notorious | first note taking and knowledge management application
kandi X-RAY | notorious Summary
kandi X-RAY | notorious Summary
Offline-first note taking and knowledge management application for desktop and the web. Supports nested notebooks, tags, real-time sync, images and file attachments. Optimised for efficiency with keyboard navigation, full-text search and version control. Never lose a thought. Private, fast, notorious
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QUESTION
I am trying to learn Common Lisp with the book Common Lisp: A gentle introduction to Symbolic Computation. In addition, I am using SBCL, Emacs, and Slime.
By the end of chapter 10, the author discuss the useful break function. In order to provide a background context, he presents this problematic function:
...ANSWER
Answered 2021-Jun-06 at 17:54If you navigate to the top frame in the debugger and press enter on that frame, you will see that commission
is not known to the debugger as a local variable:
QUESTION
import os
import random
import time
import math
def stringmanipulator(xy, y=40):
xy= xy.lower()
x = []
x = list(xy)
length = len(x)
y = int(math.floor(length * (y/100)))
while(y):
r =int(random.random()*(length-1))
if(x[r] != '_' and x[r] != ' '):
x[r] = '_'
y = y-1
return x
def printcomplement():
x = int(random.random()*11)
if(x == 0):
print("well done!!")
elif(x == 1):
print("keep going!!")
elif(x == 2):
print("YOU can save him!!")
elif(x == 3):
print("You are the hero no one wanted but everyone deserves.")
elif(x == 4):
print("Genius kid.")
elif(x == 5):
print("You are Smart, not kidding.")
elif(x == 6):
print("You are one who will destroy my carrer using your intellect.")
elif(x == 7):
print("The most kind hearted person I have ever seen till now. Yes I am talking about you")
elif(x == 8):
print("You nailed it.")
elif(x == 9):
print("AND I thought the game was hard.")
elif(x == 10):
print("I will find more difficult words to challenge you with.")
elif(x == 11):
print("How about you put another life on risk after this round.")
def printdis():
x = int(random.random()*11)
if(x == 0):
print("Fool")
elif(x == 1):
print("You will end up killing the fool and then I will hang you next.")
elif(x == 2):
print("What a piece of shit you are.")
elif(x == 3):
print("Hey disgrace to humanity.")
elif(x == 4):
print("Don't cry after the man is dead. You killed him, I gave you a chance to save him.")
elif(x == 5):
print("Dumbass!!")
elif(x == 6):
print("You know what it was my mistake to let such an idiot play.")
elif(x == 7):
print("This is your last game. I don't want fools playing this game.")
elif(x == 8):
print("I see you are already crying.")
elif(x == 9):
print("Even the guy who's life is line is laughing at your stupidity.")
elif(x == 10):
print("My 120 years old grandma has a sharper brain than yours.")
elif(x == 11):
print("Get lost, YOU useless, moronic, unworthy pile of garbage.")
def hangman(i = 0):
if(i == 0):
print("___________")
print("| |")
print("| |")
print("| ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 1):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 2):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| | ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 3):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| \\ | / ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 4):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 5):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| ")
print("|")
elif(i == 6):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| / \\")
print("|")
print("\n\nGAME OVER. You have succesfully killed a person. Better luck next time")
def game(xy, y):
x=[]
i = 0
letter = ''
x = stringmanipulator(xy, y)
xy = xy.lower()
# os.system('cls')
for index in range(len(x)):
if(x[index] == '_'):
while(letter != x[index]):
_= os.system('cls')
hangman(i)
for char in range(len(x)):
print(x[char], end=' ')
print("\n")
letter = input("Enter the letter in the first blank: ")
print(letter+str(i))
if(letter == xy[index]):
print("complement")
x[index] = letter
else:
printdis()
i+=1
dictionary ={}
dictionary["films"] = ["A Space OdysseY", "The GodFather", "Citizen Kane", "Raiders of the lost Ark", "Seven Samurai", "There will be Blood", "Casablanca", "Vertigo", "Notorious", "City Lights"]
dictionary["cities"] = ["Tokyo", "Mecca", "Beijing", "London", "Kolkata", "Washington DC", "Mumbai", "Mexico City", "Delhi", "Shanghai"]
dictionary["fruits"] = ["Damson Plum", "Pomelo", "Blood Orange", "Kumquat", "Blackcurrant", "Acerola", "Avocado", "Pomegrenate", "Apple", "Mango"]
dictionary["country"] = ["Djibouti", "Azerbaijan Azerbaijan,", "Venzuela", "Armenia", "Khazakhstan", "Bangladesh", "Saudi Arabia", "United Kingdom", "United States of America", "India"]
dictionary["flowers"] = ["Monkey Face Orchid", "Naked Man Orchid", "Dancing Girls", "Chamber Maids", "Hibiscus", "Marigold", "Tulip", "Lilies", "Daisy", "Hydrangea"]
print("WELCOME TO THE GAME HANGMAN.\n TAKE THE GAME SERIOUSLY SINCE THE LIFE OF A MAN IS DEPENDING ON YOUR KNOWLEDGE. \n\nI DON'T KNOW HOW MANY CHANCE YOU WILL GET, NOT MANY THAT I CAN CONFIRM.\n SO TRY TO SAVE YOUR FELLOW HUMAN OR LET IT BE MY FOOD. HAHAHAHAHAHAHAHAHAH!!!!!!!")
