Polyline | Polyline encoder / decoder in swift

 by   raphaelmor Swift Version: v5.0.3 License: MIT

kandi X-RAY | Polyline Summary

kandi X-RAY | Polyline Summary

Polyline is a Swift library. Polyline has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

To use this library in your project you can use CocoaPods, Carthage, Swift Package Manager, and/or integrate it manually :.
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              Polyline has a low active ecosystem.
              It has 245 star(s) with 40 fork(s). There are 9 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 5 open issues and 25 have been closed. On average issues are closed in 46 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Polyline is v5.0.3

            kandi-Quality Quality

              Polyline has 0 bugs and 0 code smells.

            kandi-Security Security

              Polyline has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Polyline code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Polyline is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Polyline releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            Polyline Key Features

            No Key Features are available at this moment for Polyline.

            Polyline Examples and Code Snippets

            Checks to see if a list is a polyline
            javadot img1Lines of Code : 17dot img1no licencesLicense : No License
            copy iconCopy
            public boolean isPalindrome(ListNode head) {
                    ListNode mid = middleNode(head);
                    ListNode headSecond = reverseList(mid);
                    ListNode rereverseHead = headSecond;
            
                    // compare both the halves
                    while (head != null &&a  
            This method recursively finds a polyline character
            javadot img2Lines of Code : 11dot img2License : Permissive (MIT License)
            copy iconCopy
            private boolean recursivePalindrome(String text, int forward, int backward) {
                    if (forward == backward)
                        return true;
                    if ((text.charAt(forward)) != (text.charAt(backward)))
                        return false;
                    if (forward <   

            Community Discussions

            QUESTION

            Cypress - iframes - Unable to target second field, the test hangs then times out
            Asked 2022-Mar-16 at 18:29

            I'm coming across an issue where once my test card number is typed into the first iframe the test tries to target the 2nd iframe (CVC) & it times out whilst trying to target the element. All info is listed below. Any help to why this is failing is appreciated!

            Custom commands used:

            ...

            ANSWER

            Answered 2022-Feb-15 at 19:59

            @BillBaily Thanks but I was looking for a larger piece of HTML, covering both iframes.

            But another suggestion - I have seen on another project that uses WorldPay has nested iframes, so you would need something like

            Source https://stackoverflow.com/questions/71067739

            QUESTION

            Python star symbol in a loop
            Asked 2022-Jan-07 at 12:33

            I am using CPython and I saw in one example file with a star symbol. Could you give an explanation what in this context the * symbol means? Here the pointsets is a numpy array that comes from pybind11, because it is an output of C++ code.

            Does the Point(*point) has something to do with the pointers in C++?

            ...

            ANSWER

            Answered 2022-Jan-07 at 12:33

            It's called unpacking operator. Here is what's written in the docs:

            An asterisk * denotes iterable unpacking. Its operand must be an iterable. The iterable is expanded into a sequence of items, which are included in the new tuple, list, or set, at the site of the unpacking.

            It is much like the "..." operator from Javascript ES6. (the spread operator)

            https://docs.python.org/3/reference/expressions.html#expression-lists

            Source https://stackoverflow.com/questions/70621142

            QUESTION

            Draw Graph Diagram with WPF in C# Properly
            Asked 2021-Dec-17 at 11:53

            How can this code produce a similar Graph Diagram as the other one? I have posted my entire code, if someone is an expert on this, share your input. I don't understand drawing fully in WPF! I am still reading on the topic.

            My Code:

            ...

            ANSWER

            Answered 2021-Dec-17 at 11:53

            You were on the right path to resolve it, I used your code as guideline.

            So, 1st here is the code that provide your desired result,

            This goes to the MainWindow xaml:

            Source https://stackoverflow.com/questions/70337253

            QUESTION

            Calculate trips in Google BigQuery
            Asked 2021-Dec-02 at 14:40

            Lets assume that there is the following BigQuery database:

            asset_id latitude longitude trip_status timestamp 2 52.1052016 10.141829999999999 false 1638274080 2 52.10512 10.1420266 false 1638274081 2 52.104774899999995 10.1427066 true 1638274085 2 52.1044833 10.1431966 true 1638274088 2 52.104156599999996 10.143821599999999 true 1638274092 2 52.10398 10.1441433 true 1638274094 2 52.1038016 10.1444783 true 1638274096 2 52.1036183 10.144823299999999 true 1638274098 2 52.1034333 10.1451783 true 1638274100 2 52.1032483 10.1455383 false 1638274102 2 52.1030533 10.145886599999999 true 1638274104 2 52.1028666 10.146175 true 1638274106 2 52.10279 10.1463266 true 1638274108 2 52.1026616 10.1466566 true 1638274110 2 52.102464999999995 10.147016599999999 true 1638274112 2 52.102215 10.1474083 true 1638274114 2 52.101968299999996 10.147795 true 1638274116 2 52.101756599999995 10.148195 false 1638274117 2 52.101538299999994 10.14864 false 1638274119 2 52.1013583 10.149076599999999 false 1638274121

            In provided data there is a flag - trip_status, indicating, whether the given coordinates have been captured during the trip mode.

