SMC | Read-only wrapper for macOS 's System Management Controller

 by   DanielStormApps Swift Version: Current License: MIT

kandi X-RAY | SMC Summary

kandi X-RAY | SMC Summary

SMC is a Swift library typically used in Utilities, macOS applications. SMC has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Read-only wrapper for macOS's System Management Controller (SMC) written in Swift
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            kandi-support Support

              SMC has a low active ecosystem.
              It has 23 star(s) with 5 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              SMC has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of SMC is current.

            kandi-Quality Quality

              SMC has no bugs reported.

            kandi-Security Security

              SMC has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              SMC is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              SMC releases are not available. You will need to build from source code and install.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of SMC
            Get all kandi verified functions for this library.

            SMC Key Features

            No Key Features are available at this moment for SMC.

            SMC Examples and Code Snippets

            No Code Snippets are available at this moment for SMC.

            Community Discussions

            QUESTION

            Access general confidence boundaries of cronbach's alpha in R psych
            Asked 2021-Jun-13 at 13:26

            I have a dataframe on which I use psych::alpha. In the output there are general confidence boundaries around a general cronbach's alpha value. I want to access those but they don't appear in the results when I save the output as a variable. In the documentation they're called itemboot.ci but that doesn't exist in the alpha object.enter code here

            ...

            ANSWER

            Answered 2021-Jun-13 at 13:26

            When you print an object, either by using print or by sending it to the R console, some extra processing may happen. Every object (almost always) has its own print and in this case you can see that the print.psych method (called behind the scenes instead of print on any psych package object) is doing the following with your object of (sub)class alpha:

            Source https://stackoverflow.com/questions/67958269

            QUESTION

            Issue in extracting a specific column from psych::alpha output
            Asked 2021-Jun-07 at 18:26
            library(mirt) #this contains a dataset called deAyala.
            library(psych) #this contains the alpha() function.
            alpha(deAyala) 
            
            ...

            ANSWER

            Answered 2021-Jun-05 at 09:41

            You can get rid of the warning bit by wrapping it with suppressWarnings() but the first bit of the message looks like just a print statement in the alpha() function. This will work though

            Source https://stackoverflow.com/questions/67848074

            QUESTION

            splitting.js results in "Uncaught TypeError: Splitting is not a function" in Rails 6
            Asked 2021-Jun-04 at 10:25

            I am using the splitting.js javascript library in my Rails 6 project. When I try to load the page I get "Uncaught TypeError: Splitting is not a function" in the console.

            I have installed the javascript library using Yarn:

            yarn add splitting

            Splitting() is called with other Javascript in scripts.js which is required in my applicaiton.js file. I have configured my application.js file in a number of ways to try to fix the issue but to no avail. Here is my current iteration of this file (entire file included in case there are other interactions to consider):

            ...

            ANSWER

            Answered 2021-Jun-04 at 10:25

            I solved this problem thanks to some help from @rossta. I needed to move all my import statement for the splitting.js module from application.js to the script.js file in which the module was being called. So I added the following to the top of scripts.js:

            Source https://stackoverflow.com/questions/67796590

            QUESTION

            snipe command isn't mentioning user
            Asked 2021-May-07 at 14:07

            I made a snipe command but the only problem is it doesn't mention a user properly. I've been trying to solve this for so long. I also attached a picture of what the snipe looks like. Traceback Error:

            Ignoring exception in command snipe: Traceback (most recent call last): File "/opt/virtualenvs/python3/lib/python3.8/site-packages/discord/ext/commands/core.py", line 85, in wrapped ret = await coro(*args, **kwargs) File "main.py", line 261, in snipe embed = discord.Embed('description = f"<@!{snipe_message_author} deleted {snipe_message_content}') TypeError: init() takes 1 positional argument but 2 were given The above exception was the direct cause of the following exception: Traceback (most recent call last): File "/opt/virtualenvs/python3/lib/python3.8/site-packages/discord/ext/commands/bot.py", line 939, in invoke await ctx.command.invoke(ctx) File "/opt/virtualenvs/python3/lib/python3.8/site-packages/discord/ext/commands/core.py", line 863, in invoke await injected(*ctx.args, **ctx.kwargs) File "/opt/virtualenvs/python3/lib/python3.8/site-packages/discord/ext/commands/core.py", line 94, in wrapped raise CommandInvokeError(exc) from exc discord.ext.commands.errors.CommandInvokeError: Command raised an exception: TypeError: init() takes 1 positional argument but 2 were given

            ...

