Hummingbird | A macOS utility that makes window management a breeze

 by   finestructure Swift Version: 2.0.0(3) License: MIT

kandi X-RAY | Hummingbird Summary

kandi X-RAY | Hummingbird Summary

Hummingbird is a Swift library. Hummingbird has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Hold down a modifier key combination like (control + option) and move you mouse pointer over a window to "grab" it anywhere to move it. Similarly, hold down another modifier key combination to resize the window as if you were dragging from the bottom right window corner from within anywhere in the window. Hummingbird brings the move and resize behaviour known from Unix window managers to macOS. In the video above, holding fn and ctrl while moving the mouse moves the window, and holding alt in addition allows the window to be resized simply by moving the mouse pointer. This is great for mouse users but is particularly helpful when using a trackpad, where clicking and holding can be a harder gesture to perform precisely.
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              Hummingbird has a low active ecosystem.
              It has 181 star(s) with 19 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 7 open issues and 23 have been closed. On average issues are closed in 104 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Hummingbird is 2.0.0(3)

            kandi-Quality Quality

              Hummingbird has no bugs reported.

            kandi-Security Security

              Hummingbird has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Hummingbird is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Hummingbird releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Hummingbird
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            Hummingbird Key Features

            No Key Features are available at this moment for Hummingbird.

            Hummingbird Examples and Code Snippets

            No Code Snippets are available at this moment for Hummingbird.

            Community Discussions

            QUESTION

            RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category
            Asked 2021-Jun-07 at 16:04

            I'm working on an October CMS project which use a blog where I need to seperate blog posts in two major categories. When listing blog posts using the RainLab.Blog plugin's Post List component, I need to list categories that are sub-categories under a specific top-level category and exclude other categories.

            In the TWIG template, I want to iterate through and list out the categories that belong to "Birds" and not "Sealife".

            In the default Post List component, categories are listed like this:

            ...

            ANSWER

            Answered 2021-Jun-07 at 16:04

            If it's totally fine to hardcode category then you can simply compare categories parent's slug or id to hardcoded value.

            Here I am using the slug to compare parent, you can also use id it's totally up to you.

            Source https://stackoverflow.com/questions/67866066

            QUESTION

            Adding supervisor and other info into bookdown pdf_book
            Asked 2021-May-05 at 09:02

            I want to include my supervisor's name, course name etc. for my paper written in bookdown. I specifically want this information to be in different lines. So far I have tried this in the yaml:

            ...

            ANSWER

            Answered 2021-May-05 at 09:02

            Using a "line block" should do the trick:

            Source https://stackoverflow.com/questions/67397354

            QUESTION

            OS Error in the listdir function of os module
            Asked 2021-Apr-14 at 08:14

            I am learning the os module of python, where I wrote the following code to try out the functions of the module.

            Input:

            ...

            ANSWER

            Answered 2021-Apr-14 at 06:34

            In python, the backslash is used as an ignore symbol. So after each backslash add another backslash

            Source https://stackoverflow.com/questions/67086612

            QUESTION

            Button Placement on split screen design
            Asked 2020-Aug-22 at 14:14

            Im playing around with bootstrap and i've come up against something I am struggling to find an answer to.

            I want to put a 'Login' on the bottom right of the screen, near the fold. Below is my code:

            ...

            ANSWER

            Answered 2020-Aug-22 at 14:14

            QUESTION

            Python: nested dictionary problem: trying to run a 'if' command to print out a string
            Asked 2020-Jul-19 at 06:01

            I am trying to do following 2 things for this nested dictionary:

            1. If a bird is aggressive, print out a string advising us to 'cover our heads' using the 'actions' list in this print statement.

            2. If a bird is endangered, print out a string advising us to 'back away', also using the actions list in this print statement.

            Here's what I have so far. Any help is much appreciated!:

            ...

            ANSWER

            Answered 2020-Jul-19 at 04:49
            final_actions={}
            for key, value in rarebirds.items():
                if final_actions.get(key)==None:
                    final_actions[key]=[]
                if 'Aggressive' in value and value.get("Aggressive")==True:
                    final_actions[key].append(actions[1])
                if 'Endangered' in value and value.get("Endangered")==True:
                    final_actions[key].append(actions[0])
                if ('Aggressive' in value and value.get("Aggressive")==False) and ('Endangered' in value and value.get("Endangered")==False):
                    final_actions[key].append(actions[2])
            print(final_actions)
            

            Source https://stackoverflow.com/questions/62976274

            QUESTION

            Display Only More Than One Unique Customer/Address Per Truck Number
            Asked 2020-Apr-29 at 15:40

            Been working on a project in which a report will generated from the SQL Query. I wish to display all Shipments (based on unique automatic truck ID) which contain any combination of:

            • Unique Customers (based on Customer Number, more than one Customer Number per shipment)
            • Unique Addresses (based on defined Address Field, more than one unique Address per shipment)

            The output should look like this when the code runs correct:

            ...

