Chester | Chester is a Swift GraphQL query builder | GraphQL library

 by   JanGorman Swift Version: 0.16.0 License: MIT

kandi X-RAY | Chester Summary

kandi X-RAY | Chester Summary

Chester is a Swift library typically used in Web Services, GraphQL applications. Chester has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Chester is a Swift GraphQL query builder.
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            kandi-support Support

              Chester has a low active ecosystem.
              It has 100 star(s) with 15 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 3 have been closed. On average issues are closed in 10 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Chester is 0.16.0

            kandi-Quality Quality

              Chester has 0 bugs and 0 code smells.

            kandi-Security Security

              Chester has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Chester code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Chester is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Chester releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            Chester Key Features

            No Key Features are available at this moment for Chester.

            Chester Examples and Code Snippets

            No Code Snippets are available at this moment for Chester.

            Community Discussions

            QUESTION

            Is there an R function to help turn State abbreviations into full names? Or Vice Versa?
            Asked 2022-Apr-18 at 03:52

            I have two large-ish data frames I am trying to append...

            In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.

            In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.

            Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.

            Edit: dput(df2)

            ...

            ANSWER

            Answered 2022-Apr-18 at 03:52

            Here's one way you could turn state abbreviations into state names using R's built in state vectors:

            Source https://stackoverflow.com/questions/71907258

            QUESTION

            Why does python print memory location rather than class.name in some cases but not others in my code?
            Asked 2022-Feb-11 at 14:18

            My code has a mathematical function that iterates over a list of county class objects and returns the county with the max voter turnout along with that turnout in a tuple.

            Code here:

            ...

            ANSWER

            Answered 2022-Feb-11 at 14:05

            There is bug in your code. In first line, you are assigning whole County object to the max_county_variable

            Source https://stackoverflow.com/questions/71081293

            QUESTION

            Fandom-py: Unable to get image by using page.images[0]
            Asked 2022-Feb-01 at 09:46

            I'm using fandom module in python for my discord bot. I get this error when I request data by using page.images[0]. It should be an image url. This is the page I want to get.

            ...

            ANSWER

            Answered 2022-Feb-01 at 09:46

            I fixed it by using pymediawiki module.

            This code that use mediawiki can replace fandom module by changing the api of wiki.

            Source https://stackoverflow.com/questions/70863772

            QUESTION

            R Shiny: How to change title of plot based on number of inputs selected in selectizeInput
            Asked 2021-Dec-08 at 15:49

            I have an app that I'd like to be able to have the title change once there is more than 1 input selected in a selectizeInput. I know this is a simple thing but I can't seem to figure it out!

            Sample of data:

            ...

            ANSWER

            Answered 2021-Dec-08 at 15:49

            Made slight changes in sample data and code:

            Source https://stackoverflow.com/questions/70263437

            QUESTION

            Cannot read property 'startLine' of undefined : conversion from Pine Script vs4 to vs5
            Asked 2021-Dec-06 at 15:14

            I am trying to convert the indicator below from Pine Script vs4 to vs5. The error message is the following: "Conversion failed, reason: line 324: Cannot read property 'startLine' of undefined". It seems that there is something wrong with the plot function.

            Does anybody have an idea of how this error could be fixed?

            Thank you

            ...

            ANSWER

            Answered 2021-Dec-06 at 15:14

            Seems to be related to color=na. Replace it with color=color(na) (Pine has a built-in mass Find and Replace via Ctrl+F) and the script should convert correctly.

            Source https://stackoverflow.com/questions/70247522

            QUESTION

            Receiving PHP contact form error (Please complete the form and try again. )
            Asked 2021-Nov-11 at 22:37

            I am creating a contact form with 5 fields which will email the input details to a set e-mail but when the form is submitted i,m receiving error! Please complete the form and try again. here is php code, js and htm form. Any help would be much appreciated.

            html Form:

            ...

            ANSWER

            Answered 2021-Nov-11 at 22:35

            QUESTION

            ValueError: All arrays must be of the same length append data in data frame
            Asked 2021-Oct-07 at 12:22
            import requests
            from bs4 import BeautifulSoup
            import pandas as pd
            headers ={
                'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.114 Safari/537.36'
            }
            productlink=[]
            n=[]
            a=[]
            re=[]
            ra=[]
            w=[]
            
