denote | REST API with JWT authentication | REST library
kandi X-RAY | denote Summary
kandi X-RAY | denote Summary
REST API with JWT authentication for a generic notes app built with Deno, Oak, and TypeScript.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of denote
denote Key Features
denote Examples and Code Snippets
def get(identifier):
"""Returns function.
Args:
identifier: Function or string
Returns:
Function corresponding to the input string or input function.
For example:
>>> tf.keras.activations.get('softmax')
>&g
def deserialize(name, custom_objects=None):
"""Returns activation function given a string identifier.
Args:
name: The name of the activation function.
custom_objects: Optional `{function_name: function_obj}`
dictionary listing user
def cross_entropy(ref, other,
allow_nan_stats=True, name=None):
"""Computes the (Shannon) cross entropy.
Denote two distributions by `P` (`ref`) and `Q` (`other`). Assuming `P, Q`
are absolutely continuous with respect to one
Community Discussions
Trending Discussions on denote
QUESTION
I am modeling a Time-constrained CVRP. The problem is to minimize the total travel time (not including the package dropping time) subject to vehicle (delivery) capacity and total time spent (per vehicle) constraints. The package dropping time refers to an additional time to be spent at each node, and the total time spent equals to the travel time plus this additional time. I have the below model that works for a single vehicle-type case. I would like to introduce two-vehicle type concept in there, meaning that I have a set of V1
type vehicles and another set of V2
type vehicles. The only difference of the vehicle-types is the per time cost of travel. Let x
denote the per time unit cost of travel by V1
, and y
denote the per time unit travel cost of V2
. How can I design the model so that it incorporates this additional aspect?
ANSWER
Answered 2021-Jun-13 at 13:34Simply register two transits callbacks (i.e. one per vehicle type)
Then use the overload of AddDimension() to pass an array of registered transit callback index.
QUESTION
The regular OLS estimator is denoted as: b =(X'X)^{-1}X'y. My question is what if your model has more than one parameter b. In the image I have worked out the problem formulation for multiple parameter estimation using OLS.
...ANSWER
Answered 2021-Jun-14 at 12:31The general request in Stack Overflow is to please type things in rather than attach images. I found the image confusing in that you use the same symbol Y to denote two very different things -- a vector and a matrix. I'll use Z for the vector.
You want to find vectors a and b to best fit
QUESTION
My data set looks like that: (f denotes features, ID denotes customers)
I would like to count pairs of features that appear through all the customers IDs. For example in the above sample as seen I would like to get that (f1,f2) = 3 , (f2,f33)= 2 , (f3,f33)=0 and so on
...ANSWER
Answered 2021-Jun-14 at 11:35I am not sure if I understood what you want, but this is my suggestion:
QUESTION
I am implementing a words/2
predicate in which a list of characters can be rendered to a list of the character as a word inside a list. I use the mathematical symbol <=>
to denote that they're working in any mode. Please advise if there's a better expression.
The example:
...ANSWER
Answered 2021-Jun-07 at 14:32split(_, [], [[]]).
split(C, [C|Xs], [[]|Ys]) :-
split(C, Xs, Ys).
split(C, [X|Xs], [[X|Y]|Ys]) :-
split(C, Xs, [Y|Ys]).
QUESTION
Hi I'm trying to get this code block to run in the mainline of one of the examples provided with ESP-IDF (denoted by arrows)
...ANSWER
Answered 2021-Jun-11 at 08:13The root cause of this error is that the struct esp_netif_t
is a private type in the netif implementation. You're not supposed to create any objects of this type, only pass around handles (pointers) to it.
I suspect you've misunderstood what esp_netif_get_netif_impl_name()
does. According to the API doc it takes a handle to a esp_netif_t
and returns the name corresponding to this interface.
What you seem to be after is retrieving the handle to your interface in the first place. For this the (rather terse) API doc suggest a few other functions, e.g. esp_netif_get_handle_from_ifkey(...)
for searching for interfaces using something called interface key (no idea, sorry, but google helps there) or esp_netif_next(...)
for iterating over interfaces.
According to this forum post you might want to try something like this:
QUESTION
I have a small follow-up question to a previous one answered here. With a dummy dataset as included below, I would like to filter off rows in which one or more of the samples (denoted S1, S2, S3, S4 in the dataset) has only "1" and "0", as well as all rows where the samples have only 1", "0" and "."
ID Pos S1 S2 S3 S4 A 22 . 1 0 . B 21 1 0 . 1 C 50 0 . . . D 11 . 1 . . E 13 0 0 0 0 F 14 1 1 1 1 G 10 1 0 0 0In other words, I want to keep only those rows that either has "1" in all the samples, or "0" in all samples, or "1" and "." in all samples, or lastly those with "0" and "." such that at the end, I have the final dataset looking as below
ID Pos S1 S2 S3 S4 C 50 0 . . . D 11 . 1 . . E 13 0 0 0 0 F 14 1 1 1 1I am trying to do this in R and I request any suggestions from you.
