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QUESTION
In the application combineLatest is used to combine three observables:
...ANSWER
Answered 2021-Mar-31 at 15:11Observables aren't typically 'set' or 'not set'. I'm not sure what you mean by this. If you have a predicate that can check your observables, here is how you might use it.
QUESTION
I am having a problem on how to approach combining multiple http get requests in parallel and returning it as a flat, observable array.
Currently, I have a method, returnNewCars()
, that returns Observable
after making one http get request -- in the method returnAllCars()
, I would like to make multiple http get requests and still return Observable
.
Right now, returnNewCars()
prints:
ANSWER
Answered 2021-Mar-30 at 16:51I'm not sure why do you need this logic to get all cars with one method since you should make a api call to get 3 kinds cars list separately. Anyway, I tried to make one method to get All as you expected and used forkJoin.
Here is the stackblitz link
QUESTION
I'm currently building a type ahead search. I'm trying to adapt it from the example here https://www.learnrxjs.io/learn-rxjs/recipes/type-ahead but I need to make an http call on keystroke. I'm testing it against timezones from my api. It works, but it seems to be compounding api calls every time I input a keyup
.
If I type 'us' it will return results and make two identical api calls. If I add 'a' to make 'usa' it will then make 3 api calls. If I backspace a letter it makes 4, so on and so forth.
From my understanding switchMap
is supposed to cancel calls that are going as newer ones come in, but it doesn't seem to do that with my implementation. I cannot for the life of me figure out why it's doing this when I keep going over the example. I tried to use .share()
to attempt to consolidate streams but it didn't seem to help.
Search service:
...ANSWER
Answered 2021-Mar-13 at 17:59Just subscribe once (probably in ngAfterViewInit() since you are accessing the dom):
QUESTION
So the code below has been developed off the answer I got in this stack overflow question.
the code is designed to poll my server until either a condition on the server is true, or polling has occurred for a minute.
I understand I can stop the polling after a minute using the takeUntil
RXJS function. However, I have no idea where in the code I would put it in. As every place I put it in that I thought it would go, the code has errored out.
I am also using this tutorial from the learnrxjs website https://www.learnrxjs.io/learn-rxjs/operators/filtering/takeuntil
You'll notice the first line of the startastream()
function is
const endtimer = timer(60000);
This is the condition that would fill the takeUntil()
argument. So takeUntil(endtimer)
ANSWER
Answered 2021-Mar-09 at 01:00You can simply place it in the pipe after switchMap:
QUESTION
I have couple of observables combined in one observable with combineLatest. Also I have one inner switchMap
observable that in real example makes an http request to remote server.
Now I wonder, how can the combined observable continue working in case if switchMap
returns error ?
I've created simplified example here
...ANSWER
Answered 2021-Feb-10 at 13:19The stream itself from the combineLatest
will end when an error occurs.
You can prevent it by adding the catchError
to the Observable returned in your switchMap
.
That way, the main stream is not altered and will continue to live.
QUESTION
So my code is:
...ANSWER
Answered 2020-Dec-08 at 19:38Below is a simple example of how it might be implemented:
QUESTION
Just started learning RxJS. Really confused about the combineAll
operator. Would really appreciate an explanation on this example code:
ANSWER
Answered 2020-Sep-20 at 13:19- Your assumption would be correct, but there is one catch with
combineAll
. This is from the docs: "Once the outer Observable completes, it subscribes to all collected Observables". This means that,const source$ = interval(1000).pipe(take(2));
has to complete in order to makecombineAll
subscribe to the inner Observables. Due totake(2)
it completes in one second with values 0 and 1. See the doc for the combineAll
To answer second and third questions of yours let me describe the situation:
First of all lets mention few important notes.
What's the type of example$? Let's look at this bit of code
const example$ = source$.pipe(map(val => ...))
.source$
isObsevable
due to theinterval
. This means that when we map the value emitted by the source Observable to the newinterval
we are going to have Observable of Observables. Thus the type ofexample$
isObsevable>
. We don't want to subscribe to this type, because in that case we will receive theObservable
in the subscribe and its not what we want. That's wherecombineAll
comes handy, it flattensObsevable>
toObservable
, that's what flattening means in terms of types.Now let's look at this situation in the different perspective.
combineAll
essentially is same as thecombineLatest
. Lets explain the resulted behavior in terms ofcombineLatest
.
const source$ = interval(1000).pipe(take(2));
, source Observable emits 2 items and completes. We are mapping this 2 events to the 2 inner Observables. In summary, we have 2 inner Observables, lets name them inner0$
and inner1$
.
As for comparison this is where combineLatest
comes in. This is how we would write same code with combineLatest
.
QUESTION
I have an object with an array of items in it something like this: { a: string, b: string, items: Something[] }
.
In my observable, when a new value is emitted, I want the previous values of items to be concatenated with new values so I used the scan operator. It does something like myObservable$.pipe(scan((acc: any, curr: any) => [...acc.items, ...curr.items]))
.
It is working as expected, but I have some pipe async like (myObservable$ | async)?.a
so I want to keep my object as is and only concatenate my items inside this object, but the scan operator maps my object to the new array (I totally understand it is the normal behavior).
So how can I concatenate my arrays in my object without this mapping?
Example:
What I have:
...ANSWER
Answered 2020-Aug-19 at 11:58Try this:
QUESTION
I noticed that some of my tap(...)
invokations won't log to console, so I investigated further and found that an inner piping seems to kill off the outer piping. For instance, the code below, will show inner but won't show outer.
ANSWER
Answered 2020-Jul-09 at 20:55The tap operator takes up to 3 callbacks. The first one is called in case a (success) value is emitted, but not when the observable goes in error. Try this as your first tap operator:
QUESTION
I have a BehaviourSubject
that is subscribed to via the getSaveBehaviorSubject() in the constructor of a Service
.This behavioursubject can receive multiple types of data from other components/services of which some types need to be stored in the backend while others do not. When it receives a value that does need to be stored it sends it to the backend via a put/post
request. As a request rate limiter I'm using the debounce(300)
operator so that the actual request to the server is made after 300 ms of inactivity have passed. This will prevent the server from throwing a 429 Too many requests
error. The debounce operator should only be applied when a value type is pushed that needs to be stored. I've tried creating such a condition with the iif()
operator. My code looks like this:
ANSWER
Answered 2020-Jun-17 at 17:56There are two issues here:
debounceTime
will emit its current value immediately when its source completes - without waiting for the timeout. Theof
factory will produce one notification and then complete right after. Therefore, there is no debouncing happening. You could fix this by replacingdebounceTime
withdelay
, as it will wait to emit even if the source has already completed.You are using
mergeMap
, which will not unsubscribe from the previous Observable when it gets a new notification. Therefore you could have a case wheregetSaveBehaviorSubject
emits 100 times within the timeout and you would send 100 server requests. You can fix this by replacingmergeMap
withswitchMap
.
Applying both should fix your issue.
But, I would recommend a different approach: Make use of the debounce
operator. Instead of a timeout value, you pass in a function that returns an Observable. When this Observable emits, the current value will be forwarded.
Like this:
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