caterpillar | ultimate logging system for Deno , Node.js , and Web Browsers

 by   bevry TypeScript Version: 8.2.0-next.1703862476.17c06ffc583a010f8cf883da66b6f7a986bd2ab1 License: Non-SPDX

kandi X-RAY | caterpillar Summary

kandi X-RAY | caterpillar Summary

caterpillar is a TypeScript library typically used in Logging applications. caterpillar has no bugs, it has no vulnerabilities and it has low support. However caterpillar has a Non-SPDX License. You can download it from GitHub.

The RFC Log Levels are provided by the rfc-log-levels package which follows RFC 3164 - The BSD Syslog Protocol. Log Entries that are within the lineLevel range, will have their line information fetched using the get-current-line package. The Logger is what you write your log messages to, which you then pipe to destinations and transforms. The Filter transport is used to filter out log levels that we do not want to pass onto the next destination. The Human transport is used to convert the Log Entries into a human readable and colourful output. The Browser transport is used to send the human output, including colours, to the Web Browser console. The Transform is used to write your own transforms, and is what all the others are based from.
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            kandi-support Support

              caterpillar has a low active ecosystem.
              It has 391 star(s) with 15 fork(s). There are 14 watchers for this library.
              There were 10 major release(s) in the last 6 months.
              There are 5 open issues and 18 have been closed. On average issues are closed in 393 days. There are 8 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of caterpillar is 8.2.0-next.1703862476.17c06ffc583a010f8cf883da66b6f7a986bd2ab1

            kandi-Quality Quality

              caterpillar has no bugs reported.

            kandi-Security Security

              caterpillar has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              caterpillar has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              caterpillar releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

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            caterpillar Key Features

            No Key Features are available at this moment for caterpillar.

            caterpillar Examples and Code Snippets

            No Code Snippets are available at this moment for caterpillar.

            Community Discussions

            QUESTION

            Search for keyword in String
            Asked 2021-Apr-22 at 05:13

            I want to write a method that returns true if a keyword is found in a string and false if not. I figured out how to do so but when the keyword is something like "cat" and the string is "There is a caterpillar on a lead" it returns true even though the cat is not in the string. What am I doing wrong?

            ...

            ANSWER

            Answered 2021-Apr-22 at 04:22

            There are many ways to solve this problem. The issue is that when you use contains(), it looks for that subtext in the full string but you want to look at words only.

            So split your string into a list/array of words using space as a separator. Then Check if your array/list contains the word.

            Source https://stackoverflow.com/questions/67206540

            QUESTION

            Why does "Game over" text not appear?
            Asked 2021-Mar-23 at 15:57

            I am currently attempting to programm a small game. An enemy is supposed to chase the player, the actual chasing is not implemented yet. I still need to figure out how to do that, but that's not the question. I have made it so that the player returns to the start point once they collide with the enemy. In addition to that, a text 'Game over' is supposed to appear. The function for that is called at the end of the game loop and while the text appeared briefly(it actually only appeared once, I have tried it multiple times), it does not stay. I was planing on making it appear and then disappear after a few seconds so that the player can play again, but I'm not sure why it disappears instantly. If this is the wrong place to post this, please tell me, I will delete this post. This is my code, would be amazing if somebody could help me out:

            ...

            ANSWER

            Answered 2021-Mar-23 at 15:57

            The collision only occurs for a moment and the game over text is only shown when the object collides. If you want to persist the text, set a gameover variable when the collision is detected and display the text based on the state of the variable:

            Source https://stackoverflow.com/questions/66766371

            QUESTION

            Python turtle game str' object is not callable
            Asked 2021-Mar-15 at 09:01

            I am reading from a book, and then I was following the instructions but this error occurred

            ...

            ANSWER

            Answered 2021-Mar-15 at 08:54

            The answer is actually very simple, Because

            leaf.color('yellow') can also be put as leaf.color = 'yellow'

            Source https://stackoverflow.com/questions/66634796

            QUESTION

            Pandas average of previous rows fulfilling condition
            Asked 2021-Feb-11 at 16:25

            I have a huge data-frame (>20m rows) with each row containing a timestamp and a numeric variable X. I want to assign a new column where for each row the value in this new column is the average of X in the previous rows within a specified time window e.g the average of all rows with time stamps no more than 5 min ago. Since the time stamps aren’t at regular intervals I can’t just take fixed slices

            Currently the best approach I’ve found is a “caterpillar” algorithm which loops through the data frame once and moves the start/end index depending on whether the timeframe window has been breached. However this is proving infeasibly slow, and I was wondering if there was a clever vectorised way to do this? Perhaps involving np arrays instead?

            Thanks

            ...

            ANSWER

            Answered 2021-Feb-11 at 16:25

            Set your timestamp to the index and use the rolling() function. You can set the window to a time offset. For example:

            Source https://stackoverflow.com/questions/66158082

            QUESTION

            React - how to filter items in dropdown
            Asked 2021-Feb-03 at 02:50

            First time encountering this so please bear with me.

