collaborated | Social chat and productivity | GraphQL library
kandi X-RAY | collaborated Summary
kandi X-RAY | collaborated Summary
run yarn build for help with the build command.
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QUESTION
I have this cloud function that append a line to a Google Spreadsheet:
...ANSWER
Answered 2021-Apr-19 at 17:51You should be able to get any response text that's passed back like this:
QUESTION
The navigation bar contains HOME,ABOUT,WORK,CONTACT. With the help href I could navigate through the page (single page website).
ISSUE : Everything works except ABOUT
Tried: Checked if there was any typo but none. Other navs works fine, navigating to home,work and contact.
Thanks in advance :)
CODE:
...ANSWER
Answered 2021-Mar-11 at 06:46href (href="#about-page") specified by you defines only attribute id, and you forgot to set the it attribute for about-page. Do this:
QUESTION
Hi everyone please could you help me with this issue?
im trying to get these (image below) to sit side by side when on smaller screen, i am really trying my hardest but still getting stuck at this anyone can help please and thank you.
its fine on full screen but I cant get it to work
Code
...ANSWER
Answered 2021-Jan-02 at 20:02Just use display flex on your logo's container:
QUESTION
I have a fixed nav bar on mobile view, the site is horizontally scrolled through. The same code worked in another html page with an almost identical div structure. I'm having one main issue in this page -The fixed nav-container isn't fixed after the first page and sometimes the second page section or '#about. I've tried adding 'fixed' in the html of the nav but it still isn't working. HTML
...ANSWER
Answered 2020-Sep-10 at 19:07All you have to do, if I get your question correctly, is to do this :
QUESTION
i'm trying to solve a problem in netlogo that has me stuck for a while now. i've got two lists (of turtles i've collaborated with and of "successful"/"unsuccessful" judgments). the two lists are mapped like so [[(turtle 10) "successful"] [(turtle 11) "unsuccessful"] with the following:
...ANSWER
Answered 2020-May-03 at 22:30If I have understood your question correctly, you can use map
to create a list of all the last
items (success or not) and then apply member?
to that list. Here is a complete model example that constructs some test data and the applies this approach.
QUESTION
Creating Data
...ANSWER
Answered 2020-Apr-19 at 16:12Since you are just asking for the two values, I have skipped the collaboration matrix.
I have also made an assumption that there is no repeated row in your tbl
.
QUESTION
I have a model called Showcase
that users use to showcase projects, and also a collaboration model where users can add collaborators to the showcase. I am trying to implement a case where administrators in the showcase and the user in a collaboration can delete that collaboration.
To explain better, in a showcase model, there is a list of administrators that manage the showcase. they also can add collaborators (through the Collaborator
model) to a showcase. The Collaborator
has a user field which is the user contributed to the showcase.
I want that after a collaborator has been added, that user can either delete himself (in a case he doesnt want to be part of the showcase) or the administrators can delete that collaborator (in a case thay added a wrong user and want to delete him from that showcase)
models.py
...ANSWER
Answered 2020-Feb-13 at 02:34You can add as many permissions as you need to permission_classses
attribute using & (and), | (or) and ~ (not) signs (doc):
QUESTION
I have a model called Showcase
that users use to showcase projects. I am trying to implement a case where any administrator in the Administrators
field in the showcase can add collaborators through the Collaborator
model. When I run my code below, I get
IntegrityError at /api/showcase/the-gods-must-be-crazy-zz2fox/collaborator/create/
NOT NULL constraint failed: showcase_collaborator.user_id
.
models.py
...ANSWER
Answered 2020-Feb-12 at 13:55As the error said, you need to provide value for user
attribute in model here. So you can do it like this.
First, update the serializer:
QUESTION
NOTE I am not necessarily asking for code to build this, just ideas on how to do this. Links and blog posts for pointers are welcome.
I am building a rest api.
I have a model
...ANSWER
Answered 2020-Jan-21 at 12:48As I see it, this structure works fine for your use case, though:
- models should always be in singular case (
Collaborator
) related_name
s should be lower case (related_name="showcases"
)- and I prefer to explicitly spell out all related_names, so I'd add
Collaborator.post
related namecollaborated_showcases
Collaborator.user
related namecollaborators
Showcase.user
related_nameowned_showcases
Then,
- To find an user's owned showcases,
Showcase.objects.filter(user=user)
- To find an user's collaborated showcases,
Showcase.objects.filter(collaborators=user)
(I think)
I'd suggest having a Collaborator
object for the owner user as well, so you can show their role more easily as well as make these queries simpler.
QUESTION
The question i need to answer:
"Display a list of academics that have collaborated with another academic on more than one paper. List individual pairs of academics on each line. List only their academic numbers. Do not list duplicate pairs. (e.g 56,113 and 113,56 are duplicate pairs)"
So far iv been looking a way to write a query that displays duplicate "panum"(paper number) but i cant find anything online, not really sure what to search for to be honest
Some useful information:
...ANSWER
Answered 2019-Oct-06 at 17:45You need a self join of the table AUTHOR
, GROUP BY
the pair of academics from each copy of the table and set the condition in the HAVING
clause:
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