einmal | The two-factor authentication | Identity Management library
kandi X-RAY | einmal Summary
kandi X-RAY | einmal Summary
The minimalistic, secure and open-source two-factor authentication app.
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QUESTION
I try to update a row, but nothing happens, I don't know what I have missed. Could some please check what I have done wrong ?
This is my helper class.
...ANSWER
Answered 2021-Jan-10 at 08:25I assume you miss update arguments in rawUpdate query.
QUESTION
I have a dataset that contains a variable called "sentence", which contains sentences. Here is a reproducible small version of it
...ANSWER
Answered 2020-Sep-16 at 22:45Base R solution:
QUESTION
I have to write a programm with a menu. Yhe user can type a number between 0 and 5. 0 ends the programm. 1 lists all env variables, 2 prints one entry, 3 adds an entry, 4 modify entry, 5 remove entry.
When I list all variables the programm crashes with: "Process finished with exit code 139 (interrupted by signal 11: SIGSEGV)"
When I want to print an environment variable, getenv()
wont find anything, although they exist.
Here is my code. If theres anything else you need to help me, please let me know.
...ANSWER
Answered 2020-May-21 at 01:07The problem in your PrintList
routine is the line which reads
QUESTION
I got many strings from our device (array). There are two different kinds of strings :
- 011_c_srr_Rtzfi_at000_hh5_fs_v343_l067_i1_Test_Test
- 041_c_ddr_Rtzfi_ds000_hh5_fs_v343_l037_i1_Test_hall (the needed information is in the middle of the string)
- 061_t_err_Rsas_au000_ti3_fs_v777_l011_ *
- 021_t_err_Rsas_au230_ti3_fs_v777_l031_ (the needed information is at the end of the string)
Conclusion: I need the following part of the string l067 / l037 / l011 ..... For example l067 means 67% and I037 means 37%. So i need this two percent values. The result is 67 and 37. My Code: (only parts)
...ANSWER
Answered 2020-May-13 at 10:55Given:
QUESTION
i worked with the pokerhand dataset from uci machine learning repository, i applied a neural network and everything went fine. Just with the presentation of the confusion matrix, there is a problem. So here is my code (please ignore my comments, i am german..):
...ANSWER
Answered 2020-May-01 at 14:54It should be because of these lines:
QUESTION
ANSWER
Answered 2020-Apr-22 at 09:13In python \b
inside a String is resolved to a backspace character. Therefore you see the white BS in the picture, becuase the console tries to represent this special character (BS for backspace).
What you need to do is to escape the \ inside your String like so
QUESTION
I´m still new to Node.js and currently developing a small app for my kitchen. This app can scan receipts and uses OCR to extract the data. For OCR extracting I´m using the ocr-space web api. Afterwards I need to parse the raw text to a JSON structure and send it to my database. I´ve also tested this receipt using AWS textract, which gave me a even poorer result. Currently I´m struggling at the parsing part using RegEx in Node.js.
Here is my JSON structure which I use to parse the receipt data:
...ANSWER
Answered 2020-Apr-20 at 03:05Pattern matching solutions like RegExp don't sound suitable for this sort of a categorization problem. You might want to consider clustering (k-means, etc.) - training a model to differentiate between ingredients and instructions. This can be done by labeling a number of recipes (the more the better), or using unsupervised ML by clustering line by line.
If you need to stick to RegExp for some reason, you keeping track of repeated words. Weak methodology: ingredient names (Chiasemen, Quinoa, ) will be referenced in the instructions, so you can match on multiline to find where the same word is repeated later on:
(?<=\b| )([^ ]+)(?= |$).+(\1)
If you do run this on a loop, plus logic, you can find pairs ingredient-instruction pairs, and work through the document with silhouette information.
You might be able to take advantage of ingredient lines containing numeric data like numbers or words like "piece(s), sticks, leaves" which you might store in a dictionary. That can enrich the word boundary input matches.
I would reconsider using RegExp here at all...
QUESTION
We are validating our XSD through https://www.freeformatter.com/xml-validator-xsd.html but it throws an error:
S4s-elt-must-match.1: The Content Of 'filmliste' Must Match (annotation?, (simpleType | ComplexType)?, (unique | Key | Keyref)*)). A Problem Was Found Starting At: Sequence.
Can someone help us?
Below is our XML and XSD Code (We changed the schemaLocation in the XML to XXXX just for the code preview):
...ANSWER
Answered 2020-Mar-26 at 16:18The error means what it says:
QUESTION
I hope the question is clear. I want the sum of the "speech share" from guest and host seperatly and for each episode.
Here is an example of my xml file:
...ANSWER
Answered 2020-Feb-03 at 12:57I want the sum of the "speech share"
There is no "speech share" in the XML you show. I am assuming you meant the total time of each contributor's segments. This is not trivial to do in XSLT 1.0.
First, you need to compute the individual pt:segment
durations. For this, you need to convert the start
and end
times to seconds (or some other common unit) so that you can subtract them. And you need to convert the results to a node-set
so that they can be summed.
Try something like the following:
XSLT 1.0 (+ EXSLT)
QUESTION
I have a list of words and my input is one of the words in the first half of the list (in this case, this list is a german song). Now I take the lenght of this word and jump this the length of this word in list, f.e. first word in the list is "Es" and the length is 2. Now we count from "Es" 2 times and we land by word "zwei". I should go through this list and check if the word appears again in the second half of the list.
The program works, but the problem is about the input. It takes one word and sees if the theorie works. This is the song list: "hin" is the last word of the first half
...ANSWER
Answered 2019-Nov-10 at 09:17Here's a version of the function that processes each word in the first part of the list. The question states that the program works, so the main logic has not been changed.
These are the changes that have been made:
- remove the
input
statement - add a
for
loop over the first part of the list - print the word being processed (for debugging and readability, may be removed)
- remove redundant
originalWordSaved
andoriginalIndex
variables - move filtering logic (the word is in the second half of the list, or appears less than twice) out of the
while
loop as it only need to run once per word - move code than cannot cause an
IndexError
out of the try/except block - specifically trap
IndexError
, because that's the only error that the code can raise: bareexcept
statements should be avoided - print the list rather than returning it
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