# x = input("Press 1 for films, 2 for cities, 3 for fruits, 4 for country and 5 for flowers (The most beautiful are usually the hardest): ")
# x = int(x)
x = int(input("Enter a number between 1 and 5: "))
if((x < 1) or(x > 5)):
print("What a moron you are. You couldn't even choose one of the option properly game over good bye, tata, cya")
x = random.randint(1,5)
time.sleep(10)
print("Just kidding you still get to play the game but now I will decide what kind of object you have to guess.")
y = int(input("Enter 40 for easy, 60 for medium and 80 for hard: "))
i = 0
xy = ""
r = random.randint(0,9)
if(x == 1):
xy = dictionary["films"][r]
print("FILMS:")
elif(x == 2):
xy = dictionary["cities"][r]
print("CITIES:")
elif(x == 3):
xy = dictionary["fruits"][r]
print("FRUITS:")
elif(x == 4):
xy = dictionary["country"][r]
print("COUNTRY:")
elif(x == 5):
xy = dictionary["flowers"][r]
print("FLOWERS:")
# hangman(0)
game(xy, y)
...ANSWER
Answered 2021-May-31 at 14:43Running your code os.system('cls') is clearing the screen before the input is read in the loop. This makes it seem that there is no output is being displayed when it's really being overwritten.
A quick test can be done to confirm that this is the problem. To do this we add another input read in the game function. like so:
QUESTION
Peculiar issue: I have a table of 140.588
rows and 246,313
MB which looks like this:
ANSWER
Answered 2021-May-28 at 11:54I guess your varchar(max)
causes the problem. The size of a text field in Excel is limited. Following an example:
QUESTION
If you run a command in Terminal, say
rsync -avuP [SourcPath] [DestPath]
That command will get logged in, say .bash_history, .zsh_history, .bash_sessions, etc.
So if you make use of something as notoriously insecure as sshpass
say sshpass -P password -p MySecetPassword [Some command requiring std input]
, that too will be logged.
But what happens when you do the equivalent when spawning a process using Node JS?
...ANSWER
Answered 2021-May-25 at 02:46There isn't a node specific history file for execs unless you created one by logging the arguments. There can be lower level OS logging that captures this type of data, like an audit log.
Passing a password on the command line is still considered the least secure way.
Try -f
to pass a file or -d
for a file descriptor instead (or ssh keys should always be the first port of call)
The man page explains...
The -p option should be considered the least secure of all of sshpass's options. All system users can see the password in the command line with a simple "ps" command. Sshpass makes a minimal attempt to hide the password, but such attempts are doomed to create race conditions without actually solving the problem. Users of sshpass are encouraged to use one of the other password passing techniques, which are all more secure.
In particular, people writing programs that are meant to communicate the password programatically are encouraged to use an anonymous pipe and pass the pipe's reading end to sshpass using the -d option.
QUESTION
I am currently applying the Contrast Limited Adaptive Histogram Equalization algorithm together with an algorithm to perform the photo denoise.
My problem is that I am working with 360 photos. As the contrast generates different values at the edges when I join the photo, the edge line is highly noticeable. How can I mitigate that line? What changes should I make so that it is not noticeable and the algorithm is applied consistently?
Original Photo:
Code to Contrast Limited Adaptive Histogram Equalization
...ANSWER
Answered 2021-May-21 at 12:27Here's an answer for C++, you can probably convert it easily to python/numpy. The idea is to use a border region before performing CLAHE and crop the image afterwards.
These are the subimage regions in the original image:
and they will be copied the the left/right of the image like this:
Maybe you can reduce the size of the border strongly:
QUESTION
I recently learnt about Perl capture groups. I would like to find a specific line of text in a C++ source code and replace a numerical value within this line.
