kQ | central location where you can find important data | Pub Sub library
kandi X-RAY | kQ Summary
kandi X-RAY | kQ Summary
kafkaQ is a central location where you can find important data about your Kafka application's performance. Our dashboard provides critical insight about your system's activity, allowing rapid diagnosis of vulnerabilities. Informed by our statistics, you can determine the optimal approach to scale your Kafka architecture, whether it means adding more brokers or reconfiguring your zookeeper.
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QUESTION
My goal
I am making a UI that has an image at the top, and four buttons below it, arranged vertically. The height of the image depends on its width, but it shouldn't be too tall that there isn't enough space for the buttons. After the image is positioned, the buttons can fill up the rest of the space. Horizontally, The image should try to take up as much of the width of the screen as possible, but the buttons should have a constant width of 300 and be centered horizontally. I understand that this is a bad idea for localisation, but I don't plan on localising this app.
A picture is worth 1000 words:
I have only used the stack overflow logo to replace the actual image that I will be using. I am not making a Stack Overflow-related app.
Also, the image view should be on the left of the buttons when the vertical size class is compact (the buttons are still vertically arranged).
I think I basically wanted a stack view whose subviews are aligned differently - the image view is aligned with "Fill", and the buttons are aligned with "Center". However, I don't know how to do that, so I tried to use nested stack views to work around this.
How to reproduce:
The outer stack view top/bottom/leading/trailing all are pinned to the VC's view, alignment set to "Fill", distribution set to "Fill Proportionally". I chose "Fill Proportionally" because I found that works the best if I use a large enough image. I added a variation on the outer stack view's axis, so that it is set to horizontal when vertical size class is compact.
The outer stack view has 2 arranged subviews - the image view and the inner stack view, whose distribution is set to "Fill", alignment is set to "Center".
The inner stack view then has those buttons. Each button has a constant width constraint.
I thought that should do the job. When I run the app, I see some "unable to satisfy constraints" warnings:
...ANSWER
Answered 2021-Apr-18 at 15:29OK - based on the image you posted, I'm going to use a 2:1
aspect ratio for your "Logo Image"...
Start with a "basic" layout:
Here's the constraints:
the Outer StackView
properties:
and the Buttons StackView
properties:
At this point, we should be "good to go" with "portrait" layout.
Let's add some trait variations...
To get this layout:
We'll add `Width: Any / Height: Compact" for the Axis and Alignment of the OuterStack:
and we'll add `Width: Any / Height: Compact" for the Alignment of the ButtonsStack:
If we run that (iPhone 12 sim), we get this:
We're close, but... we get a whole mess of auto-layout warning / error messages in the debug console.
That's because (from my experience) auto-layout needs to make multiple "passes" to fully evaluate the layout, particularly when using Aspect-Ratio constraints mixed with Stack Views.
To get rid of that, we'll give the Image View's Aspect-Ratio constraint a less-than-required Priority
:
This, effectively, allows auto-layout to break constraints during its multiple layout passes.
Here's an entire Storyboard source so you can more closely inspect things:
QUESTION
I have a list of paired strings. I want to find the length/interval between two alphabets. So far I'm able to find the interval for ordered alphabets using
...ANSWER
Answered 2021-Apr-15 at 17:28Instead of generating a list between ord(i[0])
and ord(i[1])
, and finding its length, there's a better solution, just finding the difference between ord(i[0])
and ord(i[1])
.
This doesn't immediately solve the issue for reversed alphabets, since a reversed alphabet would generate a negative number, but you can solve this with the builtin abs()
function which takes the absolute value of a number:
QUESTION
Requirement is to find a string from txt file and store it to variable.
file look like this(rsa.txt)
...ANSWER
Answered 2021-Apr-06 at 09:19You need to escape $
as \$
as it means "end of string" with -E
QUESTION
I have some code to display my board as shown below:
...ANSWER
Answered 2021-Mar-14 at 17:18You need to return cleanup function from effect, so when fast refresh will rerun it, there will be no duplicates. It works properly sometimes because sometimes fast refresh sometimes don't try to preserve state and renders everything as new. This depends on changes you made, so when you change one file it will render clean, but on another files it will try to preserve state and only rerun effects (this is where second board added).
