PostalCodeValidator | A validator postal codes with support | Internationalization library
kandi X-RAY | PostalCodeValidator Summary
kandi X-RAY | PostalCodeValidator Summary
A validator for postal codes with support for 200+ regions. Note: Only the region of a locale is used to determine validation rules. To validate the postal code for a particular region, you can construct a locale using an identifier with the "und" language code.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of PostalCodeValidator
PostalCodeValidator Key Features
PostalCodeValidator Examples and Code Snippets
Community Discussions
Trending Discussions on PostalCodeValidator
QUESTION
I have a Angular 8 application and I am working on a profile form with ngForm
so that users can fill in data about them self, like a postal cod.e I am using a regular expression for postal code, like this: ddddll(1234AA) for example.
Googled, tutorials
So I have this for checking the regular expression for Postal code:
...ANSWER
Answered 2019-Sep-02 at 10:31The problem is that the pattern should change while you are typing. You can't straight up tell the pattern that you're expecting between 1 - 4 letters first before expecting 1 - 2 numbers, simply because the pattern will not match whilst typing. It depends on the current value's length. If You've typed in less than or equal to 4 characters, the pattern should be /^[0-9]{profile.zipCode.length}/i
. From there on out, the pattern needs to match: /^[0-9]{4}[a-z]{profile.zipCode.length - 4,2}/i
.
So I'd suggest storing the pattern in a variable, and changing it based on the length of the zipcode.
QUESTION
export const composeValidators = (...validators) => value => validators.reduce((error, validator) => error || validator(value), undefined);
...ANSWER
Answered 2019-Jul-15 at 16:09export const composeValidators = (...validators) => value => validators.reduce((error, validator) => error || validator(value), undefined)
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