type-inference | Type Inference Library written in TypeScript

 by   cdiggins TypeScript Version: 1.1.0 License: MIT

kandi X-RAY | type-inference Summary

kandi X-RAY | type-inference Summary

type-inference is a TypeScript library. type-inference has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

The basic algorithm is as follows:. During step 4 (substitution), if a polytype is substituted for a type variable more than once each subsequent instance is given a new set of names for the generic type parameters. This is key for the step 5 to be able to correctly assign the forall quantifiers to the right level of nesting.
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              type-inference has a low active ecosystem.
              It has 58 star(s) with 3 fork(s). There are 5 watchers for this library.
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              It had no major release in the last 12 months.
              There are 1 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of type-inference is 1.1.0

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              type-inference has no bugs reported.

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              type-inference has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              type-inference is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              type-inference releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Community Discussions

            QUESTION

            How is compiler inferring type on a generic method?
            Asked 2021-Jun-05 at 14:23

            I have a Storage class:

            ...

            ANSWER

            Answered 2021-Jun-05 at 13:03

            To make things clearer, the class Child:

            • extends Parent
            • implements Comparable
            1) static > T max(List list)
            • T is Child
            • fails because Child is not a Comparable
            2) static > T max(List list)
            • T is Child
            • ? is Parent
            • it works because Child implements Comparable
            3) static > T max(List list)
            • T is Parent
            • ? is Child
            • it works because Child extends Parent implements Comparable

            Here in case 3), finding a valid T class can be seen as: "find the first super class of Child that implements a Comparable of itself".
            As in case 1), it cannot be Child because it is not a Comparable. The first (and only) super class of Child that implements Comparable of itself is Parent.

            I couldn't understand how updating List to List made the compiler infer the type Parent.

            • List forces T to be Child
            • List forces ? to be Child, not T

            Source https://stackoverflow.com/questions/67843458

            QUESTION

            Does Typescript (really) follows the naming convention for parameterized types (T, U, V, W) in Generics?
            Asked 2021-Feb-24 at 03:13

            I am not exactly sure if in TS we follow this naming convention for parameterized types as C++/Java or many other languages (T,U,V,W).

            I saw many times a mixed usage of parameterized types conventions in TS. For example, in the release notes of TS 2.8:

            ...

            ANSWER

            Answered 2021-Feb-24 at 03:13

            (From the comments, mostly)

            The closest I can imagine answering this in any way which is not just my opinion would be to point to some documentation that describes what the "TypeScript Type Parameter Naming Convention" is and compare it to the Java Generics tutorial document you linked.

            If so, the TypeScript design team's official stance on this seems to be "we do not intend to impose any such conventions on others", or "there are no canonical naming conventions in TS". See microsoft/TypeScript#6168 and microsoft/TypeScript#878, specifically this comment:

            [I]n general we're not interested in deciding stylistic things for people. Saying that there's One Approved Style for TS goes against our philosophy that we're here to provide types for JS regardless of how you're writing it (within reasonable parameters, of course 😉).

            There's also ESLint's naming-convention rule and TSLint's naming-convention rule, which make it possible to enforce type parameter naming conventions in a linter-checked code base, but do not seem to do by default. So no convention seems to be official enough to be enforced by default.

            For comparison's sake, let's take a look at the relevant section from the Java Generics tutorial document you linked:

            Type Parameter Naming Conventions

            By convention, type parameter names are single, uppercase letters. This stands in sharp contrast to the variable naming conventions that you already know about, and with good reason: Without this convention, it would be difficult to tell the difference between a type variable and an ordinary class or interface name.

            The most commonly used type parameter names are:

            • E - Element (used extensively by the Java Collections Framework)
            • K - Key
            • N - Number
            • T - Type
            • V - Value
            • S,U,V etc. - 2nd, 3rd, 4th types

            You'll see these names used throughout the Java SE API and the rest of this lesson.

            Note that the enumerated list above is described as "the most commonly used type parameter names" and not "the only allowable type parameter names"; it is a list of examples and thus descriptive and not prescriptive.

            The part that about choosing "single, uppercase letters" is closer to a prescription: uppercase letters tend to distinguish type names from variable names, and single-character type names tend to distinguish type parameters from specific types like class or interfaces. But I get the same sense that this is not so much a decree from on high but an observation about common practices.

            So we could presumably stop there and say "there is no official or canonical type parameter naming convention in either TypeScript or Java, and any unofficial such convention is a matter of opinion."

            But for the sake of trying to list out what I think the unofficial convention in TypeScript actually is, I'll go on. Keep in mind that it's my opinion and people could plausibly disagree.

            I'd say that the Java naming convention laid out above aligns pretty closely with what I would consider the de facto naming convention for TypeScript generic type parameters: use a single uppercase character, either corresponding to either the first letter of what they represent, such as:

            • T for "type", the most general and therefore the most commonly used type parameter name;
            • K for "key", or P for "property", both of which tend to be constrained by PropertyKey or keyof T or keyof SomeInterface or keyof SomeClass;
            • V for "value", most commonly used as a pair with K for "key";
            • A for "arguments" and R for "return", corresponding to the rest parameter list and return type of function signatures respectively, like (...args: A) => R;
            • N for "number", S for "string", B for "boolean, for type parameters constrained by primitives;

            or some sequence of related types such as:

            • T, U, V, W, etc., starting with T for "type" and then walking through the alphabet when needing more types, keeping in mind that you can only get a few this way;
            • A, B, C, D, etc., starting from the beginning of the alphabet when you expect to use a whole bunch of type parameters and you haven't already used type parameters for something else.

