Postal | A Swift framework for working with emails | Web Framework library
kandi X-RAY | Postal Summary
kandi X-RAY | Postal Summary
Postal is a swift framework providing simple access to common email providers.
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Postal Examples and Code Snippets
Lines of Code : 3
License : No License
Copypublic String getPostalCode() {
return postalCode;
} public void setPostalCode(String postalCode) {
this.postalCode = postalCode;
} public void setPostalNumber(Integer postalNumber) {
this.postalNumber = postalNumber;
} Community Discussions
Trending Discussions on Postal
QUESTION
I am making an API call to a third party API, the code snippet was made to make a request and extract the response body from the response into a string in .Net 3.1. I can parse successful responses normally and successfully. We were able to parse WebException responses up to yesterday, where now they just return garbled string down below.
...ANSWER
Answered 2022-Apr-04 at 18:39After a lot of searching and digging I was able to determine that previously when creating the HttpWebRequest somewhere in the background it knew to automatically decompress Gzip for the responses. However, after some indeterminate point in time, that instruction was left out which resulted in parsing errors. Turns out it wasn't the result of incorrect codecs, or casting types or response calls, but that "Deflate Gzip" wasn't part of the request anymore afterwards.
Our fix was solved by making sure to add:
QUESTION
I have a MySQL table with area and lat/lon location columns. Every area has many locations, say 20.000. Is there a way to pick just a few, say 100, that look somewhat evenly distributed on the map?
The distribution doesn't have to be perfect, query speed is more important. If that is not possible directly with MySQL a very fast algorithm that somehow picks evenly distributed locations might also work.
Thanks in advance.
Edit: answering some requests in comments. The data doesn't have something that can be used, it's just area and coordinates of locations, example:
...ANSWER
Answered 2022-Mar-23 at 17:16Here's an approach that may satisfy the goals.
- Preprocess the table, making a new table, to get rid of "duplicate" items.
- If the new table is small enough, a full scan of it may be fast enough.
As for "duplicates", consider this as a crude way to discover that two items land in the same spot:
QUESTION
When listing the "House" Model inside the django admin panel i want to show all Houses but with the PostalCode inside list_display so i can sort them by postal code. Can i use the existing ForeignKey connection between House and HouseAddress to achieve this?
I found some information on how to list parts of the "Houses" inside the "House Addresses" list view (because it has the foreign key field) but not from the "Houses" list view.
Admin.py
...ANSWER
Answered 2022-Mar-03 at 14:20You might be able to achieve something close to what you need (or at least useful) with list_filter, using something like:
QUESTION
Hi I'm starting with python and have a question that sounds pretty simple, but at this point I don't know how to solve it. I have a code for splitting some reports by columns. Unfortunately, I noticed that the format in output files changes during the split compared to the master file.
__ Dates format changes from short date: 9/29/2005 to 2005-09-29 00:00:00
__ Also number format changes from currencies to 'standard' number: 172,057.60 to: 172057.60
I'm struggling to find a solution to this. So far, I have found a lot of formatting information, but I have failed to apply them to the entire columns of the output files. Also it is important that dates don't turn into strings. Would you help me rewrite the code to get exactly the same formatting as in the master file?
I think that the problem might be related with how .to_excel works, but I'm not sure.
...ANSWER
Answered 2022-Mar-03 at 08:20To set the date and/or datetime format in the pandas to_excel() output you will need to use an ExcelWriter object. Something like this:
QUESTION
I'm searching SQL Server using the following and I want to find a way to reduce the query size when it comes to the range of postal codes being searched:
...ANSWER
Answered 2022-Feb-28 at 15:28You could offload the bulk of your criteria to an exists check with the lookup terms in a separate table. An example would be:
QUESTION
I'm having trouble extracting some data properly and into a SQL db, which i'm hoping someone can help with. The data is scraped from a website and represents Dutch postal codes and cities
The official Dutch postal codes are composed of 4 digits, a space in between, and a 2 capital letter addition. For example
...ANSWER
Answered 2022-Feb-16 at 12:53Maybe this can help you, I have tested it a little bit with the list data. I split x on spaces and then check if the second part has 2 capital letters. with the regex pattern [A-Z]{2}. [A-Z] Means any capital letter, and {2} means that exactly 2 of those character must be found.
But in AAA also 2 of capital letters can be found.
The regex function search returns a Match object when a match has been found and otherwise None. If you turn it into a boolean with bool(), that's either True or False. This way you can add the check on the length with the len-function to it.
QUESTION
Its my first Question here, so be kind ^^ Im training myself some JS/Jquery/Ajax. Short: Projekt to filter closest location of a specific company to our current postal zip. So, here is my "work" so far: On index.php im using a simple form like this:
...ANSWER
Answered 2022-Feb-09 at 10:18A good way to do this is by using JSON.
On the PHP side, in ajax.php, you use json_encode() to encode your array as a string.
That JSON string is then received in your Javascript AJAX as the response. There you can turn it back into an array with JSON.parse():
QUESTION
ANSWER
Answered 2022-Feb-08 at 10:14The mongo driver will not magically find out which document field you want to set into which struct field.
There are some "common sense" rules, such as field names matching properties (even if the first letter is not capitalized), but the field name Cardname will not be matched with the property name "card name".
You have to tell the mapping using struct tags, namely the bson struct tag (this is what the mongo-go driver uses).
For example:
QUESTION
I have a deeply nested json as below :
...ANSWER
Answered 2022-Feb-07 at 18:39Try the below JSONPath
QUESTION
still, an absolute beginner didn't find a proper way to make this repeat I need to repeat this program without for loop I just need to go to start of program once and output is printed
...ANSWER
Answered 2022-Jan-30 at 15:01Since you do not want to use a loop you can go for a recursive function (which is a function which basically calls itself at a certain point of time)
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