            I'm writing a React web app that pulls in data from a local db.json file and stores it in global state using the Context API. I have the data displayed on the page and I have a dropdown that pulls in the category names of this data as well.

            When I select a dropdown item from the list, I'd like it to filter the list of data to that selected category.

            Currently when you select a dropdown item, I get the following error:

            "TypeError: Cannot read property 'toLowerCase' of undefined".

            This tells me that I'm probably not accessing the 'category' data properly.

            Here's an example of the JSON, I want to access the 'category':

            ...

            ANSWER

            Answered 2021-Feb-03 at 02:50
            const [selectedCategory, setSelectedCategory] = useState('')
            const filteredProducts = data.filter(machine => machine.category.toLowerCase() === selectedCategory.toLowerCase())
            

            Source https://stackoverflow.com/questions/66020275

            QUESTION

            Given list of strings return just strings not contained in any other
            Asked 2020-Oct-13 at 14:03

            I'm trying to find a computationally friendly way for doing the following:

            given list_of_strings = ['many', 'man', 'cat', 'caterpillar', 'pillow', 'pi', 'pill']

            return sublist = ['many', 'caterpillar', 'pillow'], i.e. the list of strings not contained in any other string.

            The simplest solution would be to iterate over the elements and check whether each element is contained in the other, with O(n^2) complexity (even if there are some little optimizations I thought about, like sorting the strings by length, but this adds the sorting complexity), but I think it's too expensive.

            I thought also about implementing a trie and then use each element of the list as an haystack, then keeping just the strings contained in one haystack (that of the string itself).

            I think I'm missing more than I know, so I'm looking for suggestions

            ...

            ANSWER

            Answered 2020-Oct-12 at 14:06

            The following should work considering that there are no duplicates in your list (if there are, question must clarify what will happen with them and the code can be adjusted):

            Source https://stackoverflow.com/questions/64318941

            QUESTION

            Caterpillar plot of posterior brms samples: Order factors in a ggdist plot (stat_slab)
            Asked 2020-Sep-10 at 02:52

            I ran a bayesian linear mixed model with brms and can plot the estimates nicely but I can't figure out how to order the single-subject estimates based on the mean of the posterior samples (so as to get a caterpillar plot). This is what I've done.

            Toy data:

            ...

            ANSWER

            Answered 2020-Sep-10 at 02:52

            Two points for consideration:

            1. Ungroup the result from spread_draws, otherwise you won't be able to reorder the levels of subject;
            2. Use fct_reorder from the forcats package in tidyverse. It's designed for this exact purpose.

            Source https://stackoverflow.com/questions/63813576

            QUESTION

            Beginners sincerely ask for advice about string
            Asked 2020-Aug-31 at 13:30

            What the class describes is about "reversing a string", which is correct and usable from the Leetcode website. Today, I want to present "reversing a string" by inputting a value by myself (such as the int main() part below), but I still can't execute it after thinking for a long time. Beginners sincerely ask for advice, maybe you can also attach your writing so that I can learn, thank you.

            ...

            ANSWER

            Answered 2020-Aug-31 at 13:30
            • Your code is pretty good, however we just want to reverse the words not the chars, for that we can use a while loop.

            • Similarly using two pointers, this'd pass just fine:

            Source https://stackoverflow.com/questions/63667192

            QUESTION

            how to implement a class?
            Asked 2020-Aug-22 at 00:00

            I've been doing an exercise and we need to create a caterpillar with the size attribute from the other function. In this code below I've added a size attribute between 0 and 3.

            ...

            ANSWER

            Answered 2020-Aug-21 at 23:53

            QUESTION

            Caterpillar project confusion
            Asked 2020-Aug-21 at 22:47

            I have run into a problem in my project and could use some help figuring out what I am doing wrong.

            ...

            ANSWER

            Answered 2020-Aug-21 at 22:47

            A few things I noticed in your code:

            • In the addSegment method, the length never goes past zero
            • In the grow method, only the first segment is added. Other segments are ignored.
            • As @Kingsley mentioned, you create a new segment with an object instead of the x coord

            Make these changes to the caterpillar class:

            Source https://stackoverflow.com/questions/63515624

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install caterpillar

            This package is published with the following editions:.
            Install: npm install --save caterpillar
            Import: import * as pkg from ('caterpillar')
            Require: const pkg = require('caterpillar')
            caterpillar/source/index.ts is TypeScript source code with Import for modules
            caterpillar/edition-browsers/index.js is TypeScript compiled against ES2020 for web browsers with Import for modules
            caterpillar aliases caterpillar/edition-es2019/index.js
            caterpillar/edition-es2019/index.js is TypeScript compiled against ES2019 for Node.js 10 || 12 || 14 || 16 with Require for modules
            caterpillar/edition-es2019-esm/index.js is TypeScript compiled against ES2019 for Node.js 12 || 14 || 16 with Import for modules

            Support

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