            • trip_status value changing from false to true indicates the start of the trip.
            • trip_status value changing from true to false indicates the end of the trip.
            • All consecutive rows with trip_status = true are rows belonging to the same trip

            Question:

            Is there a way in BigQuery to extract separate trips from such dataset? Maybe somehow group data where trip_status flag is true and return as a separate datasets?

            For example, from given data, I need to retrieve something like:

            Trip 1:

            asset_id latitude longitude trip_status timestamp 2 52.104774899999995 10.1427066 true 1638274085 2 52.1044833 10.1431966 true 1638274088 2 52.104156599999996 10.143821599999999 true 1638274092 2 52.10398 10.1441433 true 1638274094 2 52.1038016 10.1444783 true 1638274096 2 52.1036183 10.144823299999999 true 1638274098 2 52.1034333 10.1451783 true 1638274100

            Trip 2:

            asset_id latitude longitude trip_status timestamp 2 52.1030533 10.145886599999999 true 1638274104 2 52.1028666 10.146175 true 1638274106 2 52.10279 10.1463266 true 1638274108 2 52.1026616 10.1466566 true 1638274110 2 52.102464999999995 10.147016599999999 true 1638274112 2 52.102215 10.1474083 true 1638274114 2 52.101968299999996 10.147795 true 1638274116

            Or, even better, something like:

            row asset_id origin.latitude origin.longitude destination.latitude destination.longitude polyline start_timestamp end_timestamp 0 2 52.104774899999995 10.1427066 52.1034333 10.1451783 ST_MAKELINE from all trip coordinates 1638274085 1638274100 1 2 52.1030533 10.145886599999999 52.101968299999996 10.147795 ST_MAKELINE from all trip coordinates 1638274104 1638274116 ...

            ANSWER

            Answered 2021-Dec-01 at 00:22

            Consider below approach

            Source https://stackoverflow.com/questions/70172033

            QUESTION

            How to add a texture to the stroke of a Bezier curve in an svg?
            Asked 2021-Nov-25 at 15:10

            Not to fill a region bounded by a bezier curve and a line.

            E.g. here's a very simple stroked Bezier curve

            ...

            ANSWER

            Answered 2021-Nov-25 at 15:10

            As pointed out in the comment @Mike 'Pomax' Kamermans

            create a pattern definition with an id, then point to that by fragment identifier in the attribute

            I added the curve code and calculated the required dimensions for the pattern

            Source https://stackoverflow.com/questions/70102783

            QUESTION

            How can I merge cv2 rectangle bounding boxes into polygons? (Not by overlap/threshold)
            Asked 2021-Nov-14 at 18:00

            I have multiple rectangle bounding boxes that I know are part of the same object (parts of a newspaper article), as in the first image. I'm trying to work out a way to merge these into one polygon bounding box, for the whole article, as in the second image.

            I have seen lots of solutions based on merging overlapping bounding boxes, but I don't care if they're overlapping or not - I already know they're part of the same article. In some cases the headline is quite far away (for example above a picture), so solutions based on padding don't work either.

            I feel like there should be a cv2 function that does this, but if there is, I am missing it. Any suggestions would be super helpful.

            Code to create these two images:

            ...

            ANSWER

            Answered 2021-Nov-14 at 18:00

            You could draw the convex hull of the contour points (this was drawn by hand):
            (wrong convex hull image)
            Then keep only the outer contour and try the polygonal approximation. I must admit that I cannot think of a smarter way of getting only vertical and horizontal lines.

            As Christoph Rackwitz observed, I was wrong. Convex hull, doesn't work. Maybe an α-shape could solve the problem, but I'm not sure. An alternative approach could be to extract all the equations of the lines which define the bounding boxes, then for each point, compute the segment that connects it to the nearest line. If the line is part of the same bounding box or if the point falls outside of the bounding box, remove the segment.