The line I'm looking for is the following:
...ANSWER
Answered 2021-Apr-30 at 09:43Try
QUESTION
I have a movieDetails.json database and the collection name is a movie then our teacher wants us to Display the number of movies based on the number of directors a movie has a. Hint you might have to use the javascript function split Since the director is not an array, it is only a string so I can't count how many directors are there because it will always come out as 1 since its a string so I want to split that string so that I can get an array so that I can count it. But unfortunately, I don't know the query that will solve this problem. ex. of expected output:
...ANSWER
Answered 2021-Apr-28 at 11:45Demo - https://mongoplayground.net/p/y3kvFnocWKn
Use aggregation query
Read the below links for better understanding
QUESTION
This question: How to parse JSON in Java Has several answers which require including 3rd party libraries, including GSON, org.json and Jackson.
I am using Adobe AEM, which is notoriously intolerant of including 3rd party libraries, so am trying to do the REST API calling with standard Java 11. java 11 has the HTTPClient classes, which will give me JSON from the response.
Now I need to convert Json into the required java object.
E.g. I have a Person class with name and age fields, and want to get a Person object from something like {"name":"bob", "age":12}
I will also need something to convert a Java object into Json.
Any suggestions?
There is something called JsonObject in java 7, but I have not been able to find any examples which show this conversion.
...ANSWER
Answered 2021-Apr-05 at 21:03You can use JsonB which was introduced in JavaEE 8
QUESTION
I am writing a raycaster using SDL's C API. I have spent weeks trying to fix the notorious fisheye effect to no avail. According to this source, I can multiply my calculated distance by the cosine of half of the FOV to fix it. That has not worked for me. I still have the cosine correction in my code nonetheless.
Here are two images demonstrating the distortion:
I think a core problem of my code may be that my angle increment is constant, while the increment should be smaller as I'm closer to the screen borders. Unfortunately, I don't know how to start implementing this.
If possible, could anyone please take a look at my code and give me a tip on how to remove the fisheye? To move in any direction, use the arrow keys. Use the 'a' and 's' keys to turn left and right respectively.
This is how I'm compiling: clang `pkg-config --cflags --libs sdl2` raycaster.c
ANSWER
Answered 2021-Mar-11 at 22:09Okay I found a guide which talks about this exact issue.
Before drawing the wall, there is one problem that must be taken care of. This problem is known as the "fishbowl effect." Fishbowl effect happens because ray-casting implementation mixes polar coordinate and Cartesian coordinate together. Therefore, using the above formula on wall slices that are not directly in front of the viewer will gives a longer distance. This is not what we want because it will cause a viewing distortion such as illustrated below.
Thus to remove the viewing distortion, the resulting distance obtained from equations in Figure 17 must be multiplied by cos(BETA); where BETA is the angle of the ray that is being cast relative to the viewing angle. On the figure above, the viewing angle (ALPHA) is 90 degrees because the player is facing straight upward. Because we have 60 degrees field of view, BETA is 30 degrees for the leftmost ray and it is -30 degrees for the rightmost ray.
QUESTION
ifstream::readsome
is notoriously bad for reading chunks of a file due to implementation-defined issues. In my case, MSVC returns 0 on a freshly opened file.
I looked at their implementation and realized they're just calling ifstream::read
under the hood:
MSVC Implementation
...ANSWER
Answered 2021-Mar-14 at 05:21I don't use get
very often so I forgot it existed. Using this answer as a guide I came up with a solution:
(I double-checked, the other answer that uses FormattedInput
as (ifs >> std::noskipws >> ch)
gives the same results even though the get
spec says it treats it as UnformattedInput
)
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install notorious
Set up your own backend for usage across multiple devices, including synchronisation and replication.
Local data directory only: Use Notorious without a backend and store all data locally (not recommended, see Backing Up Data Directory).
Ensure your NodeJS installation includes all build tools installed by the installer (python;visualstudio2017-workload-vctools). If not, it's easiest to uninstall and install the latest version of node. This is because the template on which this repository is based depends on node-gyp which requires Visual studio build tools installed.|. If you are having problems please check: https://github.com/electron-react-boilerplate/electron-react-boilerplate/issues/400. Once that is out of the way and the yarn command completes successfully, you can start the app for development using yarn dev. This starts the renderer process in hot-module-replacement mode and starts a webpack dev server that sends hot updates to the renderer process.
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