Thanks and regards!
...ANSWER
Answered 2021-Jun-10 at 12:47dieveed, it's best if you provide your data with R's dput
function.
The way to do this in the tidyverse would be something like this:
QUESTION
It is a Medical Lab Software solution. A user makes lab investigation request that is unique to a patient’s encounter, I.e., a patient can have 1 or more request per encounter. This uniqueness is denoted by the encounter_id. The challenge now is the ability to send the results back to the requester.
I am able to display all requests per encounter_id on a template but unable to return the result since each result is tied to a particular investigation. This is largely because I have a limited knowledge on JS. My current approach can only submit one record, usually the last record
Here’s the URL that displays the result template: https://smart-care.herokuapp.com/labs/lab_results/1/
Here’s the django template:
...ANSWER
Answered 2021-Jun-10 at 09:27The problem that Django handles form elements based on name
attribute and not the id
attribute so this means you need to change name per request and on the view side you loop on all keys in request.POST like
QUESTION
After hours of trial and error, I've determined that doing an Application.Vlookup for a text string in a range returns:
- Error 2042 if the text in the search range isn't preceded by an apostrophe
- Returns a value in the search range if the text is preceded by an apostrophe
Both search variables are type 8, string, but only the range value with the apostrophe is considered equal, even though the string being searched for, does not have an apostrophe in it.
Is there a way to have Vlookup consider text without an apostrophe equal? And no, I'd rather not have to add an apostrophe to everything.
Thanks in advance.
PS Made a small program, using a different version of Excel but still getting undesired results...
Excel Program and VLookup results
In the spreadsheet, all the number values were entered by keyboard.
Then used the format cells option to change them to text.
Then added an apostrophe to the second text value '478901' as denoted by the green triangle, top left-hand corner of the cell.
Vlookup in C2 does not recognize A2 as text, even though it has been formatted as such.
Vlookup in C3 does recognize A3 as text and provides the returned value in column 2.
In the macro, the output pretty much says it all.
myData range is confirmed by address call.
VarType calls for values in A2 & A3 confirms excel is treating them as Double-precision floating-point number (5) and String (8), even though both have been formatted to text, although I suspect this is just for display purposes now.
The Application.Vlookup calls for the values in A2 and A3 return same as spreadsheet Vlookup calls.
In my earlier post, I said that both vartypes returned string (8) but that only the one with the apostrophe worked. This was with the work version of excel, which is earlier than this one. So it looks like someone tried to fix this issue or it just ended up different without attention. Either way, something is broken. "444" doesn't equal "'444" except in excel and "444" equals "444" everywhere else but in excel.
Looks like I'll need to test for both.
ANSWER
Answered 2021-Jun-10 at 00:14You've formatted the worksheet cells as "Text", but if you do that after the value has been entered it does not "take": cell contents will be by default left-aligned, but the values are still numeric for the purposes of formulas etc.
Your value with the '
prefix works in the lookup because it's actually text: if you re-enter the values in the "text format" cells (no need to add the apostrophe) then those will also become non-numeric and will be matched by the vlookup.
Eg see below - first 4 rows are "General" format for "Value"; next 4 rows are formatted as "Text" (after the values had been entered).
501 and 506 are both not recognized as numbers because they have a '
prefix.
504 was re-entered after the Text cell format was applied, and so is seen as non-numeric.
505 and 507 are both still seen by Excel as numbers.
QUESTION
I have a dataframe called ActiveData
that shows the date and times (StartDT
and EndDT
) when individual ID
s were active. Active is structured like this where
StartDTand
EndDT` are formatted in mdy_hms:
ANSWER
Answered 2021-Jun-09 at 20:10Here is a method using data.table
.
- Convert
data.frame
todata.table
withsetDT
- Convert the 'DT', 'StartDT', 'EndDT' columns in both dataset to datetime class (
mdy_hms
) - Create the 'Observations' column in second dataset (df2) as the number of observations per group ID, IDobserved
- Do a join with the first data on the ID column, specify, summarise by getting the sum of difference between the DT, StartDT, EndDT columns using
difftime
and return theunique
rows
QUESTION
I have 3 tables:
- Socktype
- SockStock
- Drawer
..
- Socktype stores a sockId, sockColor and sockLength
- Drawer stores a drawerId and isWood
- Sockstock denotes an amount of a sock type in a specific drawer. it has drawerId,sockId and amount
Now I would like to create a query that gives me all information about a sock and how many socks there are across all the drawers.
I was trying something like this:
...ANSWER
Answered 2021-Jun-09 at 18:55You want a LEFT JOIN not a regular JOIN. It will make it return at least one row for each SockType, with NULLs filled in for columns coming from SockStock where there is no match.
You need the coalesce to convert the NULL to 0, but you need the LEFT for it to have a row in the first place.
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