            It was harder than I expected, because my Python OpenCV proficiency is not enough. Nevertheless you can get nearly what you wanted in the question:

            Source https://stackoverflow.com/questions/69934393

            QUESTION

            How to combine simulated animation with graphs in CodeWorld?
            Asked 2021-Oct-25 at 16:43

            I play with CodeWorld and use the "entrypoint" activityOf() to simulate a physical system consisting of tanks. Here we have one tank with an outlet flow qout(h) that depends on the height of volume level. Of course, for serious simulation work one should use other software, but still fun to do here!

            ...

            ANSWER

            Answered 2021-Oct-21 at 09:43

            I’ll respond using syntax and types form the “regular” Haskell environment, https://code.world/haskell.

            The type of a activityOf is:

            Source https://stackoverflow.com/questions/69631791

            QUESTION

            Need a programming algorithm for a tight enclosure around line segments
            Asked 2021-Sep-25 at 23:36

            I have a list of perhaps hundreds of unsorted 2D line segments at random angles as shown in blue above, and I need to determine the sorted sequence of points a – i from them as shown in red. Here are some constraints and observations:

            • The red polyline sequence a - i forms a tight enclosure of the outer points of all the segments. It's like a convex hull, but "sucked" into concavities. A tight enclosure of the entirety of all segments would be a fine solution; I can delete the unused parts.
            • An enclosure does exist. The segments are not completely random.
            • The y value of one point of each segment is 0, and the other end is a point on the enclosure.
            • The enclosure cannot cross any line segment or itself. This also means that all segments are on one side of the enclosure polyline.
            • There will be either one or two enclosure segments connected to each enclosure point a - i.
            • The points may be spaced widely differently, not as tidily as shown.
            • I should be able to determine point a or i if necessary to start off the algorithm.

            It seems like starting from a bounding box around all segments and shrinking it to form a tight enclosure would be a reasonable approach, but I can't come up with a decent algorithm. This will eventually be coded in C#, but an algorithm or pseudo-code would be fine.

            ...

            ANSWER

            Answered 2021-Sep-25 at 23:36

            History: this answer is now marked community wiki. The original conjecture was proven wrong by @dont talk just code. @Matt Timmermans provided the current conjecture in a comment under the question.

            The following conjecture is submitted without proof: To compare the order of two line segments, compare the bottom x, and return the opposite if the segments cross.

            If the conjecture holds, a comparator can be written for use with any comparison sort. Pseudocode for the comparator:

            Source https://stackoverflow.com/questions/69272475

            QUESTION

            im trying to put the text at the center in the rect of d3.js
            Asked 2021-Aug-17 at 13:51

            I'm using d3.js v6 to create a donut graph

            I have created the donut and everything the problem is regarding putting the text in rect as mentioned below

            Im hoping to achieve the expected result as shown in the image I've also attached the my current output image below

            Problem the only remaining thing that I wanted is the boxes to have the value center aligned

            ...

            ANSWER

            Answered 2021-Aug-17 at 13:51

            Fixed a few problems in your code:

            Source https://stackoverflow.com/questions/68816598

            QUESTION

            Rearranging License Plate characters based on country
            Asked 2021-Aug-12 at 21:00

            I am doing a License/Number plate recognition project and I'm on the stage of completion but there is a small problem, I have successfully recognized the characters, consider the below example:

            This is an input image, I got the prediction as 2791 2g rj14

            As you can, the ocr did a great job but the arrangement is destroyed (DESTROYING the whole purpose). Sometimes it does outputs in the correct sequence but sometimes it does not, so when it does not output in the correct sequence I'm trying to develop an algorithm which will take the predicted num_plate string as input and rearrange it on the basis of my country (India).

            Below are some images which tell us about the format of Indian Number/License Plate.

            Also, I have collected all the states but for right now, I just want to do for only the 3 states which are: Delhi (DL), Haryana (HR), UttarPradesh (UP). More info : https://en.wikipedia.org/wiki/List_of_Regional_Transport_Office_districts_in_India

            ...

            ANSWER

            Answered 2021-Aug-12 at 21:00

            If you can get the coordinates of each identified text box, then:

            • Rotate the coordinates so the boxes are parallel with the X-axis
            • Scale the Y-coordinates so they can be rounded to integers, so that boxes that are side-by-side will get the same integer Y-coordinate (like a line number)
            • Sort the data by Y, then X coordinate
            • Extract the texts in that order

            Here is an example of such sequence:

            Source https://stackoverflow.com/questions/68757237

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            You can download it from GitHub.

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