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kandi X-RAY | exy Summary
kandi X-RAY | exy Summary
Xcode’s build system has a few building blocks:. These can be configured in a number of ways. But one arrangement is particularly powerful: a workspace of interdependent projects. By building through a workspace, you can choose between building all targets at once or building them individually. exy uses xcodebuild to build the projects in a workspace individually, making the products available to the projects that depend on them. But it caches products to avoid recompiling unchanged targets. This enables fast, reliable builds on CI—most of the speed of dirty builds with the reliability of clean builds.
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QUESTION
I have a piece of code of type:
...ANSWER
Answered 2020-Jul-09 at 07:33For start you can reuse the first calculation:
QUESTION
I am writing a university project, where I take two algorithms and compare their performance, the main algorithms are Dijkstra and A*, however I am not very experienced with either Vue.js, JS in general and algorithms, and my first iteration of Dijkstra is SUPER slow. I am using a 2D grid of X by Y, with a start point node and an end point node, and running the algorithm. Any grid above 10x10 is completely too slow.
I am at a loss on what to do, I don't see any errors when running the code, it executes, but executes entirely too slow. I am not very experienced, so I don't know where to start to look and what the issue could be. Maybe there's someone with experience that could help out and tell me what I'm doing wrong?
...ANSWER
Answered 2020-May-05 at 14:17Although you seem to suggest that your algorithm works, but too slow, it actually has at least one blocking error:
for (let node in toChecknext): this will iterate the indexes of the array, not the values. Yet you treat those values as nodes, which will lead to undesired behaviour. Change to:
QUESTION
I'm trying to retrieve a long and complex token from the url in my Angular app.
An example url could look like the following (notice the id and token params):
While I can use the Query Param map to retrieve my values, Angular seems to be playing with the data :/
...ANSWER
Answered 2020-Apr-10 at 05:35Try encodeURIComponent
QUESTION
I am trying to use the domain I just purchased in Route 53 to point to an application running in Elastic Beanstalk exy.elasticbeanstalk.com
If the domain I purchased is example.com and I want traffic to point to my application in Elastic Beanstalk, How can I achieve this?
So going to example.com launches the exy.elasticbeanstalk.com
...ANSWER
Answered 2020-Jan-18 at 23:58In Route 53, alias records can be used at the root domain (also known as the zone apex) to refer to an Elastic Beanstalk Environment.
From Choosing Between Alias and Non-Alias Records:
Amazon Route 53 alias records provide a Route 53–specific extension to DNS functionality. Alias records let you route traffic to selected AWS resources, such as CloudFront distributions and Amazon S3 buckets. They also let you route traffic from one record in a hosted zone to another record. Unlike a CNAME record, you can create an alias record at the top node of a DNS namespace, also known as the zone apex. For example, if you register the DNS name example.com, the zone apex is example.com. You can't create a CNAME record for example.com, but you can create an alias record for example.com that routes traffic to www.example.com.
For for more details regarding Alias records and Elastic Beanstalk see https://docs.aws.amazon.com/Route53/latest/DeveloperGuide/resource-record-sets-values-alias.html#rrsets-values-alias-alias-target
QUESTION
I want to create an app that shows me the value of a certain coin. I use KuCoin API. When I request pricing info, i get this response:
...ANSWER
Answered 2019-Dec-01 at 22:40If you declare the FiatPrices class with a dictionary, JsonConvert will automatically deserialize into this dictionary.
QUESTION
I have a pinescript strategy below in which I am trying to calculate the Pearsons R correlation value. I got the code from here and modified it a bit (https://www.tradingview.com/script/CD7yUWRV-Linear-Regression-Trend-Channel/).
His code does not include the Pearson's R correlation which is very important to the trading strategy I'm trying to use since it indicates the strength of the trend and it's direction (up or down). To see a working examle of the Pearson's R, add the default indicator linear regression and it will be the number to the bottom left. I'll attach a screenshot for an example.
How do I calculate the Pearson's R Value from the code I have so far?
I have looked for sample pine scripts that have the Pearson's R calculation for linear regression in pinescript and could not find anything.