Also, it is better not to interact with DOM directly and use ref instead. This is better way to work with DOM in react, since it's react main purpose to update DOM.
QUESTION
Here i have got a button named generate cat which generates images but i want the images to have padding.
...JS
ANSWER
Answered 2020-Dec-19 at 17:27You can use the DOM to change CSS styles. All you have to do is add image.style.padding = "enter padding in px";
. Put this code before you append the image. You can use the DOM to change the css styles of any property. Just add element.style.csspropertyhere = "value";
QUESTION
I have a sample like this
...ANSWER
Answered 2020-Dec-18 at 21:04We can use pivot_longer
to reshape the columns from 'IK1' to 'Zoo8', then reshape again the 'K1Q' to 'K3Q' as separate
QUESTION
I'm struggling with the size of a LaunchScreen storyboard image.
Basically, it is very small on iPhone 4s, while being OK on larger screens.
Here is the storyboard file content:
...ANSWER
Answered 2020-Nov-25 at 17:08Put the image in imageView with constrains trailing and leading = 0 to the safe area, Top & Bottom = 0 to the superView, make Content mode = Scale to fill and I think It will work fine
QUESTION
Most implementations of the ArrayList use an array internally and when the size is already exhausted upon adding an element to the list, it resizes or "grows" by essentially doing the following:
- caching a new array with a new batch of freshly allocated memory.
- copying all the elements of the internal array into the new array.
- setting the internal array to the new array.
- setting index
N - 1
of the internal array to the element object, whereN
is the new size of the array.
The explanation provided is that growing the list is a rare necessity for your average add operation so the time complexity of the average add is O(1)
, hence amortized constant time.
I am confused as to how this makes sense. Say the list grows by Q
. Simple arithmetic series will show you that if I were to add x
elements to an ArrayList, the total number of element copies done internally is x^2 + Qx / 2Q
, if x
were several times larger than Q
.
Sure, for the first few values that are added the time may very well be constant, but for a large enough number of elements added we're seeing the average time complexity for each add operation to be linear or O(n)
. Hence, adding a large number of elements to the list takes exponential time. I don't understand how even the amortized time complexity of a single add operation is constant. Is there something I'm missing?
EDIT: I did not realize that the list growth is in fact geometric and this optimizes the amortized time complexity.
Conclusion:
Linear Growth of Dynamic List
Let N = kQ
For N + 1
insertions
Copies:
...ANSWER
Answered 2020-Nov-09 at 22:39Without loss of generality, suppose the initial capacity of the list is 1. We further assume that the capacity is doubled each time the capacity is exceeded by an insertion. Now consider inserting 2^k + 1
elements (which is the general worst case, since the last operation triggers the dynamic growing).
There are k
insertions that trigger dynamic growing, and their accumulative cost is
QUESTION
Note: This is for homework so please don't post full code responses, just help on what I'm misusing would be appreciated
I'm trying to plot a piecewise defined function where when 0 < x <= 10 it will be a constant (KQ/10) and for x > 10 it will be KQ/x for 10 < x < 50. Currently my result comes back as a single value instead of my expected result of an array with a constant value up until x > 10 and then varying values until x = 50
My current code
...ANSWER
Answered 2020-Sep-20 at 04:53x = np.linspace(0, 50, 1)
isnt how linspace works... this only creates one data point ...
x = np.linspace(0, 50, 10000)
... would create 10k datapoints
perhaps you wanted np.arange(0,50,1)
?
QUESTION
If I use !DOCTYPE html , unwanted borders appear at the lower corners of the header. I used images in order to get these corners. Same issue for Internet explorer and Chrome. How can I remove these borders ? If I use !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN there is not any problem.
The codes are:
...ANSWER
Answered 2020-Aug-15 at 17:11I fix it by using: display: block; Example: Details on stackoverflow.com : Fit image to table cell [Pure HTML]
Using bgcolor with !DOCTYPE html created also this unwanted borders.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install kQ
In your project's root directory, run npm install kafkaq-monitor
In the producer script of your Kafka application, import our trackProducer method and invoke it immediately after the code connecting your producer, passing in your producer as an argument. Here's an example:
We will now connect kafkaQ to your consumer. This will be very similar to the previous step. Import our trackConsumer method and invoke it after your consumer subscribes to a topic, passing your consumer as the argument. Here's an example:
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