            r =requests.get('https://www.houzz.com/professionals/general-contractor')
            soup=BeautifulSoup(r.content, 'html.parser')
            tra = soup.find_all('div',class_='hz-pro-search-result__info')
            for pro in tra:
                name=pro.find('span',class_='mlm header-5 text-unbold').text
                n.append(name)
                address=pro.find('span',class_='hz-pro-search-result__location-info__text').text
                a.append(address)
                reviews=pro.find('span',class_='hz-star-rate__review-string').text
                re.append(reviews)
                rating=pro.find('span',class_='hz-star-rate__rating-number').text
                ra.append(rating)
            for links in tra:
                for link in links.find_all('a',href=True)[2:]:
                        if link['href'].startswith('https://www.houzz.com/professionals/general-contractors'):
                            productlink.append(link['href'])
            
            for link in productlink:
                r =requests.get(link,headers=headers)
                soup=BeautifulSoup(r.content, 'html.parser')
                for web in soup.find_all('a',attrs={'class':'sc-62xgu6-0 jxCcwv mwxddt-0 bSdLOV hui-link trackMe'}):
                    w.append(web['href'])
            df = pd.DataFrame({'name':n,'address':a,'reviews':re,'rating':ra,'web':w})
            print(df)
            
            ...

            ANSWER

            Answered 2021-Oct-07 at 12:22

            Make it as simple as possible and do not store the information from different loops in these bunch of lists, try to store them in one dict:

            possible solution

            Source https://stackoverflow.com/questions/69480501

            QUESTION

            How to unnest multiple columns while including nulls
            Asked 2021-Sep-24 at 20:47

            I have a table that looks like:

            id site_names site_addresses industries feis 30 Borden Incorporated 198 Saluda St , Chester , SC , 29706-1579 , United States|198 Saluda St, Chester, SC 29706, USA|198 Saluda St Chester SC 29706-1579 United States Food and Cosmetics 12345|45678 31 Butterkrust Bakeries, Inc.|Flowers Baking Co. of Lakeland, LLC|Southern Bakeries, Inc. dba Butterkrust Bakeries null Food|Food and Cosmetics 12345 33 Church & Dwight Canada Corp. 5485 RUE FERRIER , , MONTREAL, QUEBEC Quebec , , -- , CA null null

            I want to split the table into a materialized view where each row is one of the combinations possible when you split site_names, site_addresses, industries, and feis up. So for example, a few rows from this data would be:

            id site_name site_address industry fei 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 45678 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 45678 ... 31 Butterkrust Bakeries, Inc. null Food 12345 31 Flowers Baking Co. of Lakeland, LLC null Food 12345

            I have tried several ways to accomplish this. The closest I got was with this code:

            ...

            ANSWER

            Answered 2021-Sep-24 at 20:47

            If you want all combinations, you can use a single query:

            Source https://stackoverflow.com/questions/69317331

            QUESTION

            Why is array.map nested within array.forEach so much faster (in this case) than the other way around?
            Asked 2021-Aug-07 at 14:09

            I have a page that gives the user the ability to filter store locations by clicking on links for Region and Individual Shops nested within those Regions. Every click updates an object containing which filters have been applied, hides all the elements and then shows only the filtered set of elements.

            My code in this post takes the data from the filters object and creates a CSS selector string to which the jQuery .show() method can applied.

            I tried doing it 2 different ways thinking there wouldn't be much of a difference in performance, but to my surprise, jsbench.me showed Solution #2 (below) to be ~90% slower, and I'm baffled as to why.

            Here is the code that creates the CSS selector string for each solution. They both use the same object representing the current active filters. They can be found in this Codepen as well (variables are named slightly differently, but the code is the same as below).

            Example Active Filters Object ...

            ANSWER

            Answered 2021-Aug-07 at 13:21

            The difference between forEach and map won't really be significant, forEach will likely have a slight edge since it doesn't have to create a new array but that's just a guess. The reason why your code is slower in solution 2 with forEach is because 1. you're using a join which will execute an array join on every iteration (essentially creating a factorial loop) and also 2. you're using string concatenation which will be slower than interpolation, as the comment on your question have already mentioned. Solution 1 is just linear with a bit extra for adding new items to an array, which is negligible.

            Source https://stackoverflow.com/questions/68692649

            QUESTION

            How to I get the innerHTML of the closest H3 from the clicked element?
            Asked 2021-Jul-15 at 14:40
            
              Bob Chester
              Janitor
              
                Click Here For Bio
              
            
            
            ...

            ANSWER

            Answered 2021-Jul-15 at 14:40

            Like this

            closest is the keyword

            Here I delegate from the nearest static container. Your container will be different, so change document.getElementById("container") to a relevant container

            Source https://stackoverflow.com/questions/68395810

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Chester

            Chester is available through CocoaPods. To install it, simply add the following line to your Podfile:.

            Support

            @resultBuilder seems like a natural match for this kind of task. There's a separate GraphQLBuilderTests test suite that shows the supported cases. In its basic form you can construct a query like this:.
            Find more information at:

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