...ANSWER
Answered 2019-Nov-26 at 22:58// This source code is subject to the terms of the Mozilla Public License 2.0 at https://mozilla.org/MPL/2.0/
// © x11joe
// Credit given to @midtownsk8rguy for original source code. I simply modified to add Pearson's R
//@version=4
study("Linear Regression Trend Channel With Pearson's R", "LRTCWPR", true, format.inherit)
period = input( 20, "Period" , input.integer, minval=3)
deviations = input( 2.0, "Deviation(s)" , input.float , minval=0.1, step=0.1)
extendType = input("Right", "Extend Method", input.string , options=["Right","None"])=="Right" ? extend.right : extend.none
periodMinusOne = period-1
Ex = 0.0, Ey = 0.0, Ex2 = 0.0,Ey2 =0.0, Exy = 0.0, for i=0 to periodMinusOne
closeI = nz(close[i]), Ex := Ex + i, Ey := Ey + closeI, Ex2 := Ex2 + (i * i),Ey2 := Ey2 + (closeI * closeI), Exy := Exy + (closeI * i)
ExT2 = pow(Ex,2.0) //Sum of X THEN Squared
EyT2 = pow(Ey,2.0) //Sym of Y THEN Squared
PearsonsR = (Exy - ((Ex*Ey)/period))/(sqrt(Ex2-(ExT2/period))*sqrt(Ey2-(EyT2/period)))
ExEx = Ex * Ex, slope = Ex2==ExEx ? 0.0 : (period * Exy - Ex * Ey) / (period * Ex2 - ExEx)
linearRegression = (Ey - slope * Ex) / period
intercept = linearRegression + bar_index * slope
deviation = 0.0, for i=0 to periodMinusOne
deviation := deviation + pow(nz(close[i]) - (intercept - slope * (bar_index[i])), 2.0)
deviation := deviations * sqrt(deviation / periodMinusOne)
startingPointY = linearRegression + slope * periodMinusOne
var label pearsonsRLabel = na
label.delete(pearsonsRLabel[1])
pearsonsRLabel := label.new(bar_index,startingPointY - deviation*2,text=tostring(PearsonsR), color=color.black,style=label.style_labeldown,textcolor=color.white,size=size.large)
var line upperChannelLine = na , var line medianChannelLine = na , var line lowerChannelLine = na
line.delete(upperChannelLine[1]), line.delete(medianChannelLine[1]), line.delete(lowerChannelLine[1])
upperChannelLine := line.new(bar_index - period + 1, startingPointY + deviation, bar_index, linearRegression + deviation, xloc.bar_index, extendType, color.new(#FF0000, 0), line.style_solid , 2)
medianChannelLine := line.new(bar_index - period + 1, startingPointY , bar_index, linearRegression , xloc.bar_index, extendType, color.new(#C0C000, 0), line.style_solid , 1)
lowerChannelLine := line.new(bar_index - period + 1, startingPointY - deviation, bar_index, linearRegression - deviation, xloc.bar_index, extendType, color.new(#00FF00, 0), line.style_solid , 2)
QUESTION
So before I begin here's the code:
...ANSWER
Answered 2019-Nov-14 at 20:42The parenthesis in the correlation formula is not correct. In your code, only a part of the numerator is actually divided by the denominator. Moreover, the formula for the denominator is not quite right. Try this:
QUESTION
I built my own custom indicator that calculates the approximate slope and acceleration of a chart using the previous X number of bars.
When I attach the indicator to a chart it works as expected, but when I try to retrieve the latest value within an EA using iCustom() it only returns 2147483647.
I've already tried using different values for the iCustom() shift parameter without success.
ANSWER
Answered 2019-Aug-24 at 00:31I figured out the issue.
This line was the culprit.
i = Bars - counted_bars - delta;
Once the indicator had "caught up" with all of the completed bars on the chart that would leave i equal to 1 - delta which would be negative. The result was that the while loop would never run.
QUESTION
I habitually use csvRead in scilab to read my data files however I am now faced with one which contains blocks of 200 rows, preceeded by 3 lines of headers, all of which I would like to take into account.
I've tried specifying a range of data following the example on the scilab help website for csvRead (example is right at the bottom of the page) (https://help.scilab.org/doc/6.0.0/en_US/csvRead.html) but I always come out with the same error messages :
The line and/or colmun indices are outside of the limits
or
Error in the column structure.
My first three lines are headers which I know can cause a problem but even if I omit them from my block-range, I still have the same problem.
Otherwise, my data is ordered such that I have my three lines of headers (two lines containing a header over just one or two columns, one line containing a header over all columns), 200 lines of data, and a blank line - this represents data from one image and I have about 500 images in the file, I would like to be able to read and process all of them and keep track of the headers because they state the image number which I need to reference later. Example:
...ANSWER
Answered 2018-Jul-31 at 18:09A lot's of your problem comes from the inconsistency of the number of coma in your csv file. Opening it in LibreOffice Calc and saving it puts the right number of comma, even on empty lines.
Your current code doesn't position R1 at the beginning of the values. The right formula is
QUESTION
I run my app on google nexus 10 inch device, whenever app is launch i got this issue,app is not crashing but got this. here is stactrace
...ANSWER
Answered 2018-Mar-01 at 10:45Looks like you are running your app with a proxy. Try doing the same on a open network and check if the error is still showing.
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