            ANSWER

            Answered 2020-Apr-29 at 15:40
            SELECT * FROM (SELECT DISTINCT shp.shipmentID
                                                                   , ven.CustomerCode
                                                                   , ven.CustomerName
                                                                   , ads.FirstAddress
                                                                   , ads.SecondAddress
                                                                   , ads.ThirdAddress
                                                                   , ads.City
                                                                   , ads.State
                                                                   , ads.Zip
                                                                   , CASE WHEN(ads.Country LIKE 'US') THEN N'USA' ELSE 'CANADA' END AS Country
                                                                   , COUNT (shp.shipmentID) OVER (PARTITION BY shipmentID ORDER BY shp.shpID) AS cntshpID
            
            
                                    FROM dbo.OrderItems AS ori
                                    JOIN dbo.OrderLineProducts AS olns ON olns.olnID = ori.olnID
                                    JOIN dbo.OrderLines AS oln ON oln.olnID = olns.olnID
                                    JOIN dbo.Orders AS ord ON oln.ordID = ord.ordID
                                    JOIN dbo.VendorCustomer AS ven ON ven.venID = ord.venID
                                    JOIN dbo.OrderAddresses AS oa ON oa.ordID = ord.ordID
                                    JOIN dbo.Address AS ads ON ads.addID = oa.addID
                                    JOIN dbo.AddressType AS adst ON adst.atcID = ads.atcID
                                                                   AND adst.atcAddressTypeCode = N'SHIP'
                                    JOIN dbo.OrderItemShipments AS shpo ON ori.itmID = shpo.itmID
                                                                   AND ori.itmIDInstance = shpo.itmIDInstance
                                                                   AND ori.olnID = shpo.olnID
                                                                   AND ori.olnIDInstance = shpo.olnIDInstance
                                    JOIN dbo.Shipments AS shp ON shp.shpID = shpo.shipmentID
                                    WHERE shpo.shpID = shp.shipmentID
            
                                    GROUP BY shp.shipmentID
                                                     , ven.CustomerCode
                                                     , ven.CustomerName
                                                     , ads.FirstAddress
                                                     , ads.SecondAddress
                                                     , ads.ThirdAddress
                                                     , ads.City
                                                     , ads.State
                                                     , ads.aZip
                                                     , ads.Country) AS bb
            
            WHERE bb.cntshpID > 1
            
            ORDER BY shpID ASC
            

            Source https://stackoverflow.com/questions/61488423

            QUESTION

            How to extract key value from a JS object through a common function?
            Asked 2020-Jan-01 at 11:15

            I try to extract a value from JS object.

            Here is my data -

            ...

            ANSWER

            Answered 2020-Jan-01 at 08:21

            You don't need a for loop. If you know the structure of your object, then you can simple do the following:

            Source https://stackoverflow.com/questions/59550869

            QUESTION

            The same Flutter web build runs locally with `dhttp` but fails with `firebase serve` or `firebase deploy`
            Asked 2019-Dec-21 at 13:50

            I'm developing a Flutter app for both mobile and web. It uses several packages, including those for Firestore:

            ...

            ANSWER

            Answered 2019-Dec-18 at 16:59

            Try to modify your web/index.html

            from

            Source https://stackoverflow.com/questions/59342808

            QUESTION

            GCP error reporting stacktrace sample is not detected
            Asked 2019-Dec-10 at 09:44

            I'm currently trying to implement the GCP error reporting for a Symfony project (PHP) in order to report any errors especially the stack trace of the application. The implementation is done by using the Google Cloud Client Library. However it appear that GCP is not detecting the stacktrace that I'm sending. Below is a screenshot of how it look like on the interface:

            As documented in this documentation. I have to precise the type of message that I'm sending to the ReportedEventError (If i'm not mistaken the message should be prefix by the 'PHP Fatal Error') string in order for the message to be recognized as a stacktrace. But that didn't worked.

            In order for you to help me solve my issues below is the JSON paylaod of what is send by the Google Cloud Client Library.

            ...

            ANSWER

            Answered 2019-Dec-10 at 09:44

            The issue I had was that I used the Symfony default's method to print the error. In order to resolve this issue I replace this piece of code

            Source https://stackoverflow.com/questions/59251709

            QUESTION

            Write csv to google cloud storage
            Asked 2019-Nov-21 at 18:09

            I am trying to understand how to write a multiple line csv file to google cloud storage. I'm just not following the documentation

            Close to here: Unable to read csv file uploaded on google cloud storage bucket

            Example:

            ...

            ANSWER

            Answered 2019-Nov-21 at 18:09

            The blob.upload_from_string(data) method creates a new object whose contents are exactly the contents of the string data. It overwrites over existing objects rather than appending.

            The easiest solution would be to write your whole CSV to a temporary file and then upload that file to GCS with the blob.upload_from_filename(filename) function.

            Source https://stackoverflow.com/questions/43601294

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Hummingbird

            Hummingbird has been tested on macOS 10.14 Mojave and 10.15 Catalina but it should run on earlier macOS versions as well (macOS 10.11 or higher).
            Download the latest release from the Hummingbird home page
            Unzip and run!

            Support

            Hummingbird is open source but if you'd like to support the app or simply don't want to bother building it yourself, please head over to https://hbird.app to download the commercial version. It comes with a 14 day free trial and you can purchase a license through the website or from within the app.
            Find more information at:

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            CLONE
          • HTTPS

            https://github.com/finestructure/Hummingbird.git

          • CLI

            gh repo clone finestructure/Hummingbird

          • sshUrl

            git@github.com:finestructure/Hummingbird.git

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