            ANSWER

            Answered 2021-May-07 at 14:07

            You can't mention users in the author field or the title field, better move it to the description.

            Source https://stackoverflow.com/questions/67428709

            QUESTION

            Error building with make: Undefined reference to `CEGUI::NullRenderer::create()'
            Asked 2021-Apr-30 at 20:33

            Lately someone reminded me of a game I used to play back when I was growing up (not so long ago) and I wanted to try getting it to run again. It hasn't been developed for almost ten years so no of the prebuilt packages work. I grabbed an the source code for the game and for an old version of the CEGUI library and got to work.

            I fixed a few issues in the make process but now I'm stuck with this error message:

            ...

            ANSWER

            Answered 2021-Apr-30 at 20:33

            You've declared it, which means the compiler is happy to compile it. The declaration is like the name of the function: the compiler knows that the function exists and can compile code that calls it.

            But in order to link it, you have to link in the definition (the implementation) of that function. The linker is telling you that it doesn't have the actual implementation of that function that you declared.

            Most likely your link line is wrong, almost surely you either forgot to put the library on the link line at all or else you put it in the wrong place, but since you didn't provide us with any information about the link command that was run to generate that error message or the makefile rule you used to link, there's no way we can help.

            Source https://stackoverflow.com/questions/67336566

            QUESTION

            Dyld Error Message when launching PyCharm
            Asked 2021-Mar-27 at 18:50

            I have been trying to figure out this problem for few weeks now, but am still stuck. I have been researching it and slowly getting more information but have not been able to solve it yet.

            I have read these similar questions on Stack Overflow:

            dyld: Library not loaded: /usr/local/Cellar/python/3.7.4_1/Frameworks/Python.framework/Versions/3.7/Python

            dyld: Library not loaded: /System/Library/Frameworks/CoreFoundation.framework/Versions/A/CoreFoundation

            Resolving PyCharm python error - dyld: Library not loaded

            The problem is that every time I launch PyCharm, the error below pops up:

            ...

            ANSWER

            Answered 2021-Mar-27 at 18:45
            1. Something might be broken with my Virtual Environments

            The easiest solution is using a venv - it's standard library and thus the best baseline for virtual enviorments. (For completness it's worth mentioning that historically there have been a number of solutions for this.) As an example creating a venv with the PyCharm GUI is easy, it creates a new interpreter from the base Python interpreter optionally sharing its site-packages. The GUI lets you interface with PyPI to install aditional packages.

            Eventually, it's worth learning to do the same using the command line, see venv — Creation of virtual environments. This boils down to 3 commands

            1. Create the venv (since you have Python on your PATH)

              c:\>python -m venv c:\path\to\myenv

            2. Activate the venv (this is OS specific, see the documentation)

              /bin/activate

            3. After activating use pip to install any libraries you want

              pip install library_name

            After having the venv created and activated it's ready to use on the terminal (inside or outside PyCharm), or you can use it with run configurations in PyCharm.

            Now, in your case you are also using Anaconda, which manages the packages and the environments for you. But it's important to realize that what Anaconda does for the most part are the above steps wrapped in it's own GUI, see the similarities with Finding your Anaconda Python interpreter path.

            Besides this, there's a hard rule that venvs should not be copied or moved. They have hardcoded paths inside them that will break. So, when you create a venv use it in the directory where you created it. The whole point of venvs is that if you break something you simply create a new one on-the-fly. Eventually, you'll want to write your own shell script to automate creating venvs.

