Chester | Chester is a Swift GraphQL query builder | GraphQL library
kandi X-RAY | Chester Summary
kandi X-RAY | Chester Summary
Chester is a Swift GraphQL query builder.
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QUESTION
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
Edit: dput(df2)
...ANSWER
Answered 2022-Apr-18 at 03:52Here's one way you could turn state abbreviations into state names using R's built in state vectors:
QUESTION
My code has a mathematical function that iterates over a list of county class objects and returns the county with the max voter turnout along with that turnout in a tuple.
Code here:
...ANSWER
Answered 2022-Feb-11 at 14:05There is bug in your code.
In first line, you are assigning whole County object to the max_county_variable
QUESTION
I'm using fandom module in python for my discord bot. I get this error when I request data by using page.images[0]
. It should be an image url. This is the page I want to get.
ANSWER
Answered 2022-Feb-01 at 09:46I fixed it by using pymediawiki module.
This code that use mediawiki can replace fandom module by changing the api of wiki.
QUESTION
I have an app that I'd like to be able to have the title change once there is more than 1 input selected in a selectizeInput
. I know this is a simple thing but I can't seem to figure it out!
Sample of data:
...ANSWER
Answered 2021-Dec-08 at 15:49Made slight changes in sample data and code:
QUESTION
I am trying to convert the indicator below from Pine Script vs4 to vs5. The error message is the following: "Conversion failed, reason: line 324: Cannot read property 'startLine' of undefined". It seems that there is something wrong with the plot function.
Does anybody have an idea of how this error could be fixed?
Thank you
...ANSWER
Answered 2021-Dec-06 at 15:14Seems to be related to color=na
. Replace it with color=color(na)
(Pine has a built-in mass Find and Replace via Ctrl+F) and the script should convert correctly.
QUESTION
I am creating a contact form with 5 fields which will email the input details to a set e-mail but when the form is submitted i,m receiving error! Please complete the form and try again. here is php code, js and htm form. Any help would be much appreciated.
html Form:
...ANSWER
Answered 2021-Nov-11 at 22:35QUESTION
import requests
from bs4 import BeautifulSoup
import pandas as pd
headers ={
'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.114 Safari/537.36'
}
productlink=[]
n=[]
a=[]
re=[]
ra=[]
w=[]
r =requests.get('https://www.houzz.com/professionals/general-contractor')
soup=BeautifulSoup(r.content, 'html.parser')
tra = soup.find_all('div',class_='hz-pro-search-result__info')
for pro in tra:
name=pro.find('span',class_='mlm header-5 text-unbold').text
n.append(name)
address=pro.find('span',class_='hz-pro-search-result__location-info__text').text
a.append(address)
reviews=pro.find('span',class_='hz-star-rate__review-string').text
re.append(reviews)
rating=pro.find('span',class_='hz-star-rate__rating-number').text
ra.append(rating)
for links in tra:
for link in links.find_all('a',href=True)[2:]:
if link['href'].startswith('https://www.houzz.com/professionals/general-contractors'):
productlink.append(link['href'])
for link in productlink:
r =requests.get(link,headers=headers)
soup=BeautifulSoup(r.content, 'html.parser')
for web in soup.find_all('a',attrs={'class':'sc-62xgu6-0 jxCcwv mwxddt-0 bSdLOV hui-link trackMe'}):
w.append(web['href'])
df = pd.DataFrame({'name':n,'address':a,'reviews':re,'rating':ra,'web':w})
print(df)
...ANSWER
Answered 2021-Oct-07 at 12:22Make it as simple as possible and do not store the information from different loops in these bunch of lists, try to store them in one dict
:
QUESTION
I have a table that looks like:
id site_names site_addresses industries feis 30 Borden Incorporated 198 Saluda St , Chester , SC , 29706-1579 , United States|198 Saluda St, Chester, SC 29706, USA|198 Saluda St Chester SC 29706-1579 United States Food and Cosmetics 12345|45678 31 Butterkrust Bakeries, Inc.|Flowers Baking Co. of Lakeland, LLC|Southern Bakeries, Inc. dba Butterkrust Bakeries null Food|Food and Cosmetics 12345 33 Church & Dwight Canada Corp. 5485 RUE FERRIER , , MONTREAL, QUEBEC Quebec , , -- , CA null nullI want to split the table into a materialized view where each row is one of the combinations possible when you split site_names, site_addresses, industries, and feis up. So for example, a few rows from this data would be:
id site_name site_address industry fei 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 45678 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 45678 ... 31 Butterkrust Bakeries, Inc. null Food 12345 31 Flowers Baking Co. of Lakeland, LLC null Food 12345I have tried several ways to accomplish this. The closest I got was with this code:
...ANSWER
Answered 2021-Sep-24 at 20:47If you want all combinations, you can use a single query:
QUESTION
I have a page that gives the user the ability to filter store locations by clicking on links for Region and Individual Shops nested within those Regions. Every click updates an object containing which filters have been applied, hides all the elements and then shows only the filtered set of elements.
My code in this post takes the data from the filters object and creates a CSS selector string to which the jQuery .show()
method can applied.
I tried doing it 2 different ways thinking there wouldn't be much of a difference in performance, but to my surprise, jsbench.me showed Solution #2 (below) to be ~90% slower, and I'm baffled as to why.
Here is the code that creates the CSS selector string for each solution. They both use the same object representing the current active filters. They can be found in this Codepen as well (variables are named slightly differently, but the code is the same as below).
Example Active Filters Object ...ANSWER
Answered 2021-Aug-07 at 13:21The difference between forEach
and map
won't really be significant, forEach
will likely have a slight edge since it doesn't have to create a new array but that's just a guess. The reason why your code is slower in solution 2 with forEach
is because 1. you're using a join
which will execute an array join on every iteration (essentially creating a factorial loop) and also 2. you're using string concatenation which will be slower than interpolation, as the comment on your question have already mentioned. Solution 1 is just linear with a bit extra for adding new items to an array, which is negligible.
QUESTION
Bob Chester
Janitor
Click Here For Bio
...ANSWER
Answered 2021-Jul-15 at 14:40Like this
closest is the keyword
Here I delegate from the nearest static container. Your container will be different, so change document.getElementById("container")
to a relevant container
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