sqrs | 🚌SQRS is a JavaScript library for implementing CQRS pattern | Dependency Injection library
kandi X-RAY | sqrs Summary
kandi X-RAY | sqrs Summary
In short, CQRS is a pattern that differentiates between read operations and write operations. Write operations are achieved via commands that represent intent to change the system's state, and read operations are achieved via queries that read the system's state. The distinction between the to comes from the principle that asking a question shouldn't change the response.
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QUESTION
I wrote two versions of code for a Swift programming exercise from an online programming exercise website. The exercise is as follows:
Find the difference between the square of the sum and the sum of the squares of the first N natural numbers. The square of the sum of the first ten natural numbers is (1 + 2 + ... + 10)² = 55² = 3025. The sum of the squares of the first ten natural numbers is 1² + 2² + ... + 10² = 385. Hence the difference between the square of the sum of the first ten natural numbers and the sum of the squares of the first ten natural numbers is 3025 - 385 = 2640.
The code for the first version is:
...ANSWER
Answered 2020-Jul-17 at 00:36Lazy properties have mutating getters, i.e. accessing a lazy property will potentially mutate the struct. Why? Think about the first time you access a lazy property. Before the first access, that property has no value, after you access it, the expression on the right of = is evaluated and assigned to the property. Now the property has a value. This is how accessing a lazy property can change the struct. As a result, you need a var to access lazy properties.
Changing the struct into a class also helps, because now sqrs stores a reference, and let sqrs only makes the reference to the object constant, rather than making the object itself constant.
The first version initialises all the properties in the initialiser. You are allowed to assign to each let property once in the initialiser, which is what the first version did. And since the properties are not lazy in the first version, you can access them with a let constant.
QUESTION
I'm trying to write data to my SQLite database. I think there's an error at my migration file and the foreign keys.
I have tried to change names of the files, making the foreign key nullable and clearing Laravel's caches.
Are you familiar with the error that the error handler shows or could you point me towards a page that could help me understand what I'm doing wrong?
Thank you very much in advance.
Migration file:
...ANSWER
Answered 2019-Sep-07 at 08:13@dparoli said in a comment of this post:
"Are you sure that you have an User with id = 1 in the database? – dparoli"
This was the answer to my question. Because there was nog user = 1 in the database, it crashed.
QUESTION
I am building a minesweeper game in C#, and one of my functions keeps crashing the program. The erorr message is Process is terminated due to StackOverflowException. I tried to find where is the problem in my recursion, but I didn't find it. The problem only happen if Openk is called, so I am pretty sure the problem is there. I tried to find if there is an infinite recursion, but didn't find it. What could be the problem?
ANSWER
Answered 2017-Jan-29 at 15:58Your problem is that you keep looping and executing Openk on the same middle square each time. Maybe it is because of the unguarded if statement. It goes like this in your code.
- You pass the selected coordinates of a square, say [5,5].
- Then you loop a row before 5 (4), row 5, and a row after 5 (6).
- For each row, your loop a square before the selected column 5 (4), column 5, and and the next column of 5 (6).
- In your code, only when you reach the middle square (i = 0, j = 0), you execute the checking of square if it is a mine, and if it is not mine, you pass the selected coordinates after subtracting with zeros (i = 0, j = 0), which effectively loops the same spot again!
.
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