            1. Something might be broken with my PATH

            Source https://stackoverflow.com/questions/66788592

            QUESTION

            ANTLR4 no viable alternative at input 'do { return' error?
            Asked 2021-Mar-27 at 14:13

            This ANTLR4 parser grammar errors a 'no viable alternative' error when I try to parse an input. The only rules I know of that matches the part of the input with the error are the rules 'retblock_expr' and 'block_expr'. I have put 'retblock_expr' infront of 'block_expr' and put 'non_assign_expr' infront of 'retblock_expr' but it still throws the error.

            input:

            print(do { return a[3] })

            full error:

            line 1:11 no viable alternative at input '(do { return'

            parser grammar:

            ...

            ANSWER

            Answered 2021-Mar-27 at 14:13

            Your PRINT token can only be matched by the blk_expr rule through this path:

            There is no path for retblock_expr to recognize anything that begins with the PRINT token.

            As a result, it will not matter which order you have elk_expr or retblock_expr.

            There is no parser rule in your grammar that will match a PRINT token followed by a LPR token. a block_expr is matched by the program rule, and it only matches (ignoring wsp) block_expr or retblock_expr. Neither of these have alternatives that begin with an LPR token, so ANTLR can't match that token.

            print(...) would normally be matched as a function call expression that accepts 0 or more comma-separated parameters. You have no sure rule/alternative defined. (I'd guess that it should be an alternative on either retblock_expr or block_expr

            That's the immediate cause of this error. ANTLR really does not have any rule/alternative that can accept a LPR token in this position.

            Source https://stackoverflow.com/questions/66831117

            QUESTION

            Why is my ANTLR4 parser grammar erroring 'no viable alternative at input'?
            Asked 2021-Mar-25 at 02:52

            When I run my grammar (lexer and parser) in powershell, it produces these errors:

            ...

            ANSWER

            Answered 2021-Mar-23 at 10:50

            Both global and a are listed in your grammer under kwr rule.

            kwr is mentioned in the inl rule which isn't used anywhere. So your parser don't know how to deal with inl and don't know what to do with two inl chained together (global a)

            Source https://stackoverflow.com/questions/66761457

            QUESTION

            UPPAAL: ModelDemo for Java API (Error while getting memory info: 34, javax.xml.stream.XMLStreamException: ParseError at [row,col]:[1,3])
            Asked 2021-Feb-20 at 22:55

            I am trying to get get the ModelDemo.java to work because I would like to work with the Java API. Unfortunately, I am running into errors...

            I am using Eclipse IDE Version 2020-06 (4.16.0), openjdk 11.0.10 2021-01-19 and uppaal64-4.1.24 for linux. I have created a project which contains the the ModelDemo.java file. I have also added model.jar and uppaal.jar as external JARs to the Classpath of the project in eclipse.

            Running the main in ModelDemo.java with the 'hardcoded' argument returns this log:

            ...

            ANSWER

            Answered 2021-Feb-20 at 22:55
            Error while getting memory info: 34
            

            Source https://stackoverflow.com/questions/66294466

            QUESTION

            Are oracle OBIEE bundle patches applied consecutively or can you just apply the latest
            Asked 2021-Feb-17 at 21:26

            we have an OBIEE 12.2.1.3.0 server in Linux that currently only has this OBI bundle patch applied:

            29112070;OBI BUNDLE PATCH 12.2.1.3.190416

            Since then, there have been 6 more bundle patches that have been released. I was wondering if each one has to be installed in the order they were released as they are considered cumulative, however on Oracles support site they show that they are all superseded by the latest, because well, they are all older than the latest bundle patch.

            The latest patch is #32294042, and I was wondering if just that could be installed as it has these patches listed in the 'Bugs Fixed By This Patch" section:

            ...

            ANSWER

            Answered 2021-Feb-17 at 21:26

            Bundle Patches are always cumulative. You can install the last one.

            Generally you should try to stay up-to-date. it's not just application bugs which are fixed but also security bugs. The closer you stay to the current patch level the more secure you are.

            Source https://stackoverflow.com/questions/66248161

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install SMC

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/DanielStormApps/SMC.git

          • CLI

            gh repo clone DanielStormApps/SMC

          • sshUrl

            git@github.com:DanielStormApps/SMC.git

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