coward | Coward is a Deno module | REST library

by itjk TypeScript Version: v0.3.2 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | coward Summary

coward is a TypeScript library typically used in Web Services, REST, Discord applications. coward has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Coward is a Deno module for easy interaction with the Discord API.

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Quality

Security

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Support

coward has a low active ecosystem.

It has 63 star(s) with 7 fork(s). There are 8 watchers for this library.

It had no major release in the last 12 months.

There are 2 open issues and 10 have been closed. On average issues are closed in 9 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of coward is v0.3.2

Quality

coward has no bugs reported.

Security

coward has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

coward is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

coward releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

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coward Key Features

No Key Features are available at this moment for coward.

coward Examples and Code Snippets

No Code Snippets are available at this moment for coward.

Community Discussions

Trending Discussions on coward

Is it possible to repeat a loop after trying a limited amount of times?

Mongodb query to Display the number of movies based on the number of directors a movie has using split

Google Sheets: How to grab unique names and numbers from one sheet and adding it to another sheet based on a specific value

ValueError shape mismatch objects cannot be broadcast to a single shape

Discord bot on .NET, reacting on specific words

mdt shell does not connect or push ssh key

Cannot convert a list of "strings" to a tf.Dataset.from_tensor_slicer() - ValueError: Can't convert non-rectangular Python sequence to Tensor

Dynamically update dictionary values in functions from other dictionaries

How do I randomly generate an item in an array without getting the same item twice in a row?

How can I tar gz files with file name date range?

QUESTION

Is it possible to repeat a loop after trying a limited amount of times?

Asked 2021-May-03 at 16:47

So, I'm new to programming and I'm struggling a lot to define a "try again" after a set amount of times on my little guessing game. This is the code that I'm using:

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ANSWER

Answered 2021-May-02 at 20:19

There are a couple of things I'd like to point out. They won't fix anything though.

Instead of subtracting 3 of t, set t=0 instead. t-=3 might cause t to go to negatives (unless this was on purpose)
The while loop will stop as soon as t exceeds max_tries. This means that it might not "retry" every time. while True: or while bool will fix it. (bool can be a variable of boolean type).
You don't specify num after you guess correctly and play again. Just put num = random.randint(1,10) right before continue.

Now, back to your original question:

Your else statement will never be reached. This is because all the conditions (num < answer, num > answer, and num == answer) are all specified. There is no other possible operation between num and answer that you can do, hence else will never be reached.

To fix this, you can use an if statement before the first current if.

Source https://stackoverflow.com/questions/67360489

QUESTION

Mongodb query to Display the number of movies based on the number of directors a movie has using split

Asked 2021-Apr-28 at 11:45

I have a movieDetails.json database and the collection name is a movie then our teacher wants us to Display the number of movies based on the number of directors a movie has a. Hint you might have to use the javascript function split Since the director is not an array, it is only a string so I can't count how many directors are there because it will always come out as 1 since its a string so I want to split that string so that I can get an array so that I can count it. But unfortunately, I don't know the query that will solve this problem. ex. of expected output:

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ANSWER

Answered 2021-Apr-28 at 11:45

Demo - https://mongoplayground.net/p/y3kvFnocWKn

Use aggregation query

Read the below links for better understanding

Source https://stackoverflow.com/questions/67298166

QUESTION

Google Sheets: How to grab unique names and numbers from one sheet and adding it to another sheet based on a specific value

Asked 2021-Apr-21 at 18:47

I just started working at a new company and I thought that I'd make a spreadsheet for my personal use. My boss came across me working on that spreadsheet and loved it so far. They've been manually entering values into their own spreadsheets since they've started and I thought it was super tedious, so I've been working on my own for the last week trying to improve efficiency on my end. Now my bosses want me to do this for the other branches... so the pressure is real for me. I've completed every other feature they've requested, but I'm struggling with this last one so I'm here now requesting help.

I have two sheets. One called "Inspection Results" and "Still Hasn't Passed Inspection."

"Inspection Results" looks something like this:

Timestamp Date Name MS Number Address Jurisdiction Inspection Result 4/21/2021 4/21/2021 John Smith MS12345 123 Test St Orange Passed 4/20/2021 4/20/2021 John Smith MS12345 123 Test St Orange Failed 4/21/2021 4/21/2021 Rick Grimes MS12356 123 Meme St Riverside Passed 4/19/2021 4/19/2021 Michelle Obama MS54321 123 Demo St Long Beach Failed 4/18/2021 4/18/2021 Michelle Obama MS54321 123 Demo St Long Beach Failed 4/18/2021 4/18/2021 Courage Dog MS98765 123 Coward St Orange Cancelled

"Still Hasn't Passed Inspection" currently looks like this:

Name MS Number

I want to search every row in "Inspection Results" and find the Names(Column C) of the people that do not have a inspection result(Column G) of "Passed" and write a new row in "Still Hasn't Passed Inspection" with the Name(Column C) and MS Number(Column D) of those people that could not be found with a "Passed" inspection result.

I want the table in "Still Hasn't Passed Inspection" to have unique rows. For example, there are some rows in "Inspection Results" that I have the same Name and Inspection Result. In the table that I posted, Michelle Obama failed inspection. I only want Michelle Obama to appear one time in the "Still Hasn't Passed Inspection" sheet. John Smith failed inspection one day, but passed on the following day so he wouldn't be included in the table.

Basically, based on the example table I posted above, I want "Still Hasn't Passed Inspection" to look like this:

Name MS Number Michelle Obama MS54321 Courage Dog MS98765

I'm trying to automate this process so I, or whoever, doesn't have to keep manually entering and deleting rows every time someone finally passes inspection. If someone submits a "Passed" entry into "Inspection Results" for someone that previously "Failed" or "Cancelled", I want "Still Hasn't Passed Inspection" to be updated.