            Such conventions are not absolute, and will tend to be bent where necessary to avoid ambiguity or other confusion. If you need more type parameters than can be obtained above without name collisions, it might be desirable to add a character to the name:

            • T0, T1, T2, T3, etc., appending numbers to get a sequence of related types;
            • KT, KU, KV: prefixing K for "keys of" T, U, and V, respectively;

            It is farther from what I consider conventional but still common enough to write short UpperCamelCase names to be more descriptive of what the types represent, with the drawback that they could start being confused for specific types and not type parameters:

            • Key, Val, Prop, Arg, Ret, Type, This

            The following is unconventional (remember, my opinion here!) and should be avoided unless there is some overwhelming extenuating reason to do so:

            • Long names that look like interface or class names like InputType or Properties;
            • Prefixing an uppercase T on a longer type name like TNotRecommended;
            • Names that begin with a lowercase letter like t or u or myType;

            Source https://stackoverflow.com/questions/66325117

            QUESTION

            Difference between covariant and contravariant positions in Typescript
            Asked 2020-Dec-05 at 15:45

            I'm trying to understand the following examples from the Typescript advanced types handbook.

            Quoting, it says that:

            The following example demonstrates how multiple candidates for the same type variable in co-variant positions causes a union type to be inferred:

            ...

            ANSWER

            Answered 2020-Dec-05 at 15:45

            Your observation that one of the examples resolves to never is accurate and you are not missing any compiler settings. In newer versions of TS, intersections of primitive types resolve to never. If you revert to an older version you will still see string & number. In newer version you can still see the contravariant position behavior if you use object types:

            Source https://stackoverflow.com/questions/62496072

            QUESTION

            What is the inferred type of a function argument with a default value but no type annotation? How about a variable initialized as 'None'?
            Asked 2020-Oct-27 at 13:08

            What is the type (in the sense of type annotations, not type()) of variables and parameters that come without a type annotation but with an initial value? E.g.,

            ...

            ANSWER

            Answered 2020-Oct-23 at 11:16

            Concerning the types situation of this block

            Source https://stackoverflow.com/questions/64498806

            QUESTION

            TypeScript function type with fixed parameters but inferred return type
            Asked 2020-Oct-14 at 20:41

            I can't figure out how to create a type that is a function whose parameters are set but whose return value is generic and should be inferred from the provided function.

            This particular use case is that I'm defining a set of selectors on data. All of the selectors have the same state input, and their output will be a property of that state:

            ...

            ANSWER

            Answered 2020-Oct-14 at 20:41

            Here's a neat trick you can use. Create a wrapper function that does nothing but restrict and forward the types.

            Source https://stackoverflow.com/questions/64360059

            QUESTION

            Unexpected return type of vavr's Either in reactor
            Asked 2020-Aug-20 at 09:29

            There are two simple methods using vavr's Either.

            ...

            ANSWER

            Answered 2020-Aug-20 at 05:36

            The second example seems to 'lose' the type information for the left side when the map(Either::right) is applied.

            Adding some type 'hints' to the map method call should do the trick. So the testReactorEither will look like this:

            Source https://stackoverflow.com/questions/63497038

            QUESTION

            C# - Implicitly convert or infer generic return type
            Asked 2020-Aug-13 at 20:53

            I've started using the pattern of a generic result type as a wrapper object that includes a return value and information about the operation like whether it succeeded. Here's an example:

            ...

            ANSWER

            Answered 2020-Aug-13 at 20:25

            You could get around the bool issue with just an overload:

            Source https://stackoverflow.com/questions/63239812

            QUESTION

            Auto return value inference and c++ static typing
            Asked 2020-Jul-25 at 20:33

            In this very interesting use case of auto return value inference(taken from: https://www.geeksforgeeks.org/type-inference-in-c-auto-and-decltype/ ):

            ...

            ANSWER

            Answered 2020-Jul-25 at 20:33

            You'll get one function that returns a value of common type of A and B. C++ is a statically typed language, so the type of cond ? a : b should be known at compile time. There are special rules to determine that common type. Informally speaking, it is a type that A and B can be implicitly converted to. If no such type exists, you'll get a compilation error.

            For example,

            Source https://stackoverflow.com/questions/63092955

            QUESTION

            How do Lambda expressions infer types in Java?
            Asked 2020-Jul-15 at 20:04

            I am currently trying to understand how Java infers the type of lambda expressions. I can illustrate with an example:

            Writing:

            ...

            ANSWER

            Answered 2020-Jul-15 at 17:51

            producer.send is a method that accepts a record and a Callback, and Callback has exactly one abstract method, which accepts a RecordMetadata and an Exception. Therefore, if the compiler sees a lambda as the second argument to producer.send, it must be implementing the method Callback.onCompletion, and it must have two arguments, with the first a RecordMetadata and the second an Exception.

            The point being: it's inferred from the type of the method that you're passing the lambda to.

            Source https://stackoverflow.com/questions/62920883

            QUESTION

            Result type of a polyvariadic function in haskell
            Asked 2020-May-31 at 13:14

            While studying polyvariadic functions in Haskell I stumbled across the following SO questions:

            How to create a polyvariadic haskell function?

            Haskell, polyvariadic function and type inference

            and thought I will give it a try by implementing a function which takes a variable number of strings and concatenates/merges them into a single string:

            ...

            ANSWER

            Answered 2020-May-31 at 12:17

            printf works without type annotation because of type defaulting in GHCi. The same mechanism that allows you to eval show $ 1 + 2 without specifying concrete types.

            GHCi tries to evaluate expressions of type IO a, so you just need to add appropriate instance for MergeStrings:

            Source https://stackoverflow.com/questions/62114605

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            You can download it from GitHub.

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            npm i type-inference

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            gh repo clone cdiggins/type-inference

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