ring | Unofficial packages for Ring Doorbells

As astutely pointed out by @fmw42, you can use cv2.warpPolar. Here's an example.

I made a small sandbox to demonstrate how you could implement your use case using react-hook-form.

The reason it isn't working is, that you never update react-hook-form's internal state when toggling the switch, you only update your useState. So when you call handleUpdateUser the data that is passed as the argument is the initial data you set via defaultValues.

Actually there is no need to use useState here, as you could just use react-hook-form's internal form state. For this to work you have to use the component react-hook-form provides as the component from Headless UI @headlessui/react is an external controlled component which doesn't expose a ref prop for an actual element ( uses a instead of an element). You can find more info here.

This way to you can also make your more generic for a reuse by providing a value and onChange prop instead of status and setStatus. But of course you could also use these names still. The will provide a value and onChange prop on the field object which i spread on the component.

In your example it isn't clear how your component will receive the initial userData. I assumed you'd make an api request and so i put it in a useEffect. To update the form state after the api call finished you have to use the reset method react-hook-form provides. If you only render when the userData is already loaded you can omit this step and just pass the result to the defaultValues to useForm.

I mocked the api calls with a simple Promise, but you should get the idea.

Component.js

I used what you did and android 12 emulator also worked.I used this for versions less than android 12 I hope it works.

While I do not have previous experience with this particular (from appearances, rather sophisticated) package Oscar.jl, parsing this error message tells me that the function you are trying to call is being given a BigFloat as input, but simply does not have a method for that type.

At first this was a bit surprising given that there are no BigFloats in your input, but after a bit of investigation, it appears that the culprit is the following

Previous answers may help as background:
c++, std::atomic, what is std::memory_order and how to use them?
https://bartoszmilewski.com/2008/12/01/c-atomics-and-memory-ordering/

Firstly the system you describe is known as a Single Producer - Single Consumer queue. You can always look at the boost version of this container to compare. I often will examine boost code, even when I work in situations where boost is not allowed. This is because examining and understanding a stable solution will give you insights into problems you may encounter (why did they do it that way? Oh, I see it - etc). Given your design, and having written many similar containers I will say that your design has to be careful about distinguishing empty from full. If you use a classic {begin,end} pair, you hit the problem that due to wrapping

{begin, begin+size} == {begin, begin} == empty

Okay, so back synchronisation issue.

Given that the order only effects reording, the use of release in Publish seems a textbook use of the flag. Nothing will read the value until the size of the container is incremented, so you don't care if the orders of writes of the value itself happen in a random order, you only care that the value must be fully written before the count is increased. So I would concur, you are correctly using the flag in the Publish function.
I did question whether the "release" was required in the Consume, but if you are moving out of the queue, and those moves are side-effecting, it may be required. I would say that if you are after raw speed, then it may be worth making a second version, that is specialised for trivial objects, that uses relaxed order for incrementing the head.

You might also consider inplace new/delete as you push/pop. Whilst most moves will leave an object in an empty state, the standard only requires that it is left in a valid state after a move. explicitly deleting the object after the move may save you from obscure bugs later.

You could argue that the two atomic loads in consume could be memory_order_consume. This relaxes the constraints to say "I don't care what order they are loaded, as long as they are both loaded by the time they are used". Although I doubt in practice it produces any gain. I am also nervous about this suggestion because when I look at the boost version it is remarkably close to what you have. https://www.boost.org/doc/libs/1_66_0/boost/lockfree/spsc_queue.hpp

Both the top and left calculations need adjusting so there isn't so much movement:

I've tried to get a handle on this problem using just the DE-9IM that Boost Geometry implements: https://godbolt.org/z/KWzvzExr7 which outputs https://pastebin.ubuntu.com/p/9ck6gcPK5P/

Without more details on how exactly you configured the Gradle plugin, it’s hard to say what’s wrong exactly. I believe the issue is most likely a bad keyring file or a bad in-memory secret key. The PGPSecretKeyRing constructor doesn’t find the expected secret key tag but instead finds 0xffffffff in your case.

With that in mind, let me try to answer your three questions:

1. I see two likely possibilities:
   • The plugin simply uses PGPSecretKeyRing under the hood no matter if you use a keyring file or just a single secret key, or
   • You have configured the plugin wrongly.
2. The “secret key tag” is one of the packet tags that are part of the OpenPGP format. The tag is not found in your case which is why I believe that something is wrongly configured (e.g., by passing in the secret key in a bad format).
3. Again, 0xffffffff is not the expected tag but the one that’s actually found in your case. The expected tag is the “Secret-Key Packet” which would be 0x5.

Some more pointers that might actually help you get the issue fixed:

• Another SO answer of mine helping someone who also faced the “Could not read PGP secret key” error.
• A Gradle issue where people have faced the same PGPSecretKeyRing error and at least one person found a solution.