Is there a way I can accomplish this with certain formulas or am I going to have to create a script on this and, if so, does anyone have a reference they can point me towards? I'm not an experienced coder. I'm not familiar with Javascript and its syntax, but I do know how variables, if statements, and for loops work. I'm not asking anyone to write me a bunch of code on this. This isn't your responsibility. If you want to, of course, it would always be appreciated. Any hints or reference towards resolving this would be amazing.

Thank you.

...

ANSWER

Answered 2021-Apr-21 at 18:47

I am a big fan of the query (QUERY(data, query, [headers])) function. Using it, you could do something like this on "Still Hasn't Passed Inspection"

Source https://stackoverflow.com/questions/67199089

QUESTION

ValueError shape mismatch objects cannot be broadcast to a single shape

Asked 2021-Feb-19 at 10:04

I try to plot a third stacked bar in matplotlib following this post on stackoverflow : A third stacked bar in matplotlib

But I have an Value error as mentionned in title and I don't understand why as I followed the exact same process as in the post...

Here is the code :

...

ANSWER

Answered 2021-Feb-19 at 10:02

This is because count_recruit+count_coward creates a large list instead of adding them up like in the example you linked. In the example they used numpy arrays which are added up by the + sign.

You could first add the lists up elementwise, and then use them:

Source https://stackoverflow.com/questions/66275112

QUESTION

Discord bot on .NET, reacting on specific words

Asked 2021-Jan-05 at 16:03

The thing is that I wanted to create a bot that would react on a specific words sending by people in discord channel chat.

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ANSWER

Answered 2021-Jan-05 at 09:55

When you use contains it just sees that mooooooo does contain moo mooo and moooo because it is part of the string. That means that for every time your foreache runs and there is a match (wich is a few times) it will run the send message.

are you trying to see if there is a moo or are you trying to tell them apart?

if you are trying to see if there is a moo you should have the code be

Source https://stackoverflow.com/questions/65576426

QUESTION

mdt shell does not connect or push ssh key

Asked 2020-Aug-13 at 15:40

I cannot connect to my coral devboard via mdt shell over OTG USB-C port after following along here. Initially, I had the mendel 'public device cowardly refusal' issue as outlined in an q&answer here. I used serial console and nmtui to get the devboard on my LAN and I fixed that checking code on my host to match my LAN arrangement (172 instead of 192 block) and that worked to start connection via mdt shell.

Now, when connecting I get the below error about only allowing a single ssh key. I have ONLY connected via screen in serial console since I initially flashed the board. No one has ever ssh'd.

...

ANSWER

Answered 2020-Aug-13 at 15:40

can you try using ssh instead of mdt (mdt is just wrapper around ssh)? I believe this is a Catalina problem, Linux and older versions of Mac also works fine, I believe it has to do with their libusb changes. This issue has been reported earlier, here is a quick guide on using ssh:

Create a id_rsa key on your mac with:

Source https://stackoverflow.com/questions/63396084

QUESTION

Cannot convert a list of "strings" to a tf.Dataset.from_tensor_slicer() - ValueError: Can't convert non-rectangular Python sequence to Tensor

Asked 2020-Jul-21 at 14:00

I have the following data:

...

ANSWER

Answered 2020-Jul-21 at 12:53

You will need to turn these strings into vectors, and pad them to equal length. I'll show you an example with just partial_x_train_actors_array:

Source https://stackoverflow.com/questions/63014556

QUESTION

Dynamically update dictionary values in functions from other dictionaries

Asked 2020-May-25 at 20:58

Noob here trying to wrap my head around this idea I had. I know it's not pythonic or anything. Just trying to get a basic system working here but this is the closest to a functioning version of what I'm trying to do. Tried a bunch of things and can't seem to get the options to update properly. Really hope some feedback can point me in the right direction. Iv included the entire code, the part with the commented section in the challenge() function by battleChoice is my main issue. I can't get the options dictionary values to change to call different functions based on the current page.

...

ANSWER

Answered 2020-May-25 at 20:33

This happens because you've declared options in a global scope and re-declaring it in a local scope inside the challenge() function. So when you update options locally, the global variable is not changed at all.

You have at least these two options:

State to challenge() that options is a reference to a global value and do the update:

Source https://stackoverflow.com/questions/62009951

QUESTION

How do I randomly generate an item in an array without getting the same item twice in a row?

Asked 2020-May-01 at 05:22

Hello I have a random quote generator. My question is How do I randomly generate an item in an array without getting the same item twice in a row?

below I will post my project I want to keep it a as simple project as possible thank you for any help.

heres is all of my css coding:

...

ANSWER

Answered 2020-May-01 at 05:22

Here is an idea:

Deep copy quotes
Pick a random entry from the deep copy and display it
Remove this entry from the deep copy (to prevent picking the same before picking all the others)
If the deep copy is empty, recopy it

Source https://stackoverflow.com/questions/61537041

QUESTION

How can I tar gz files with file name date range?

Asked 2020-Feb-25 at 05:19

I want to make a tar.gz file which compresses multiple files, selected by exact date range which composes the name of the files. for example, file names are

...

ANSWER

Answered 2020-Feb-25 at 05:19

If you want to select the log file to be compressed based on the filenames, you will need to compare the filenames one by one. Would you please try the following:

Source https://stackoverflow.com/questions/60386082

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install coward

You can download it from GitHub.

Support

Any contributions to Coward are accepted and encouraged. This can range from submitting bug reports, requesting features, improving documentation, or writing code. Please refer to CONTRIBUTING.

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