ANSWER
Answered 2021-Apr-21 at 07:07The proposed program is currently broken when using Open MPI, see issue https://github.com/open-mpi/ompi/issues/8763. The current workaround is to use MPICH.
QUESTION
I'm making an Ajax call to the same PHP page from a link on the page. For the final code I'll be passing some parameters but for the sake of keeping it simple, I'm not doing that in the code below. Reason I'm using Ajax is to place a "Please Wait" message as it seemed the most effective way to do it (usually you do a call from one page to another, which works perfectly fine).
I do get to see the "Please wait" message accordingly after clicking on the link but it keeps the content of THE section below the new content being displayed by the Ajax call. So int he example, below, I basically end up with 2 links that say "Click here". How do I make it load just the new content (which in this case is identical)?
This must be simple but I'm not sure what I'm missing here.
PWAIT.PHP
...ANSWER
Answered 2018-Feb-20 at 02:22After our discussions, we've discovered that your code is working exactly as it should. It is doing exactly what you ask it to do.
- Load the page from the server
- Click button
- Loads the same page via AJAX
- Duplicates the page contents into a div on the page
- Display duplicate contents
That's what you've asked, that's what you've received.
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Install pwait
download pwait $ wget https://github.com/wting/pwait/raw/master/pwait
make it executable $ chmod +x ./pwait
move it to a folder in $PATH $ mv ./pwait ~/bin/
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